Quantitative Aptitude
Time and Work
2,195 Questions
Time and Work Questions
B
Correct answer
Explanation
Using M1*D1*H1 = M2*D2*H2: 39 * 12 * 5 = 30 * D2 * 6. 2340 = 180 * D2. D2 = 2340 / 180 = 13.
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$23$ days
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$37$ days
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$37\cfrac{1}{2}$
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$40$ days
C
Correct answer
Explanation
A does 80% in 20 days, so A's rate is 4% per day. Remaining 20% is done by A and B in 3 days, so (A+B)'s rate is 20/3 = 6.66% per day. B's rate = 6.66 - 4 = 2.66% per day. Time for B = 100 / 2.66 = 37.5 days.
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$I$ alone sufficient while $II$ alone not sufficient to answer
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$II$ alone sufficient while $I$ alone not sufficient to answer
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Either $I$ or $II$ alone sufficient to answer
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Both $I$ and $II$ are not sufficient to answer
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Both $I$ and $II$ are necessary to answer
A
Correct answer
Explanation
Statement I: A+B take 7 days. If they work 5 days, they finish 5/7 of the work. A finishes the remaining 2/7 alone. This is sufficient. Statement II: Does not provide enough info to isolate A's work.
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$5$ days
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$6$ days
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$10$ days
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$10\cfrac{1}{2}$ days
C
Correct answer
Explanation
A's work rate is 1/24, B's is 1/9, C's is 1/12. B and C work for 3 days, completing 3 * (1/9 + 1/12) = 3 * (4/36 + 3/36) = 3 * (7/36) = 7/12 of the work. Remaining work is 1 - 7/12 = 5/12. A completes this in (5/12) / (1/24) = 5/12 * 24 = 10 days.
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Any two of the three
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$I$ and $II$ only
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$II$ and $III$ only
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$I$ and $III$ only
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None of these
A
Correct answer
Explanation
Let M be men's rate, W be women's rate. I: 10M = 1/6. II: 10M + 10W = 1/(24/7) = 7/24. III: 10M*3 + 10W*4 = 1. Any two of these equations allow solving for M and W, thus finding the time for 10 women (1/W).
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$13\cfrac{1}{3}$ days
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$15$ days
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$20$ days
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$26$ days
A
Correct answer
Explanation
X does 1/40 of work per day. In 8 days, X does 8/40 = 1/5 of the work. Remaining work = 4/5. Y finishes 4/5 in 16 days, so Y does (4/5)/16 = 1/20 of the work per day. Together, they do 1/40 + 1/20 = 3/40 of the work per day. Time taken = 40/3 = 13 1/3 days.
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$I$ only
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$II$ and $III$ only
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$III$ only
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$I$ and $III$ only
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Any one of the three
E
Correct answer
Explanation
All three statements provide enough information to calculate the total work capacity and thus the number of workers required for 10 days. I: 20% in 8 days by 8 workers -> 100% in 40 days by 8 workers -> 10 days by 32 workers. II: 20 workers in 16 days -> 10 days by 32 workers. III: 1/8 in 5 days by 8 workers -> 100% in 40 days by 8 workers -> 10 days by 32 workers.
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$I$ only
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$II$ only
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$III$ only
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$I$ or $II$ or $III$
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$II$ or $III$ only
A
Correct answer
Explanation
Using the work formula M1*D1 = M2*D2, we have 15 * 20 = 25 * D2. 300 = 25 * D2, so D2 = 300/25 = 12 days.
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$14$ days
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$6$ days
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$8$ days
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$10$ days
C
Correct answer
Explanation
A's work rate is 1/20, B's is 1/15, and C's is 1/12. On day 1, A and B work together (1/20 + 1/15 = 7/60); on day 2, A and C work together (1/20 + 1/12 = 8/60). In 2 days, they complete 15/60 = 1/4 of the work, so the total work takes 8 days.
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$\dfrac {3}{4}$ days
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$1\dfrac {1}{2}days$
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$3\ days$
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$7\ days$
B
Correct answer
Explanation
A's rate = 1 / (20/3) = 3/20 work/day. B's rate = 1/5 = 4/20 work/day. Combined rate = 7/20 work/day. Work done in 2 days = 2 * (7/20) = 14/20 = 7/10. Remaining work = 3/10. B finishes 3/10 at rate 1/5: (3/10) / (1/5) = 15/10 = 1.5 days.
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$20\ men$
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$25\ men$
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$15\ men$
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$30\ men$
B
Correct answer
Explanation
Work = (M * D * W) / Wages. (45 * 48 * 1) / 15525 = (N * 16 * 2) / 5750. 2160 / 15525 = 32N / 5750. N = (2160 * 5750) / (15525 * 32) = 12420000 / 496800 = 25.
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92 days
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128 days
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111 days
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84 days
B
Correct answer
Explanation
This is an inverse proportion problem. 8 workers * 96 days = 6 workers * x days. x = (8 * 96) / 6 = 128 days.
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$3$ days
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$5$ days
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$4 \, \dfrac{1}{2}$ days
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$4$ days