Quantitative Aptitude

Time, Work, and Projects

190 Questions

Time and work questions test the ability to calculate the time required to complete tasks involving individual or combined worker efficiency. These problems frequently appear in competitive exams to assess logical calculation skills. Topics include pipes, cisterns, group efficiency, and hourly work rates.

Combined work efficiencyMen and days calculationsWorker efficiency ratiosWorking hours per dayLeaving and joining workers

Time, Work, and Projects Questions

Multiple choice

A transporter receives the same number of orders each day. Currently, he has some pending orders (backlog) to be shipped. If he uses 7 trucks, then at the end of the 4th day he can clear all the orders. Alternatively, if he uses only 3 trucks, then all the orders are cleared at the end of the 10th day. What is the minimum number of trucks required so that there will be no pending order at the end of the 5th day?

  1. 4

  2. 5

  3. 6

  4. 7
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Multiple choice business mathematics and statistics applications of calculus revenue functions from marginal revenue functions minimization of cost function and maximization of revenue function and profit function integral calculus – ii

A village road is to be constructed by a team of $250$ workers. After $12$ days it was found that only $2/7^{th}$ part of the work was complete. To complete the rest in another $25$ days, how many more workers should be employed?

  1. $53$
  2. $52$
  3. $55$
  4. $50$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let the total unit of work be $7$ units.
According to question,
$\dfrac {M _{1}D _{1}}{W _{1}} = \dfrac {M _{2}D _{2}}{W _{2}} \Rightarrow \dfrac {250\times 12}{2} = \dfrac {M _{2}\times 25}{(7 - 2)} \Rightarrow M _{2} = 300$
Number of extra workers needed $= 300 - 250 = 50$.

Multiple choice maths how much does it weigh? basic operations with same units operations involving units of length calculations define weight and units of weight

Mr Sahoo attended a 1-day workshop from 09:15 a.m. to half five in the evening. The workshop included a $1\frac{1}{4}$ hour lunch break, two 15 minutes tea breaks and 13 activities, each of equal duration. Calculate the duration of each activity.

  1. $30$ minutes
  2. $20$ minutes
  3. $25$ minutes
  4. $40$ minutes
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Total time of the workshop =$8$ hours and $15$ min

$=8 \times 60+15=495 $ min

Total time of tea break = $30$ min

lunch break time = $75$ min

hence time available for 13 activities 
$=495-75-30$ $=6$ hours and $30$ min
$=390 $ min

So, time devoted to each activity $=\dfrac{390}{13}=30$ min

Multiple choice political science gender inequality across the wall gender disparity global problems and india's role human rights : origin, characteristics and types international problems problems affecting the world

How much more an Indian woman, on an average, works than a man every day?

  1. one hour more

  2. two hours more

  3. three hours more

  4. one hour less
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
 On an average, an Indian woman works one hour more than an average man every day. Yet much of her work is not paid and therefore often not valued. 
Multiple choice maths direct proportion and inverse proportion inverse proportion rule of three types of proportions

The number of workers increased the days to complete the work decreased."is example of 

  1. Inverse ratio

  2. Direct ratio

  3. Both of A and B

  4. none of above
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Inverse proportion is a relation between two quantities such that one increases in proportion as the other decreases i.e. If $x$ increases as $y$ decreases, $x \alpha \dfrac{1}{y}$ 

In the given example, if the no. of workers are increased then the time required to do the job will decrease, likewise if no. of workers decrease, then time to do the same job will increase i.e. no. of workers and time to do job are inversely proportional to each other.
hence the answer is inverse proportion
So, the answer is option A.

Multiple choice maths direct proportion and inverse proportion inverse proportion rule of three types of proportions

Ten men, working for 6 days of 10 hours each, finish $ \dfrac {5}{21} $ of a piece of work. How many men working at the same rate and for the same number of hours each day, will be required to complete the remaining work in 8 days?

  1. 24

  2. 26

  3. 25

  4. 21
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Lets first find the number of working hours required to complete $\dfrac { 5 }{ 21 }$ of the work.
M = number of men
D = number of days
H = number of hours worked per day
N = work done
MDH = N
10$\times $6$\times $10 = $\dfrac { 5 }{ 21 }$
600 hours to complete $\dfrac { 5 }{ 21 }$ of work
Let the total number of hours required to complete the work be $x$ then
$x$ = $\dfrac { 5 }{ 21 }$ $\div $600
   = 600$\times $$\dfrac { 21 }{ 5
 }$
$x$   = 2520 hours
so the remaining work is $x$$-$  $\dfrac { 5 }{ 21 }$
               = $\dfrac {16 }{ 21 }$ $x$

               =$\dfrac {16 }{ 21 }$$\times $2520
               = 1920 hours required to complete remaining $\dfrac {16 }{ 21 }$ of the work
 now the equation we get is
MDH = N
MDH = 1920
M $\times $ 8$\times $10 = 1920
M =  $\dfrac { 1920 }{ 80 } $
M = 24
 Ans. 24 men

Multiple choice maths profit-loss overhead expenses introduction to total cost price of the article profit and loss with overhead expenses

if 5 men and 9 women can do a piece of work in 19 days then in how many days will 3 men and 6 women do the same work ?

  1. 12 days

  2. 15 days

  3. 18 days

  4. 21 days
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation
It is given that 5 men or 9 women can do the job in 19 days.

So, 5 men=9 women

1 man = $\dfrac { 9 }{ 5 }$ women

3 men = 3 $(\dfrac { 9 }{ 5 } )$ women

So, work done = 3 men+6 women = 3 $(\dfrac { 9 }{ 5 } )+6$

$=\dfrac { 27 }{ 5 } +6$

$=\dfrac { 57 }{ 5 } $

Now,$ \dfrac { {M} _{1} {D} _{1} }{{W} _{1} }$= $ \dfrac { {M} _{2} {D} _{2} }{ {W} _{2} } ,$ 

let ${D} _{2} = x$

$\dfrac { 9*19 }{ {W} _{1} } = \dfrac { \dfrac { 57 }{ 5 } *x }{ {W} _{2} }$

$ \Longrightarrow 9*19=\dfrac { 57x }{ 5 }$

$ \Longrightarrow 3=\dfrac { x }{ 5 }$

$ \Longrightarrow x=15$ days

So, option (b) is correct.