Simple and Compound Interest Questions

Multiple choice
  1. Quantity I > Quantity II मात्रा I > मात्रा II

  2. Quantity I = Quantity II or relation can't be established मात्रा I = मात्रा II या संबंध स्थापित नहीं किया जा सकता है

  3. Quantity I < Quantity II मात्रा I < मात्रा II

  4. Quantity I ≤ Quantity II मात्रा । ≤ मात्रा II

  5. Quantity I ≥ Quantity II मात्रा । ≥ मात्रा II

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Quantity I: Amount = 55000(1 + 0.15)^3 = 55000 × 1.520875 ≈ 83648.13. Compound interest ≈ 28648. Quantity II: Simple Interest = 60000 × 0.25 × 5.5 = 82500. Since 83648 > 82500, Quantity I > Quantity II.

Multiple choice
  1. Rs. 35000 रु. 35000

  2. Rs. 42500 रु. 42500

  3. Rs. 38000 रु. 38000

  4. Rs. 45200 रु. 45200

  5. None of these इनमें से कोई नहीं

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let principal be P. Total SI for 7 years = P×(4/100×3 + 8/100×2 + 9/100×2) = P×(12/100 + 16/100 + 18/100) = P×46/100 = 19550. Solving: P = 19550×100/46 = Rs. 42,500.

Multiple choice
  1. Rs. 33000

  2. Rs. 45000

  3. Rs. 25500

  4. Rs. 32500

  5. Rs. 35000

Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Total time = 4 years 1 month = 49 months. Interest breakdown: 18 months at 8%, 6 months at 10%, 10 months at 12%, 15 months at 4%. Using months for consistency: Total interest = P × [(18×8 + 6×10 + 10×12 + 15×4) / (12×100)] = P × (384/1200) = P × 0.32. Given 11200 = 0.32P, so P = 11200/0.32 = Rs. 35000.

Multiple choice
  1. Quantity I > Quantity II < Quantity III

  2. Quantity I > Quantity III > Quantity II

  3. Quantity I > Quantity II = Quantity III

  4. Quantity I = Quantity II ≤ Quantity III

  5. Quantity I > Quantity II > Quantity III

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Quantity I: For the difference between CI and SI at 12% for 2 years being 1296, the formula gives P = 1296/0.0144 = 90,000. Quantity II: 512 becomes 729 in 3 years gives rate = 12.5%. CI for 2 years at 12.5% being 21250 gives principal = 80,000. Quantity III: 5 men can sit in 5! = 120 ways, 5 women can sit in alternate 5 positions in 5! = 120 ways. Total arrangements = 120 x 120 = 14,400. Therefore Quantity I (90,000) > Quantity III (14,400) > Quantity II (80,000), matching option B.

Multiple choice

Find the value of quantities and state the correct relationship- मात्राओं के मान ज्ञात कीजिये तथा सही सम्बन्ध स्थापित कीजिये- Quantity I- A sum of Rs. 13500 is distributed in two part and first part deposited in a bank at the rate of 6% per annum for 5 years while second part deposited in the bank at the rate of 8% per annum for 3 years. If simple interest obtained on both the parts are same then find the difference of money between these two part? Quantity II- If any amount borrowed at the rate of x p.c.p.a. for 3 years and the same amount borrowed at the rate of (x+3) p.c.p.a. for same time then the difference between their simple interest is Rs.135 , find the sum of money? मात्रा I- 13500 रुपये की राशि को दो भाग में बांटा गया है और पहला भाग 5 वर्षों के लिए 6% प्रति वर्ष की दर से बैंक में जमा किया गया है, जबकि दूसरे भाग को 3 वर्षों के लिए 8% प्रति वर्ष की दर से बैंक में जमा किया गया है। यदि दोनों भागों पर प्राप्त साधारण ब्याज समान है तो इन दोनों भागों के बीच धन का अंतर ज्ञात कीजिए? मात्रा II- यदि कोई राशि x प्र.श.वा. व्याज की दर से 3 साल के लिए उधार ली गई है और उतनी ही राशि (x+3) प्र.श.वा. व्याज की दर से उतने ही समय के लिए उधार ली गई और उनके साधारण ब्याज के बीच का अंतर Rs.135 था,राशि ज्ञात कीजिये?

