Multiple choice

$S, T$ and $U$ can complete a work in $40, 48$ and $60$ days respectively. They received$Rs. 10800$ to complete the work. They begin the work together but $T$ left $2$ days before the completion of the work and $U$ left $5$ days before the completion of work. $S$ has completed the remaining work alone. What is the share of $S$ (in Rs) from total money.

  1. $4000$
  2. $4320$
  3. $4500$
  4. $4860$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let total work be 720 units (LCM of 40, 48, 60). Efficiencies: S=18, T=15, U=12. Total efficiency = 45. Let total days be D. S worked D days, T worked D-2, U worked D-5. 18D + 15(D-2) + 12(D-5) = 720. 45D - 30 - 60 = 720. 45D = 810, D = 18. S worked 18 days. S's share = (18 * 18 / 720) * 10800 = (324/720) * 10800 = 0.45 * 10800 = 4860.

AI explanation

Using the LCM method with total work as 240 units, the daily work rates of S, T, and U are 6, 5, and 4 units respectively. Assuming the project took n days, S worked for n days, T worked for n-2 days, and U worked for n-5 days. The equation for total work is 6n + 5(n-2) + 4(n-5) = 240, which simplifies to 15n - 30 = 240. Solving this gives n = 18 days, and S worked all 18 days to complete 108 units of work. The share of money is proportional to work done, so S receives 10800 multiplied by the fraction 108/240, which is Rs. 4860.