Quantitative Aptitude
Time and Work
2,195 Questions
Time and Work Questions
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$A$
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$B$
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$C$
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$A$ and $B$ both
C
Correct answer
Explanation
A completes 1/5 in 12 days, so 1 work in 60 days. B completes 60% (3/5) in 30 days, so 1 work in 50 days. C completes 1/3 in 15 days, so 1 work in 45 days. C is the fastest.
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$15$ days
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$7.5$ days
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$9$ days
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$12.5$ days
B
Correct answer
Explanation
10 women = 15 days, so 1 woman = 150 days. 6 men = 10 days, so 1 man = 60 days. Work rate of 5 women + 6 men = 5/150 + 6/60 = 1/30 + 1/10 = 4/30 = 2/15. Time = 15/2 = 7.5 days.
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$\displaystyle 14\frac{2}{5}$ Days
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9 Days
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8 Days
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$\displaystyle 7\frac{5}{9}$
C
Correct answer
Explanation
B completes 17/35 of the work in 17 days, so the remaining work completed by A and B together is 18/35. Their combined daily rate is 1/28 + 1/35 = 9/140, and 18/35 divided by this rate equals 8 days.
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Rs. $120$
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Rs. $108$
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Rs. $60$
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Rs. $36$
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$\displaystyle 20\frac{1}{2}$days
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$\displaystyle 20\frac{3}{5}$days
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21 days
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$\displaystyle 20\frac{4}{7}$days
D
Correct answer
Explanation
Total work = 8 * 9 * 20 = 1440 man-hours. New setup: 7 men * 10 hours * D days = 1440. D = 1440 / 70 = 144 / 7 = 20 and 4/7 days.
B
Correct answer
Explanation
Work done = 120m in 60 days by 30 men. Remaining work = 240m in 60 days. (M1*D1)/W1 = (M2*D2)/W2. (30*60)/120 = (M2*60)/240. M2 = 60. More men needed = 60 - 30 = 30.
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$100$ men
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$150$ men
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$120$ men
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$80$ men
C
Correct answer
Explanation
Work = 75 boys * 24 days = 1800 boy-days. Double work = 3600 boy-days. 2 men = 3 boys, so 1 man = 1.5 boys. 20 days * M men * 1.5 boys/man = 3600 boy-days. 30M = 3600, M = 120.
B
Correct answer
Explanation
Work done = 3/4 in 60 days by 60 men. Remaining work = 1/4. Remaining time = 90 - 60 = 30 days. Let x be men needed. (60 * 60) / (3/4) = (x * 30) / (1/4). 3600 / 0.75 = 30x / 0.25. 4800 = 120x. x = 40. Men to discharge = 60 - 40 = 20.
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$6$ days
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$6.25$ days
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$7.2$ days
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$7.5$ days
D
Correct answer
Explanation
A's rate = 1/12. B is 60% more efficient, so B's rate = 1.6 * (1/12) = 1.6/12 = 16/120 = 2/15. Time taken by B = 1 / (2/15) = 15/2 = 7.5 days.
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$15$ days
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$20$ days
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$25$ days
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$30$ days
C
Correct answer
Explanation
A = B + C (in terms of work rate). A + B = 1/10, C = 1/50. Since A = B + C, substitute A: (B + C) + B = 1/10 => 2B + 1/50 = 1/10 => 2B = 5/50 - 1/50 = 4/50 = 2/25. So B = 1/25. B takes 25 days.
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$13$ days
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$15$ days
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$20$ days
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$13.33$ days
D
Correct answer
Explanation
Let work rates be A, B, C. A = 0.5B, C = 0.5(A+B) = 0.5(1.5B) = 0.75B. Given C = 1/40, then 0.75B = 1/40, so B = 1/30. Then A = 1/60. Total rate = 1/60 + 1/30 + 1/40 = (2+4+3)/120 = 9/120 = 3/40. Time = 40/3 = 13.33 days.
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$\displaystyle 5\frac{1}{4}$ days
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$\displaystyle 6\frac{1}{4}$ days
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$\displaystyle 7\frac{1}{2}$ days
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None of these
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$23$ days
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$37$ days
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$\displaystyle 37\frac{1}{2}$ days
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$40$ days
C
Correct answer
Explanation
Since A completes 4/5 of the work in 20 days, A can complete the entire work alone in 25 days, meaning A's daily work rate is 1/25. The remaining 1/5 of the work is completed by A and B together in 3 days, which means their combined daily rate is 1/15. Subtracting A's rate from the combined rate gives B's daily rate as 1/15 - 1/25 = 2/75, so B alone takes 75/2 = 37 1/2 days.
D
Correct answer
Explanation
Rates: Man = 1/3, Woman = 1/4, Boy = 1/12. Total work needed in 1/4 day is 1 unit. 1 man + 1 woman in 1/4 day = (1/3 + 1/4) * 1/4 = (7/12) * 1/4 = 7/48. Remaining work = 1 - 7/48 = 41/48. Boys needed = (41/48) / (1/12 * 1/4) = (41/48) / (1/48) = 41.