Simple and Compound Interest Questions

Multiple choice
  1. Rs. 400

  2. Rs. 380

  3. Rs. 310

  4. Rs. 345

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Using the simple interest formula A = P(1 + rt), where A = 403, r = 10% = 0.10, and t = 3 years. Substituting: 403 = P(1 + 0.10 × 3) = P(1.3). Therefore, P = 403/1.3 = 310. Option A (Rs. 400) and B (Rs. 380) are incorrect as they don't satisfy the formula.

Multiple choice
  1. 8 years

  2. 14 years

  3. 12 years

  4. 15 years

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Simple Interest = Principal × Rate × Time. Here: SI = 9870-5250 = Rs.4620, P = Rs.5250, R = 11%. Using the formula: 4620 = 5250 × 0.11 × T. Therefore, T = 4620/(5250 × 0.11) = 4620/577.5 = 8 years. After 8 years at 11% simple interest, Rs.5250 will amount to Rs.9870.

Multiple choice
  1. Rs. 600

  2. Rs. 560

  3. Rs. 675

  4. Rs. 650

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The difference between amounts after 4 years and 3 years (806 - 767 = 39) is the simple interest for one year. At 6% per annum, Principal = (Interest × 100) / (Rate × Time) = (39 × 100) / (6 × 1) = 650. Verification: Interest for 3 years = 650 × 6 × 3 / 100 = 117, so Amount = 650 + 117 = 767 ✓

Multiple choice
  1. Rs. 1,55,945

  2. Rs. 1,95,455

  3. Rs. 1,94,555

  4. Rs. 1,45,955

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let P be the balance amount after down payment. Simple interest at 10% on P is 0.1P, so total payable = P + 0.1P = 1.1P. This equals 20 × 25,000 = 5,00,000. Therefore 1.1P = 5,00,000, giving P = 4,54,545 (approx). Down payment = 6,50,000 - 4,54,545 = 1,95,455. Option B matches.

Multiple choice
  1. ₹4,000

  2. ₹4,193

  3. ₹4,393

  4. ₹4,388

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Principal = 35,000, rate = 6% p.a. compounded half-yearly means 3% per half-year for 4 periods. Amount = 35000(1.03)⁴ = 35000 × 1.1255 = 39,393. Compound Interest = 39,393 - 35,000 = 4,393. Option C matches this calculation. Verify: (1.03)⁴ = 1.1255088, times 35000 = 39392.8, nearest rupee is 39393.

Multiple choice
  1. $₹ 560$
  2. $₹ 506$
  3. $₹ 650$
  4. $₹ 605$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

CI for 2 years: 5000(1.1² - 1) = 5000 × 0.21 = 1050. CI for 3 years: 5000(1.1³ - 1) = 5000 × 0.331 = 1655. Difference: 1655 - 1050 = 605. Alternatively, the extra interest in year 3 is 10% of the amount after year 2: (5000 × 1.21) × 0.10 = 6050 × 0.10 = 605.

Multiple choice
  1. 5 percent

  2. 20 percent

  3. 10 percent

  4. 15 percent

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

For simple interest: Amount = Principal + (P×R×T)/100. Given P=3000, Amount=6000, so Interest=3000. Since R=T (rate equals time), we have 3000 = (3000×R×R)/100, which gives R²=100, so R=10%. Checking: 3000 + (3000×10×10)/100 = 3000 + 3000 = 6000.

Multiple choice
  1. ₹ 20000

  2. ₹ 30000

  3. ₹ 35000

  4. ₹ 40000

  5. None of these इनमें से कोई नहीं

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Difference between CI and SI for 2 years = P × r²/10000. Given: 256 = P × 8²/10000 = P × 64/10000. So P = 256 × 10000/64 = 256 × 156.25 = ₹40,000. The formula for 2-year difference at rate r% is P(r/100)².

Multiple choice
  1. If statement I alone is sufficient but statement II alone is not sufficient.

  2. If statement II alone is sufficient but statement I alone is not sufficient.

  3. If each statement alone (either I or II) is sufficient.

  4. If statement I and II together are not sufficient.

  5. If both statement together are sufficient, but neither statement alone is sufficient.

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

To find the difference between simple interest (SI) and compound interest (CI), we need the principal amount (P), rate (R), and time (T). Statement I gives rate = 5%. Statement II gives interest = Rs. 1250 after 5 years, but doesn't specify whether this is SI or CI, and doesn't give the principal. Even together, we cannot determine the principal uniquely because we don't know which type of interest the Rs. 1250 represents. Both statements together are insufficient.

Multiple choice
  1. Rs.500 @ 10%, Rs.800 @ 12%

  2. Rs.700 @ 10%, Rs.600 @ 12%

  3. Rs.800 @ 10%, Rs.400 @ 12%

  4. Rs.700 @ 10%, Rs.500 @ 12%

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let amount at 12% = x and at 10% = y. Then 0.12x + 0.10y = 130 and 0.10x + 0.12y = 134. Subtracting: -0.02x + 0.02y = 4, so y - x = 200. From first eq: 12x + 10(x + 200) = 13000 gives 22x + 2000 = 13000, so 22x = 11000, x = 500, y = 700. So Rs. 500 at 12%, Rs. 700 at 10%. Option D has this.

Multiple choice
  1. Rs./रु.30956.80

  2. Rs./रु.35017.20

  3. Rs./रु.43597.80

  4. Rs./रु.44247.20

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Year 1-2: Simple Interest = 35500 × 15% × 2 = Rs.10650. Amount after 2 years = 35500 + 10650 = Rs.46150. Year 3-5 (3 years of Compound Interest at 20%): 46150 × (1.20)^3 - 46150 = 46150 × 1.728 - 46150 = 79747.20 - 46150 = Rs.33597.20. Total interest = 10650 + 33597.20 = Rs.44247.20. The problem involves two phases: simple interest for 2 years, then compound interest for 3 years on the accumulated amount.

Multiple choice
  1. Rs. 700

  2. Rs. 500

  3. Rs. 800

  4. Rs. 400

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let amount at 12% be x, at 10% be y. Then 0.12x+0.10y=130. If interchanged: 0.12y+0.10x=134. Subtracting: 0.02y-0.02x=4 → 0.02(y-x)=4 → y-x=200. Solving: from first eq, 12x+10y=13000. Using y=x+200: 12x+10(x+200)=13000 → 22x=11000 → x=500. Amount at 12%=Rs.500.