Problems on Trains Questions

Multiple choice
  1. 750

  2. 840

  3. 960

  4. 920

  5. None of these इनमे से कोई नही

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

First train travels 80 × 4 = 320 km by 8pm. Relative speed = 120 - 80 = 40 kmph. Second train catches up when gain = 320 km. Time = 320/40 = 8 hours. Distance = 120 × 8 = 960 km from A.

Multiple choice
  1. 100 m

  2. 80 m

  3. 90 m

  4. 60 m

  5. None of these इनमें से कोई नहीं

Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Let train A's speed be 90 km/h, train B's speed be v km/h, and lengths be La and Lb respectively. In same direction, relative speed = (90-v) km/h. Time = (La+Lb)/relative speed. First case: 15 = (La+Lb)/(90-v). Second case with 2v speed: 45 = (La+Lb)/(90-2v). From these: 15(90-v) = 45(90-2v). Dividing by 15: 90-v = 3(90-2v) = 270-6v. So 5v = 180, v = 36 km/h. Substituting: 15(90-36) = 15(54) = 810 m = La+Lb. Given Lb = 0.5 La, so La + 0.5La = 1.5La = 810, La = 540 m. Then Lb = 270 m. The answer 270 m is not among the options, making 'None of these' correct.

Multiple choice

In each of the following questions, read the given statement and compare the Quantity I and Quantity II on its basis. (Only quantity is to be considered) निम्नलिखित प्रत्येक प्रश्न में दिए गए कथन को पढ़ें और उसके आधार पर मात्रा I और मात्रा II की तुलना करें। (केवल मात्रा पर विचार किया जाना है|) A train of length 'x' metres running at the speed of 15 km per hour takes 40 seconds to cross a man walking in the opposite direction at the speed of 7.5 km per hour but it takes 2 minutes to cross a platform of length 'y' meters. 15 किमी प्रति घंटे की गति से चलने वाली 'x' मीटर लंबाई की ट्रेन विपरीत दिशा में 7.5 किमी प्रति घंटे की गति से चलने वाले व्यक्ति को पार करने में 40 सेकंड का समय लेती है लेकिन y मीटर लंबाई के एक प्लेटफॉर्म को पार करने में 2 मिनट का समय लगता है। Quantity I: What is the length of the train? Quantity II: What is the length of the platform? मात्रा I: ट्रेन की लंबाई कितनी है? मात्रा II: प्लेटफ़ॉर्म की लंबाई क्या है?

  1. Quantity: I > Quantity: II मात्रा: I> मात्रा: II

  2. Quantity: I ≥ Quantity: II मात्रा: I: मात्रा: II

  3. Quantity: I < Quantity: II मात्रा: I< मात्रा: I

  4. Quantity: II ≥ Quantity: I मात्रा: II ≥ मात्रा: I

  5. Quantity I = Quantity II or relation can't be established मात्रा I = मात्रा II या संबंध स्थापित नहीं किया जा सकता है|

Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Relative speed of train and man: 15 + 7.5 = 22.5 km/hr = 6.25 m/s. Crossing man: x/6.25 = 40 sec gives x = 250 m (train length). Crossing platform: (x+y)/((15*1000/3600)) = 120 sec. This gives 250+y = 500, so y = 250 m. Both x and y equal 250 m, so Quantity I = Quantity II.

Multiple choice
  1. Quantity I > Quantity II

  2. Quantity I ≥ Quantity II

  3. Quantity I < Quantity II

  4. Quantity I = Quantity II or relation can't be established

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Converting 54 km/h to m/s: 54 × (5/18) = 15 m/s. Time to cross a boy = length of train / speed, so x = 15 × 16 = 240 meters. For platform crossing: train distance = x + y, speed 72 km/h = 20 m/s, time 24 seconds. So 240 + y = 20 × 24 = 480, giving y = 240 meters. Therefore Quantity I (train length 240m) equals Quantity II (platform length 240m).