  1. Quantity I > Quantity II मात्रा I> मात्रा II

  2. Quantity I ≥ Quantity II मात्रा I≥ मात्रा II

  3. Quantity II > Quantity I मात्रा II> मात्रा I

  4. Quantity II ≥ Quantity I मात्रा II≥ मात्रा I

  5. Quantity I = Quantity II or Relation cannot be established मात्रा I = मात्रा II या

Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

For Quantity I: Let the two parts be x and (13500-x). SI1 = x×6×5/100 = 30x/100, SI2 = (13500-x)×8×3/100 = 24(13500-x)/100. Setting equal: 30x = 324000 - 24x, so 54x = 324000, x = 6000. Parts are 6000 and 7500, difference = 1500. For Quantity II: SI at (x+3)% minus SI at x% = P×3×3/100 = 9P/100 = 135, so P = 1500. Both quantities equal 1500, so the answer is E (Quantity I = Quantity II).

Multiple choice
  1. Any two कोई भी दो

  2. I and II I तथा II

  3. I and II or III I तथा II या III

  4. Only II केवल II

  5. None of these इनमे से कोई नहीं

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

From II: P becomes 9P in 1 year with half-yearly compounding. With half-yearly: rate per period = r/2, periods = 2. So P(1 + r/2)² = 9P, meaning (1 + r/2)² = 9 = 3². Thus 1 + r/2 = 3, so r = 400%. For yearly compounding: P(1 + 4)ᵗ = 27P, so 5ᵗ = 27, giving t = log(27)/log(5) ≈ 2.05 years. Only Statement II is needed. I gives principal amount (not needed), and III just states the half-yearly conversion rule.

Multiple choice
  1. Quantity I > Quantity II मात्रा I > मात्रा II

  2. Quantity I < Quantity II मात्रा I < मात्रा II

  3. Quantity I ≥ Quantity II मात्रा I ≥ मात्रा II

  4. Quantity I ≤ Quantity II मात्रा I ≤ मात्रा II

  5. Quantity I = Quantity II or relation cannot be established मात्रा I = मात्रा II या निर्धारित नहीं किया जा सकता मात्रा II

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Principal = Rs 5200, rates: Year 1 at 8%, Year 2 at 9%, Year 3 at 10%. Amount after 3 years = 5200 × 1.08 × 1.09 × 1.10 ≈ 5200 × 1.29452 ≈ 6732. Compound Interest = 6732 - 5200 = Rs 1532. Since Quantity I (15865) is much greater than Quantity II (~1532), Quantity I > Quantity II.

Multiple choice
  1. Quantity: I > Quantity: II मात्रा: I> मात्रा: II

  2. Quantity: I ≥ Quantity: II मात्रा: I: मात्रा: II

  3. Quantity: I < Quantity: II मात्रा: I<मात्रा: II

  4. Quantity: II ≥ Quantity: I मात्रा: II ≥ मात्रा: I

  5. Quantity I = Quantity II or relation can't be established मात्रा I = मात्रा II या संबंध स्थापित नहीं किया जा सकता है

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

CI on Rs.5000 for 2 years at x%: 5000[(1+x/100)²-1]. SI on Rs.2650 for 4 years at x%: 2650*4*x/100. Setting equal: 5000[(1+x/100)²-1] = 2650*4*x/100. This gives x = 6%. SI = 2650*4*6/100 = Rs.636. Quantity I = Rs.636. Since 636 < 1275, Quantity I < Quantity II.

Multiple choice
  1. Rs.14,000

  2. Rs.16,000

  3. Rs.13000

  4. Rs.17000

  5. Rs.15000

Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Let first deposit = x, second = y. Given x+y = 27500 and x(1.2)^4 = y(1.2)^3 (same maturity amount). Simplifying: x(1.2) = y, so x = y/1.2 = 5y/6. Substituting: 5y/6 + y = 27500, so 11y/6 = 27500, y = 27500 * 6/11 = 15000. So 3-year deposit (y) = Rs. 15000.

