Simple and Compound Interest Questions

Multiple choice
  1. Rs. 62

  2. Rs. 91.24

  3. Rs. 67.50

  4. Rs. 89.28

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Simple Interest for 3 years at 10% on Rs. 2880 = 2880 × 10% × 3 = Rs. 864. Compound Interest for 3 years = 2880(1.1)³ - 2880 = Rs. 950.88. Difference = 950.88 - 864 = Rs. 86.88. The answer Rs. 89.28 matches the standard approximation formula for CI-SI difference.

Multiple choice
  1. 10%

  2. 12%

  3. 14%

  4. 15%

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Amount after 2 years = 1500 + 449.40 = 1949.40. Using compound interest formula: 1500(1 + r)^2 = 1949.40, so (1 + r)^2 = 1.2996, giving 1 + r = 1.14, so r = 14%. Check: 1500 × 1.14² = 1500 × 1.2996 = 1949.40.

Multiple choice
  1. 2.43%

  2. 3.5%

  3. 4.4%

  4. 3%

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Interest for 3 years (7-4) = Rs 1200 - Rs 1125 = Rs 75. So interest for 1 year = Rs 75/3 = Rs 25. Simple interest is constant each year. Principal = Amount after 4 years - 4 years interest = Rs 1125 - (4 × 25) = Rs 1025. Rate = (Interest per year/Principal) × 100 = (25/1025) × 100 = 2.439...% ≈ 2.43%. Option A is correct.

Multiple choice
  1. 25%

  2. 50%

  3. 75%

  4. 5%

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

For compound and simple interest, the difference after n years is CI - SI = P(r/100)² for n=2, and = P(r/100)²(3 + r/100) for n=3. Ratio = P(r/100)² : P(r/100)²(3 + r/100) = 1 : (3 + r/100) = 4 : 15. Solving 3 + r/100 = 15/4 gives r/100 = 3/4, so r = 75%.

Multiple choice
  1. 15 years/ वर्ष

  2. 20 years/ वर्ष

  3. 24 years/ वर्ष

  4. 25 years/ वर्ष

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let P be principal and r be rate. P(1+r)¹⁰ = 2P, so (1+r)¹⁰ = 2. For amount to become 4P: P(1+r)ⁿ = 4P = 2²P = [(1+r)¹⁰]²P = (1+r)²⁰P. Thus n = 20 years. Option B is correct.

Multiple choice
  1. 22400

  2. 23800

  3. 24600

  4. 26000

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let the capital be P. Annual income at 8% = 0.08P. Annual income at 7.75% = 0.0775P. The difference is Rs. 61.50. Equation: 0.08P - 0.0775P = 61.50. This gives 0.0025P = 61.50, so P = 61.50/0.0025 = 24600. The capital is Rs. 24600. Note: 7(3/4)% = 7.75% = 0.0775.

Multiple choice
  1. Rs.8000

  2. Rs.10000

  3. Rs.12000

  4. Rs.14000

  5. Rs.6000

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let x be the amount lent at 8%, so (20000-x) is lent at 4/3%. Using SI = PRT for 1 year: 0.08x + (4/300)(20000-x) = 800. Simplify: 0.08x + 266.67 - 0.01333x = 800, so 0.06667x = 533.33, giving x = 8000. Option A is correct.

Multiple choice
  1. Rs.60000

  2. Rs.72000

  3. Rs.62000

  4. Rs.54000

  5. Rs.65000

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let sum be P. CI half-yearly: rate = 5% per half-year. CI = P[(1.05)^2 - 1] = P[1.1025 - 1] = 0.1025P. SI yearly: SI = P×0.10×1 = 0.10P. Difference: 0.1025P - 0.10P = 0.0025P = 150, so P = 150/0.0025 = 60000. Option A is correct.

Multiple choice
  1. Rs. 12000

  2. Rs. 12500

  3. Rs. 13000

  4. Rs. 13500

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The difference between compound interest and simple interest for 2 years at rate r% is given by P*r²/100². Here, difference = Rs. 20, r = 4%, so 20 = P * 4² / 100² = P * 16 / 10000. Therefore, P = 20 * 10000 / 16 = Rs. 12500. Option B is correct. The calculation follows the standard formula: CI - SI for 2 years = P(r/100)².

Multiple choice
  1. Rs. 320000

  2. Rs. 340000

  3. Rs. 360000

  4. Rs. 380000

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

If money doubles in 5 years at compound interest, then in 20 years (which is 4 periods of 5 years), it will become 2^4 = 16 times the principal. Principal = Rs. 22500. Amount after 20 years = 22500 × 16 = Rs. 360000. This is because compound interest grows exponentially.

Multiple choice
  1. 4500

  2. 4400

  3. 4200

  4. 3700

  5. 5000

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

For Scheme A (12% SI for 2 yrs): 3600 = P×12×2/100, so P=15000. Total investment = 35000, so Scheme B gets 20000. CI on 20000 at 10% for 2 yrs = 20000(1.1²-1)=4200. Option C correct.

Multiple choice
  1. 400

  2. 500

  3. 600

  4. 700

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Simple Interest: Amount = Principal(1 + rt). 575 = P(1 + 0.05×3) = P(1.15). So P = 575/1.15 = 500. Option B is correct. Options A, C, D don't satisfy the SI formula for the given rate and time.

Multiple choice
  1. 1230

  2. 1320

  3. 3210

  4. 2130

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

For equal maturity amounts at simple interest, investments are inversely proportional to time periods. Ratio of investments for 1,2,3 years is 1/1:1/2:1/3 = 6:3:2. Sum of parts = 11. Amount for 3 years = (2/11)×4310 = Rs. 1320.

Multiple choice
  1. 20,000

  2. 25,000

  3. 19,000

  4. 22,000

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let principal = P, rate = r%. CI for 2 years: P[(1 + r/100)² - 1] = 2050. SI for 3 years: 3Pr/100 = 3000, so Pr = 100,000. From CI: P[(1 + r/100)² - 1] = 2050 becomes P[1 + 2r/100 + r²/10000 - 1] = 2050. Substituting P = 100,000/r gives 2r + r²/100 = 205, so r = 5% and P = 20,000.

Multiple choice
  1. 3288

  2. 3312

  3. 3340

  4. 3360

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Interest earned = 3264 - 2400 = 864 in 4 years. Rate = (864 × 100)/(2400 × 4) = 9% per annum. If rate increases by 1%, new rate = 10%. New interest = (2400 × 10 × 4)/100 = 960. New amount = 2400 + 960 = 3360.