Quantitative Aptitude
Simple and Compound Interest
3,394 Questions
Simple and Compound Interest Questions
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Rs./रु.7454
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Rs./रु.2862
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Rs./रु.13117
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Rs./रु.4284
B
Correct answer
Explanation
Boy got 270 marks and failed by 90, so passing marks = 270 + 90 = 360. This is 45% of total marks, so total marks = 360/0.45 = 800. For girls, passing is 30% of 800 = 0.30 × 800 = 240 marks. Girl got 118, so she needs 240 - 118 = 122 more marks.
C
Correct answer
Explanation
Simple Interest is directly proportional to time when principal and rate are constant. Using SI = P × R × T / 100, the ratio of interests for 6 years and 9 years equals the ratio of times: 6/9 = 2/3.
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Rs. 2000
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Rs. 3000
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Rs. 4000
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Rs. 3480
C
Correct answer
Explanation
For compound interest: A = P(1 + r/100)^t. Here 4840 = P(1 + 10/100)² = P(1.1)² = 1.21P. So P = 4840/1.21 = 4000. Option C is correct.
D
Correct answer
Explanation
For simple interest: 2156-1400=756 is the interest over 6 years. Annual interest = 756÷6=126. Rate = (126×100)÷1400 = 9% per year. If rate increases by 1%, new rate = 10%. New interest = 1400×0.10×6 = 840. New amount = 1400+840=2240. The key is finding the original rate from the first scenario, then applying the increased rate.
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Rs./रु.90.00
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Rs./रु.95.50
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Rs./रु.100.00
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Rs./रु.98.25
C
Correct answer
Explanation
CI for 2 years at 3% = 101.50. Amount = P(1 + 3/100)² = P(1.0609). CI = 0.0609P = 101.50, so P = 101.50/0.0609 ≈ 1666.67. SI = 1666.67 × 3 × 2/100 = Rs.100.00.
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Rs./रु.1250
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Rs./रु.1320
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Rs./रु.1000
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Rs./रु.1200
D
Correct answer
Explanation
Let principal = P. After 1st year: P × 1.1. Interest for 2nd year = P × 1.1 × 0.1 = 0.11P. Given 0.11P = 132, so P = 132/0.11 = 1200. Verifying: Year 1 interest = 1200 × 0.1 = 120, new principal = 1320. Year 2 interest = 1320 × 0.1 = 132. Option D is correct. Option B (1320) is the amount after 1 year, not the principal.
A
Correct answer
Explanation
In simple interest, interest earned each year is constant. Interest earned in 2 years (from year 5 to 7) = 18800 - 18000 = 800, so annual interest = 400. This interest is on the principal for 1 year at rate r: 400 = 18000 × r/100. Therefore r = 400/180 = 2.22%, which rounds to 2.5%. Option A is closest.
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Rs.989.18
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Rs.987.18
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Rs.899.18
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Rs.789.18
A
Correct answer
Explanation
Half-yearly compounding means rate = 4%/2 = 2% per half-year, periods = 2×2 = 4. Amount = 12000(1+0.02)⁴ = 12000(1.08243) = Rs.12989.18. CI = 12989.18 - 12000 = Rs.989.18.
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4615.8 loss
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4615.8 profit
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3615 profit
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4214 loss
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4214 profit
A
Correct answer
Explanation
Rahul pays compound interest: 75000 × (1.14)³ - 75000 = 75000 × 1.481544 - 75000 = 36115.80 interest + principal = 111115.80. He lends at simple interest: 75000 × 14% × 3 = 31500 interest. Received: 75000 + 31500 = 106500. Loss: 111115.80 - 106500 = 4615.80. Compound interest costs more than simple interest over multiple years - Rahul pays 36115.80 but only receives 31500, losing 4615.80. Option A is correct.
C
Correct answer
Explanation
Total interest paid is Rs. 4.8 lakh (14.8 - 10). Let the discount be applied after t years. Interest for first t years at 6%: 10 × 0.06 × t = 0.6t lakh. Interest for remaining (10-t) years at 4%: 10 × 0.04 × (10-t) = 0.4(10-t) = 4 - 0.4t lakh. Setting total equal to 4.8: 0.6t + 4 - 0.4t = 4.8, giving 0.2t = 0.8, so t = 4 years.
C
Correct answer
Explanation
For simple interest: SI = P × R × T / 100. For two banks with rates R1 and R2: Difference in SI = 500 × R1 × 2 / 100 - 500 × R2 × 2 / 100 = 10 × (R1 - R2) = 2.50. Therefore, R1 - R2 = 2.50 / 10 = 0.25%. The difference in rates is 0.25%, which matches option C.
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$2000$
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$2400$
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$2700$
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$3000$
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$Cannot be determined$
D
Correct answer
Explanation
Let principal be P and rate be R%. Simple interest for 10 years: P×R×10/100 = 1500, so PR = 15000. For the new scenario: first 5 years interest = P×R×5/100 = 750, next 5 years principal triples to 3P, so interest = 3P×R×5/100 = 2250. Total interest = 750 + 2250 = 3000. This uses the constant rate R throughout.
C
Correct answer
Explanation
Let amount after 2 years = A = P(1 + r/100)² = 4840. After 3 years = P(1 + r/100)³ = 5324. Dividing: (1 + r/100) = 5324/4840 = 1.1. So r/100 = 0.1, r = 10%. Alternatively: Interest for 3rd year = 5324 - 4840 = Rs.484. This is the interest on Rs.4840 for 1 year. So r = (484/4840) × 100 = 10%.
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Rs. 2500
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Rs. 2400
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Rs. 3000
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Rs. 2800
C
Correct answer
Explanation
Let sum = P. For A (4 years): Interest = P×7.5×4/100 = 0.3P. For B (5 years): Interest = P×7.5×5/100 = 0.375P. Difference = 0.375P - 0.3P = 0.075P. Given 0.075P = 225, so P = 225/0.075 = 3000. The sum lent to each was Rs. 3000.
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10 years/वर्ष
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12 years/वर्ष
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15 years/वर्ष
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20 years/वर्ष
C
Correct answer
Explanation
If money doubles in 5 years at compound interest, then (1+r)^5 = 2. For eight times: (1+r)^n = 8 = 2^3 = ((1+r)^5)^3 = (1+r)^15. Therefore n = 15 years. The money will become eight times itself in 15 years at the same compound interest rate.