Quantitative Aptitude
Time and Work
2,195 Questions
Time and Work Questions
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$4$ days
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$10$ days
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$15$ days
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$20$ days
A
Correct answer
Explanation
3 men = 5 women. So 1 man = 5/3 women. 6 men + 5 women = 6(5/3) + 5 = 10 + 5 = 15 women. 5 women take 12 days, so 15 women take (5/15) * 12 = 4 days.
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24 days
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6 days
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12 days
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20 days
A
Correct answer
Explanation
Work = (Workers * Days * Hours) / Units. (1 * 18 * 4) / 5 = (1 * D * 6) / 10. 72/5 = 6D/10. 14.4 = 0.6D. D = 14.4 / 0.6 = 24.
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$4000$
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$4320$
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$4500$
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$4860$
D
Correct answer
Explanation
Let total work be 720 units (LCM of 40, 48, 60). Efficiencies: S=18, T=15, U=12. Total efficiency = 45. Let total days be D. S worked D days, T worked D-2, U worked D-5. 18D + 15(D-2) + 12(D-5) = 720. 45D - 30 - 60 = 720. 45D = 810, D = 18. S worked 18 days. S's share = (18 * 18 / 720) * 10800 = (324/720) * 10800 = 0.45 * 10800 = 4860.
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$14$ days
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$16$ days
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$13$ days
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$17$ days
B
Correct answer
Explanation
Using the formula (M1 * D1 * H1) = (M2 * D2 * H2), we have 24 * 15 * 8 = 20 * D2 * 9. Solving for D2: D2 = (24 * 15 * 8) / (20 * 9) = 2880 / 180 = 16.
A
Correct answer
Explanation
The total work is 10 × 40 = 400 man-days. If the four men leave after x days, then 10x + 6(50 - x) = 400, which gives x = 25 days.
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144/5, 36, 48
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36, 48, 144/5
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48, 144/5, 36
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none of these
A
Correct answer
Explanation
Let work rates be A, B, C. A+B+C = 1/12. A+C = 2B implies 3B = 1/12, so B = 1/36. A+B = 3C implies 4C = 1/12, so C = 1/48. Then A = 1/12 - 1/36 - 1/48 = (12-4-3)/144 = 5/144. Time taken: A=144/5, B=36, C=48.
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$9\ days$
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$10\ days$
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$11\ days$
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$14\ days$
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$10$ days
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$7 \dfrac { 1 } { 2 }$ days
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$12$ days
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$12 \frac { 1 } { 2 }$ days
A
Correct answer
Explanation
If B is 50% more efficient than A, B's efficiency is 1.5 times A's. Time taken by B = Time taken by A / 1.5 = 15 / 1.5 = 10 days.
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$35$
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$\dfrac{81}{7}$
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$\dfrac{60}{7}$
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$\dfrac{61}{5}$
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$2\frac{3}{5}$ days
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$4\frac{4}{5}$ days
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$5\frac{4}{5}$ days
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none of there
B
Correct answer
Explanation
A's work rate is 1/8 per day and B's rate is 1/12 per day. Together their rate is 1/8 + 1/12 = 5/24, so the required time is 24/5 = 4 4/5 days.
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$31$ days
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$32$ days
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$23$ days
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$21$ days
B
Correct answer
Explanation
This is an inverse proportion problem. The total work is 200 students * 40 days = 8000 student-days. Dividing this by 250 students gives 8000 / 250 = 32 days.
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$14days$
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$12days$
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$9days$
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$10days$
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$\None \of \these$
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$6$ days
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$8$ days
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$10$ days
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$12$ days
B
Correct answer
Explanation
Let M be daily wage of a man, W of a woman. (4M + 6W) * 5 = 1600 => 4M + 6W = 320. (3M + 7W) * 6 = 1740 => 3M + 7W = 290. Solving: 12M + 18W = 960 and 12M + 28W = 1160. 10W = 200, W = 20. 4M + 120 = 320, 4M = 200, M = 50. For 7M + 6W: 7(50) + 6(20) = 350 + 120 = 470 per day. Days = 3760 / 470 = 8.