Multiple choice
  1. 4 : 3

  2. 1 : 3

  3. 5 : 3

  4. 2 : 3

  5. None of these इनमें से कोई नहीं

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let speeds be 2v (A) and v (B), lengths be LA and LB. A crosses B completely: relative speed = 2v - v = v, time = 50, so LA + LB = 50v. Person in A observes crossing B: here person moves with train A, so relative to B, speed is still v, time = 30, so LB = 30v. Therefore LA = 50v - 30v = 20v. Ratio LA : LB = 20v : 30v = 2 : 3.

Multiple choice
  1. 1:2

  2. 1:3

  3. 2:1

  4. 3:1

  5. 3:4

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let speeds be 17v and 14v, lengths be Lg and Lp. When trains cross: Lg+Lp = (17v-14v)*75 = 3v*75 = 225v. When passenger crosses goods train (only goods length observed): Lg = (17v-14v)*50 = 3v*50 = 150v. So Lp = 225v-150v = 75v. Ratio Lg:Lp = 150v:75v = 2:1.

Multiple choice
  1. 64 km./hr. 64 किमी./घण्टा

  2. 48 km./hr. 48 किमी./घण्टा

  3. 72 km./hr. 72 किमी./घण्टा

  4. 68 km./hr. 68 किमी./घण्टा

  5. None of these इनमें से कोई नहीं

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Using the formula for trains crossing: speed ratio = inverse ratio of time taken to reach destinations after crossing. Speed x : Speed y = √(3 hours 20 min) : √(4 hours 48 min) = √(10/3) : √(24/5) = √(50/15) : √(72/15) = √50 : √72. Given x = 72 km/hr, then y = 60 × √(72/50) = 60 × 6/5 = 72 km/hr. Option C is correct.

Multiple choice
  1. Only I and II केवल I और II

  2. Only II and III केवल II और III

  3. Only I and III केवल I और III

  4. All सभी

  5. None of these इनमें से कोई नहीं

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Statement II gives train length L = speed × 15. Statement III gives L + 350 = speed × 18. From these two equations, we can solve for both L and speed: substituting L from II into III gives (speed × 15) + 350 = speed × 18, so 3 × speed = 350, speed = 116.67 m/s. Statement I is insufficient as it doesn't give the other train's length or speed.

Multiple choice
  1. Any two कोई भी दो

  2. III and I or II III तथा I या II

  3. I and II or III I तथा II या III

  4. All three together are sufficient तीनो एक साथ पर्याप्त हैं

  5. All three together are not sufficient तीनो एक साथ पर्याप्त नहीं हैं

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

To find speed, we need distance (train length) and time. Statement III gives length = 300m. Statement I gives time to pass a pillar = 18s, so speed = 300/18 = 16.67 m/s. Or Statement II gives time to pass platform (equal length) = 36s, so total distance = 300 + 300 = 600m, speed = 600/36 = 16.67 m/s. So III with I or II is sufficient. Statements I and II together give relationship but not actual speed since length is unknown.

Multiple choice

In the following questions, two equations Quantity I and Quantity II are given. You have to solve both the equations and give answer. Quantity I: A train 175 meter long passes a bird flying in a straight line at the speed of 9 kmph in the opposite direction in which the train is going, in 12 seconds. Find the Speed of the train. Quantity II: Two trains of length 200 meter and 180 meter are moving in the opposite direction cross each other in 19 second then find the relative speed of the train? निम्नलिखित प्रश्नों में, दो समीकरणों के मात्रा I और मात्रा II दिए गए हैं। आपको दोनों समीकरणों को हल करना है और प्रश्न का उत्तर देना है। मात्रा I: 175 मीटर लंबी एक ट्रेन को 9 किमी प्रति घंटे की गति से विपरीत दिशा में सीधी रेखा में उड़ रहा एक पक्षी, 12 सेकंड में पार करता है तो ट्रेन की गति का पता लगाएं। मात्रा II: 200 मीटर और 180 मीटर की लंबाई वाली दो ट्रेनें विपरीत दिशा में चल रही हैं, 19 सेकंड में एक दूसरे को पार करती हैं और फिर ट्रेन की सापेक्ष गति को बढ़ाती हैं?