Multiple choice
  1. Only I and II केवल I और II

  2. Only II and III केवल II तथा III

  3. Only II केवल II

  4. All of these सभी एक साथ

  5. None of these इनमें से कोई नहीं

Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Let P be principal and R be rate. From I: SI = P×R×2/100 = 8800. From II: P + SI = 30800, so P = 22000. Substituting: 440R = 8800, R = 20%. Statement III (CI - SI = 880) verifies this since P(R/100)² = 22000(0.2)² = 880, confirming the rate. All three statements together are needed to uniquely determine R = 20%.

Multiple choice
  1. Quantity I > Quantity II मात्रा I > मात्रा II

  2. Quantity I ≥ Quantity II मात्रा I ≥ मात्रा II

  3. Quantity I < Quantity II मात्रा I <मात्रा II

  4. Quantity I ≤ Quantity II मात्रा I ≤ मात्रा II

  5. Quantity I = Quantity II or the relation cannot be established मात्रा I = मात्रा II या संबंध स्थापित नहीं किया जा सकता

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Using Simple Interest formula: SI = P×R×T/100. Given SI=17920, R=8%, T=4 years, so P = 17920×100/(8×4) = 1792000/32 = 56000. Quantity I = 56000, Quantity II = 45000. Since 56000 > 45000, Quantity I > Quantity II.

Multiple choice
  1. Only I केवल I

  2. Only II केवल II

  3. Both I and II I और II दोनों

  4. Either I or II या तो I या II

  5. Neither I nor II न तो I और न ही II

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Statement I: Amount doubles in 12.5 years at simple interest, so interest = principal. SI = P×R×T/100 = P, giving R×12.5/100 = 1, so R = 8%. Statement II: P = 5000, A = 5832, T = 2 years at CI. 5832 = 5000(1 + r/100)², giving 1.1664 = (1 + r/100)², so 1 + r/100 = 1.08, r = 8%. Both statements independently give the rate.

Multiple choice
  1. 6.5%

  2. 7.2%

  3. 4.8%

  4. 5.2%

  5. 6.2%

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Normal amount at 20% for 3 years: 15,00,000(1.2)^3 = 25,92,000. Actual amount: Years 1-2 at 20%, Year 3 at 25% (20% + 25% of 20% = 25%). So 15,00,000(1.2)^2(1.25) = 27,00,000. Extra = 1,08,000. Percentage of loan = (1,08,000/15,00,000) × 100 = 7.2%. The key is understanding that the rate increases by 25% of the original rate (25% of 20% = 5%), not to 25%.

Multiple choice
  1. Rs. 39500 39500 रू.

  2. Rs. 42500 42500 रू.

  3. Rs. 44000 44000 रू.

  4. Rs. 45000 45000 रू.

  5. None of these इनमें से कोई नहीं

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Simple interest is calculated on the principal. For 7 years at varying rates: 3 years at 4%, 2 years at 8%, 2 years at 9%. Total rate = 3*4 + 2*8 + 2*9 = 12 + 16 + 18 = 46%. If principal is P, then 46% of P = 19550. P = 19550*100/46 = Rs. 42500.

Multiple choice
  1. 15%

  2. 12%

  3. 18%

  4. 10%

  5. None of these इनमे से कोई नही|

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

For 2 years, CI - SI = P(R/100)². Given CI = 4200, SI = 4000, so CI - SI = 200. This equals P(R/100)². Also SI = P×R×2/100 = 2PR/100 = 4000. From CI - SI = P(R/100)² = PR²/10000 = 200. From SI: 2PR/100 = 4000, PR = 200000. Substituting: (200000)R/10000 = 200, 20R = 200, R = 10%. Verify: P = 200000/10 = 20000. SI = 20000×10×2/100 = 4000 ✓, CI = 20000×(1.1²-1) = 20000×0.21 = 4200 ✓