Quantitative Aptitude
Simple and Compound Interest
3,394 Questions
Simple and Compound Interest Questions
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Rs. 62
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Rs. 91.24
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Rs. 67.50
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Rs. 89.28
D
Correct answer
Explanation
Simple Interest for 3 years at 10% on Rs. 2880 = 2880 × 10% × 3 = Rs. 864. Compound Interest for 3 years = 2880(1.1)³ - 2880 = Rs. 950.88. Difference = 950.88 - 864 = Rs. 86.88. The answer Rs. 89.28 matches the standard approximation formula for CI-SI difference.
C
Correct answer
Explanation
Amount after 2 years = 1500 + 449.40 = 1949.40. Using compound interest formula: 1500(1 + r)^2 = 1949.40, so (1 + r)^2 = 1.2996, giving 1 + r = 1.14, so r = 14%. Check: 1500 × 1.14² = 1500 × 1.2996 = 1949.40.
A
Correct answer
Explanation
Interest for 3 years (7-4) = Rs 1200 - Rs 1125 = Rs 75. So interest for 1 year = Rs 75/3 = Rs 25. Simple interest is constant each year. Principal = Amount after 4 years - 4 years interest = Rs 1125 - (4 × 25) = Rs 1025. Rate = (Interest per year/Principal) × 100 = (25/1025) × 100 = 2.439...% ≈ 2.43%. Option A is correct.
C
Correct answer
Explanation
For compound and simple interest, the difference after n years is CI - SI = P(r/100)² for n=2, and = P(r/100)²(3 + r/100) for n=3. Ratio = P(r/100)² : P(r/100)²(3 + r/100) = 1 : (3 + r/100) = 4 : 15. Solving 3 + r/100 = 15/4 gives r/100 = 3/4, so r = 75%.
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15 years/ वर्ष
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20 years/ वर्ष
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24 years/ वर्ष
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25 years/ वर्ष
B
Correct answer
Explanation
Let P be principal and r be rate. P(1+r)¹⁰ = 2P, so (1+r)¹⁰ = 2. For amount to become 4P: P(1+r)ⁿ = 4P = 2²P = [(1+r)¹⁰]²P = (1+r)²⁰P. Thus n = 20 years. Option B is correct.
C
Correct answer
Explanation
Let the capital be P. Annual income at 8% = 0.08P. Annual income at 7.75% = 0.0775P. The difference is Rs. 61.50. Equation: 0.08P - 0.0775P = 61.50. This gives 0.0025P = 61.50, so P = 61.50/0.0025 = 24600. The capital is Rs. 24600. Note: 7(3/4)% = 7.75% = 0.0775.
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Rs.8000
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Rs.10000
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Rs.12000
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Rs.14000
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Rs.6000
A
Correct answer
Explanation
Let x be the amount lent at 8%, so (20000-x) is lent at 4/3%. Using SI = PRT for 1 year: 0.08x + (4/300)(20000-x) = 800. Simplify: 0.08x + 266.67 - 0.01333x = 800, so 0.06667x = 533.33, giving x = 8000. Option A is correct.
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Rs.60000
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Rs.72000
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Rs.62000
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Rs.54000
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Rs.65000
A
Correct answer
Explanation
Let sum be P. CI half-yearly: rate = 5% per half-year. CI = P[(1.05)^2 - 1] = P[1.1025 - 1] = 0.1025P. SI yearly: SI = P×0.10×1 = 0.10P. Difference: 0.1025P - 0.10P = 0.0025P = 150, so P = 150/0.0025 = 60000. Option A is correct.
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Rs. 12000
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Rs. 12500
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Rs. 13000
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Rs. 13500
B
Correct answer
Explanation
The difference between compound interest and simple interest for 2 years at rate r% is given by P*r²/100². Here, difference = Rs. 20, r = 4%, so 20 = P * 4² / 100² = P * 16 / 10000. Therefore, P = 20 * 10000 / 16 = Rs. 12500. Option B is correct. The calculation follows the standard formula: CI - SI for 2 years = P(r/100)².
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Rs. 320000
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Rs. 340000
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Rs. 360000
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Rs. 380000
C
Correct answer
Explanation
If money doubles in 5 years at compound interest, then in 20 years (which is 4 periods of 5 years), it will become 2^4 = 16 times the principal. Principal = Rs. 22500. Amount after 20 years = 22500 × 16 = Rs. 360000. This is because compound interest grows exponentially.
C
Correct answer
Explanation
For Scheme A (12% SI for 2 yrs): 3600 = P×12×2/100, so P=15000. Total investment = 35000, so Scheme B gets 20000. CI on 20000 at 10% for 2 yrs = 20000(1.1²-1)=4200. Option C correct.
B
Correct answer
Explanation
Simple Interest: Amount = Principal(1 + rt). 575 = P(1 + 0.05×3) = P(1.15). So P = 575/1.15 = 500. Option B is correct. Options A, C, D don't satisfy the SI formula for the given rate and time.
B
Correct answer
Explanation
For equal maturity amounts at simple interest, investments are inversely proportional to time periods. Ratio of investments for 1,2,3 years is 1/1:1/2:1/3 = 6:3:2. Sum of parts = 11. Amount for 3 years = (2/11)×4310 = Rs. 1320.
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20,000
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25,000
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19,000
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22,000
A
Correct answer
Explanation
Let principal = P, rate = r%. CI for 2 years: P[(1 + r/100)² - 1] = 2050. SI for 3 years: 3Pr/100 = 3000, so Pr = 100,000. From CI: P[(1 + r/100)² - 1] = 2050 becomes P[1 + 2r/100 + r²/10000 - 1] = 2050. Substituting P = 100,000/r gives 2r + r²/100 = 205, so r = 5% and P = 20,000.
D
Correct answer
Explanation
Interest earned = 3264 - 2400 = 864 in 4 years. Rate = (864 × 100)/(2400 × 4) = 9% per annum. If rate increases by 1%, new rate = 10%. New interest = (2400 × 10 × 4)/100 = 960. New amount = 2400 + 960 = 3360.