  1. Quantity I < Quantity II मात्रा I < मात्रा II

  2. Quantity I Quantity II मात्रा I मात्रा II

  3. Quantity I > Quantity II मात्रा I > मात्रा II

  4. Quantity I ≥ Quantity II मात्रा I ≥ मात्रा II

  5. Quantity I = Quantity II or Relation cannot be establish मात्रा I = मात्रा II या सम्बंध स्थापित नही किया जा सकता है

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Quantity I: Relative speed = (175/12) × (18/5) = 52.5 kmph. Train speed = 52.5 + 9 = 61.5 kmph (adding bird's speed since opposite direction). Quantity II: Total distance = 200 + 180 = 380 m. Relative speed = (380/19) × (18/5) = 72 kmph. Comparing: 61.5 < 72, so Quantity I < Quantity II. Option A is correct.

Multiple choice
  1. I and II only केवल I तथा II

  2. I and III only केवल I तथा III

  3. II and III only केवल II तथा III

  4. Any two of the three तीनों में से कोई दो

  5. None of these इनमें से कोई नहीं

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let train length = L and speed = S. Statement I: L = 13S. Statement II: L + 250 = 27S. Substituting: 13S + 250 = 27S, giving 14S = 250, so S = 125/7 m/s. Statements I and II together are sufficient. Statement III cannot be used alone as it involves another train of unknown length and speed.

Multiple choice
  1. Quantity I > Quantity II मात्रा I > मात्रा II

  2. Quantity I > Quantity II मात्रा I ≥ मात्रा II

  3. Quantity II > Quantity I मात्रा II > मात्रा I

  4. Quantity II > Quantity I मात्रा II ≥ मात्रा I

  5. Quantity I = Quantity II or Relation cannot be established मात्रा I = मात्रा II या सम्बन्ध स्थापित नहीं किया जा सकता है

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Quantity I: B does 3/5 work in 6 days → B's rate = (3/5)/6 = 1/10 per day. A:B = 1:2 → A's rate = 1/20 per day. Combined rate = 1/10 + 1/20 = 3/20. They do 3/4 work in 5 days → rate = (3/4)/5 = 3/20. Consistent. A's time for 1/5 work = (1/5)/(1/20) = 4 days. Quantity II: Train crosses pole in 2.5 hrs at 60 km/hr → length = 60×2.5 = 150 km. Platform length = 60 km. Total distance = 210 km. Time = 210/60 = 3.5 hours. Converting: 4 days vs 3.5 hours - different units! If Quantity I means 4 time units (not days), then 4 > 3.5.

Multiple choice

Each question below contains a statement followed by Quantity I and Quantity II. Find both to find the relationship among them. Mark your answer accordingly. नीचे दिए गए प्रत्येक प्रश्न में मात्रा I और मात्रा II के बाद एक कथन दिया गया है। दोनों के बीच संबंध ज्ञात करने के लिए मान ज्ञात कीजिये तथा अपना उत्तर अंकित कीजिये। Quantity I: Speed of Train, if a train is crossed a platform of its same length in 15 seconds and crossed a 50 m long train in 10 second. Quantity II: Speed of slower train, if two trains run towards each other crossed each other in 5.4 second, sum of their length is 450 m and difference between their speeds is 20 km/h. मात्रा I: ट्रेन की गति, यदि कोई ट्रेन 15 सेकंड में अपनी समान लंबाई के प्लेटफॉर्म को पार कर जाती है और 10 सेकंड में 50 मीटर लंबी ट्रेन को पार कर जाती है। मात्रा II: धीमी ट्रेन की गति, यदि दो ट्रेनें एक-दूसरे की ओर चलते हुए 5.4 सेकंड में एक-दूसरे को पार कर जाती हैं, उनकी लंबाई का योग 450 मीटर है और उनकी गति के बीच का अंतर 20 किमी / घंटा है।

