Quantitative Aptitude
Simple and Compound Interest
3,394 Questions
Simple and Compound Interest Questions
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3 years/वर्ष
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4 years/वर्ष
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5 years/वर्ष
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6 years/वर्ष
C
Correct answer
Explanation
For Rs. 6000 at 4% for 5 years: SI = 6000 × 0.04 × 5 = Rs. 1200. Amount = 7200. For Rs. 8000 at 3%, we need same interest. 8000 × 0.03 × T = 1200. T = 1200/(240) = 5 years. Set the interest amounts equal and solve for time.
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Rs.500
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Rs.600
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Rs.700
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Rs.710
B
Correct answer
Explanation
After 2 years, amount = 720. After further 5 years (total 7 years), amount = 1020. So interest for 5 years = 1020 - 720 = 300. Interest per year = 60. Interest for 2 years = 120. Principal = Amount after 2 years - Interest for 2 years = 720 - 120 = 600. Option B is correct.
D
Correct answer
Explanation
For compound interest: Amount = Principal × (1 + r/100)^n. Given: 2.25P = P(1 + r/100)^2. Therefore (1 + r/100)^2 = 2.25 = 1.5^2, so 1 + r/100 = 1.5, giving r = 50%. Option D is correct.
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9100
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7800
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5200
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4200
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Cannot be determined.
E
Correct answer
Explanation
The question is ambiguous - 'doubles his investment after 5 years' could mean reinvesting the accumulated amount or adding an equal principal. Without clarity on the compounding mechanism, a definitive answer cannot be calculated.
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10 : 9
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9 : 8
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9 : 10
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8 : 9
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None of these
C
Correct answer
Explanation
For Atul: P1 × 15 × 4 / 100 = 1280, so P1 = Rs. 2133.33. For Aakash: P2 × 8 × 5 / 100 = 1008, so P2 = Rs. 2520. Ratio Aakash:Atul = 2520:2133.33 = 9:7.99 ≈ 9:8 after rounding.
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Rs. 11125.40
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Rs. 11050.60
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Rs. 12060.50
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Rs. 13025.40
A
Correct answer
Explanation
For compound interest with varying rates: Amount = Principal × (1 + r1/100) × (1 + r2/100) × (1 + r3/100). Amount = 9525 × (1.03) × (1.05) × (1.08) = 9525 × 1.03 × 1.05 × 1.08 = 9525 × 1.168... = Rs. 11125.40 (approximately).
C
Correct answer
Explanation
For 2 years, the difference between CI and SI is P(r/100)² = 410-400=10. From SI: 2Pr/100=400, so Pr/100=200. Therefore (r/100)×200=10, giving r/100=1/20, hence r=5%. The 5% rate satisfies both conditions.
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9 : 6 : 4
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9 : 8 : 7
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9 : 6 : 5
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9 : 8 : 2
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9 : 3 : 1
A
Correct answer
Explanation
Using CI formula A = P(1 + r)^t where r = 50% = 1/2. For equal final amounts: P1 × (3/2)^5 = P2 × (3/2)^10 = P3 × (3/2)^15. Taking ratios: P1 : P2 : P3 = (3/2)^-5 : (3/2)^-10 : (3/2)^-15. Inverting and simplifying: P1 : P2 : P3 = 2^15/3^5 : 2^20/3^10 : 2^25/3^15. Common ratio gives 9 : 6 : 4. Work backwards from equal final amounts.
B
Correct answer
Explanation
Let total capital be Rs. x. Half at 10% gives (x/2) × 10% = 5x%. One-third at 9% gives (x/3) × 9% = 3x%. Remaining (x - x/2 - x/3) = x/6 at 12% gives (x/6) × 12% = 2x%. Total interest = 5x% + 3x% + 2x% = 10x%. Average rate = 10x%/x = 10%.
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Rs./रु.30000
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Rs./रु.26800
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Rs./रु.27300
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Rs./रु.28500
C
Correct answer
Explanation
For first year at 4%: 25000 × 1.04 = Rs. 26000. For second year at 5%: 26000 × 1.05 = Rs. 27300. Alternatively, using the formula A = P(1 + r1)(1 + r2) = 25000 × 1.04 × 1.05 = 25000 × 1.092 = Rs. 27300.
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Rs. 8500
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Rs. 9414.4
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Rs. 8914.4
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Rs. 9914.4
D
Correct answer
Explanation
Compound interest for 2 years at 8%: CI = P[(1 + 8/100)^2 - 1] = P[1.1664 - 1] = 0.1664P. Given CI = Rs. 1414.4, so P = 1414.4/0.1664 = Rs. 8500. Total amount = P + CI = 8500 + 1414.4 = Rs. 9914.4.
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Rs./रु.6986.1142
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Rs./रु.7042.2014
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Rs./रु.7126.8512
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Rs./रु.8321.4166
C
Correct answer
Explanation
Simple Interest: 6216 = 14800 × R × 3, so Rate R = 6216/(14800×3) = 14% per annum. Compound Interest for 3 years at 14%: 14800 × [(1.14)^3 - 1] = 14800 × (1.481544 - 1) = 14800 × 0.481544 = Rs.7126.85. The difference between compound and simple interest arises because CI earns interest on interest, while SI only earns on the principal. For the same rate and period, CI is always greater than SI when time > 1 year.
A
Correct answer
Explanation
Let rate = R% and time = T years. Given rate = time, so R = T. Simple Interest = Principal × R × T / 100 = P × R × R / 100. Also given: SI = 16% of Principal = 0.16P. So P × R² / 100 = 0.16P, giving R² = 16. Therefore R = 4% (rate cannot be negative). Verification: 4% rate for 4 years gives SI = P × 4 × 4 / 100 = 16% of P.
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Rs./रु.1250
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Rs./रु1000
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Rs./रु1200
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Rs./रु1320
C
Correct answer
Explanation
For compound interest, interest in year n = P(1+r/100)^(n-1) × r/100. CI for 2nd year is 110% of 1st year means (1+r/100) = 2.1, so r = 110%. CI for 2nd year = P × 1.1 × 1.1 = 1.21P. SI for 5th year = P × 5 × 1.1 = 5.5P. Difference = 5.5P - 1.21P = 12. P = 1200.
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Rs.3000
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Rs.3600
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Rs.4500
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Rs.6000
B
Correct answer
Explanation
The difference between CI and SI for 2 years is CI - SI = P(r/100)² where P is principal. Given: 144 = P(20/100)² = P(0.04), so P = 144/0.04 = Rs.3600. The amount asked for is Rs.3600. Verification: SI for 2 years at 20% = Rs.1440, CI = 3600(1.2)² - 3600 = Rs.1584, difference = Rs.144.