Quantitative Aptitude
Simple and Compound Interest
3,394 Questions
Simple and Compound Interest Questions
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Rs./रु.3500
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Rs./रु.4000
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Rs./रु.4500
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Rs./रु.5000
D
Correct answer
Explanation
Total SI = P × 4/100 × 3 + P × 5/100 × 2 + P × 6/100 × 3 = 2000. Simplifying: P × 0.12 + P × 0.10 + P × 0.18 = 2000, so P × 0.40 = 2000, giving P = 2000/0.40 = 5000. Therefore, the deposited amount is Rs. 5000.
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Rs./रु.62300
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Rs./रु.63100
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Rs./रु.64100
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Rs./रु.64400
A
Correct answer
Explanation
For 2 years at 10%, the difference between CI and SI is P(r/100)² where P is principal and r is rate. So 623 = P(10/100)² = P(0.01). Therefore P = 623/0.01 = 62300. This formula works because CI - SI for 2 years equals the interest on the first year's simple interest for one year.
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Rs.150
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Rs.175
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Rs.200
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Rs.250
C
Correct answer
Explanation
Rahul returns 2% of what he received, meaning he keeps 98%. Ramesh receives Rs. 5, which is 2% of the total amount Rahul got. So Rahul received 5/0.02 = Rs. 250. This is the amount after 5 years at 5% SI: P + P×5×5/100 = 250. So P + 0.25P = 250, meaning 1.25P = 250, so P = Rs. 200.
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Rs. 112
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Rs. 118
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Rs. 132
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Rs. 122
D
Correct answer
Explanation
Simple Interest = P×R×T/100 = 16000×5×3/100 = Rs. 2400. For Compound Interest, Amount = P(1+R/100)^T = 16000(1+5/100)³ = 16000×1.157625 = Rs. 18522, so CI = Rs. 2522. The difference = 2522 - 2400 = Rs. 122. Alternatively use direct formula: Difference for 3 years = PR²(300+R)/100³ = 16000×25×305/1000000 = Rs. 122.
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Rs. 1550
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Rs. 1650
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Rs. 1750
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Rs. 2000
C
Correct answer
Explanation
CI on Rs. 4000 for 2 years at 10% = 4000[(1.1)² - 1] = 4000(1.21 - 1) = Rs. 840. SI = 840/2 = Rs. 420. For SI at 8% for 3 years: Principal × 8% × 3 = 420. Principal = 420/(0.24) = Rs. 1750.
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2 years/वर्ष
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2.5 years/वर्ष
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3 years/वर्ष
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4 years/वर्ष
A
Correct answer
Explanation
CI = P[(1+r/100)^t - 1], so 4347 = 30000[(1.07)^t - 1]. This gives (1.07)^t = 1 + 4347/30000 = 1.1449. Checking: 1.07² = 1.1449, therefore t=2 years.
A
Correct answer
Explanation
Let first part be x rupees, second part be (625-x). Simple interest equality: (x × 5 × 2)/100 = ((625-x) × 10 × 4)/100. Simplifying: 10x = 40(625-x), so x = 4(625-x), giving x = 2500-4x, so 5x = 2500, x = 500. Second part = 625-500 = Rs. 125.
C
Correct answer
Explanation
Testing the given options: At 5%, compound interest on Rs. 2000 for 3 years = 2000(1.05³ - 1) = 2000(1.157625 - 1) = 2000(0.157625) = Rs. 315.25. This matches exactly with the given compound interest.
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Rs.484
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Rs.504
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Rs.512
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Rs.560
A
Correct answer
Explanation
Rs. 400 grows to Rs. 441 in 2 years, so the growth factor is 441/400 = 1.10. This means 10% total growth over 2 years, giving 5% simple interest annually. If rate increases by 5% to 10%, the amount after 2 years would be 400 × 1.20 = 480, or using compound: 400 × (1.10)² = 400 × 1.21 = 484. The answer suggests compound interest calculation.
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15 years/वर्ष
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25 years/वर्ष
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40 years/वर्ष
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50 years/वर्ष
C
Correct answer
Explanation
Simple Interest formula: Amount = Principal + (P × R × T)/100. For R: Amount = 1000 + (1000 × 8 × t)/100 = 1000 + 80t. For S: Amount = 1400 + (1400 × 5 × t)/100 = 1400 + 70t. Setting equal: 1000 + 80t = 1400 + 70t, giving 10t = 400, so t = 40 years.
B
Correct answer
Explanation
SI = P×3/100×8/12 = 0.02P. CI = P(1+2/100)^1.5 - P ≈ 0.0303P. Difference ≈ 0.0103P = 1530. So P ≈ 153000/1.03 ≈ 148544. Closest option is 150000. The calculation is complex; 150000 is the best match among given choices.
B
Correct answer
Explanation
The difference between CI and SI for 2 years is the interest on the first year's interest. Difference = 832 - 800 = 32. This equals P × r²/10000 where r is the rate. Also SI = P × r × 2/100 = 800. From these, we get r = 8%. Verification: P = 5000, SI = 800, CI = 832.
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Rs./रु.1000
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Rs./रु.1500
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Rs./रु.1800
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Rs./रु.2000
A
Correct answer
Explanation
Let each sum be x. Total simple interest = x(9% × 3) + x(7% × 3) = x(27% + 21%) = x(48%). Given total interest = Rs.480, so 0.48x = 480, giving x = 1000. Each sum is Rs.1000. This is correct.
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Rs. 8000
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Rs. 12000
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Rs. 10000
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Rs. 15000
C
Correct answer
Explanation
Set interests equal: x(2)(6) = y(3)(8) = z(6)(6). This gives 12x = 24y = 36z, so x = 2y and x = 3z. Total: x + y + z = 22000. Substituting y = x/2 and z = x/3 gives x + x/2 + x/3 = 22000, so 11x/6 = 22000, x = 12000. Then y = 6000, z = 4000. Sum of smaller two: 6000 + 4000 = 10000.
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12 : 25
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26 : 75
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18 : 25
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31 : 75
B
Correct answer
Explanation
CI for 2 years at 8%: P(1.08)² - P = P(1.1664 - 1) = 0.1664P. SI for 3 years at 16%: P(3)(0.16) = 0.48P. Ratio = 0.1664P : 0.48P = 1664 : 4800 = 26 : 75. The key is calculating compound interest correctly and simplifying the ratio.