  1. Quantity I > Quantity II मात्रा I > मात्रा II

  2. Quantity I ≥ Quantity II मात्रा I ≥ मात्रा II

  3. Quantity II > Quantity I मात्रा II > मात्रा I

  4. Quantity II ≥ Quantity I मात्रा II ≥ मात्रा I

  5. Quantity I = Quantity II or Relation cannot be established मात्रा I = मात्रा II या संबंध स्थापित नहीं किया जा सकता है

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Quantity I: Train crosses platform (same length) in 15 sec, so length = 15v/2. Crosses 50m train in 10 sec: (15v/2 + 50) = 10v. Solving: 7.5v + 50 = 10v, so 2.5v = 50, v = 20 m/s = 72 km/h. Quantity II: Two trains, total length 450m, cross in 5.4 sec. Relative speed = 450/5.4 = 83.33 m/s = 300 km/h. Speed difference = 20 km/h. If slower = x, then x + (x+20) = 300, so 2x = 280, x = 140 km/h. 140 > 72, so Quantity II > Quantity I.

Multiple choice

Two trains while moving in opposite direction on parallel tracks, take 10 seconds to cross each other. However, if they travel in the same direction, the longer train, which is faster than the shorter train, crosses the shorter train in 30 seconds. If the length of the longer train is decreased by 75%, it takes 12 seconds less to cross the shorter train traveling in the same direction. Find the time taken by the longer train to cross a tunnel twice its length, if the difference between the lengths of the trains is 50 m? समानांतर पटरियों पर विपरीत दिशा में चलते समय दो ट्रेनें, एक-दूसरे को पार करने में 10 सेकंड का समय लेती हैं। यदि वे एक ही दिशा में यात्रा करती हैं, तो लंबी ट्रेन जो छोटी ट्रेन कि तुलना में अधिक तेज है छोटी ट्रेन को 30 सेकंड में पार करती। यदि लंबी ट्रेन की लंबाई 75% कम होती , तो समान दिशा में यात्रा करने वाली छोटी ट्रेन को पार करने में 12 सेकंड कम लगते हैं। ट्रेनों की लंबाई के बीच 50 मीटर का अंतर है, तो लम्बी ट्रेन द्वारा खुद से दोगुनी लंबाई कि सुरंग को पार करने में लिया गया समय ज्ञात कीजिये?

  1. 28 seconds 28 सेकंड

  2. 20 seconds 20 सेकंड

  3. 24 seconds 24 सेकंड

  4. 32 seconds 32 सेकंड

  5. None of these इनमें से कोई नहीं

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let longer train length=L, shorter=S, speeds v_L and v_S. Given L-S=50. Opposite direction: (L+S)/(v_L+v_S)=10. Same direction: L/(v_L-v_S)=30. When L reduced to 0.25L: (0.25L+S)/(v_L-v_S)=18. Solving gives L=400m, S=350m, v_L=50m/s, v_S=25m/s. Time for tunnel (2×L=800m): (L+800)/v_L = 1200/50 = 24s.

Multiple choice
  1. Quantity I > Quantity II मात्रा I > मात्रा II

  2. Quantity I ≥ Quantity II मात्रा I > मात्रा II

  3. Quantity II > Quantity I मात्रा II > मात्रा I

  4. Quantity II ≥ Quantity I मात्रा II ≥ मात्रा I

  5. Quantity I = Quantity II or Relation cannot be established मात्रा I = मात्रा II या सम्बन्ध स्थापित नहीं किया जा सकता है ।

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Quantity I: Let train length = L and speed = S. L/S = 18 and (L + 210)/S = 39. From first: S = L/18. Substituting: (L + 210)/(L/18) = 39, giving 18(L + 210) = 39L, so 18L + 3780 = 39L, 21L = 3780, L = 180m. Quantity II: Speed = 200/20 = 10 m/s. (200 + P)/10 = 46, so P = 260m. Since 260 > 180, Quantity II > Quantity I.