Quantitative Aptitude
Simple and Compound Interest
3,394 Questions
Simple and Compound Interest Questions
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Rs.4142.2
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Rs.4145.2
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Rs.4147.2
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Rs.5149.7
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Rs.4567.5
C
Correct answer
Explanation
CI = P[(1+r/100)^t - 1]. P=12000, r=16%, t=2. Amount = 12000×(1.16)^2 = 12000×1.3456 = 16147.2. CI = 16147.2-12000 = 4147.2. Apply compound interest formula systematically.
C
Correct answer
Explanation
Simple interest = (P×R×T)/100. Given SI = 240% of P = 12P/5. So 12P/5 = (P×R×16)/100. Solving: 12/5 = 16R/100, which gives 12/5 = 4R/25, so R = (12×25)/(5×4) = 15%.
B
Correct answer
Explanation
Step 1: Calculate amount from Arun using SI formula: SI = (P × R × T) / 100 = (1500 × 14 × 5) / 100 = Rs. 1050. Total received = Rs. 1500 + 1050 = Rs. 2550. Step 2: Let savings added be x. Total invested = Rs. (2550 + x) at 20% CI for 2 years. Using CI formula: Amount = Principal × (1 + r/100)^t. Interest earned = Rs. 1408. Solving: (2550 + x) × (1.20)^2 - (2550 + x) = 1408. This gives (2550 + x) × 0.44 = 1408, so 2550 + x = 1408 / 0.44 = 3200. Therefore x = 3200 - 2550 = Rs. 625.
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6615,6000
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6200,6415
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6400,6215
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6415,6200
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6000,6615
E
Correct answer
Explanation
Let Puneet's share = P and Shashank's share = S. Given: P + S = 12615. Using CI formula A = P(1 + 5/100)^6 = P(1.05)^6 for Puneet and A = S(1.05)^8 for Shashank. Both receive same amount: P(1.05)^6 = S(1.05)^8. This gives P = S(1.05)^2 = S × 1.1025. Substituting: 1.1025S + S = 12615, so 2.1025S = 12615. Solving: S = 12615 / 2.1025 = 6000. Therefore P = 12615 - 6000 = 6615. Share of Shashank and Puneet = 6000, 6615.
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$1830.625$
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$1730.625$
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$1370.625$
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$1570.50$
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None of these
B
Correct answer
Explanation
Using compound interest formula A = P(1 + r)^t: A = 6250 × (1.13)^2 = 6250 × 1.2769 = 7980.625. CI = A - P = 7980.625 - 6250 = 1730.625.
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Rs.27000
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Rs.18000
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Rs.9000
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Rs.36000
B
Correct answer
Explanation
Interest on Rs.15000 at 12% for 2 years = 15000 × 0.12 × 2 = 3600. Total interest = 9000, so interest on second loan = 9000 - 3600 = 5400. At 15% for 2 years: 5400 = P × 0.15 × 2, so P = 5400 / 0.3 = 18000, matching option B.
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Rs. 1891.50
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Rs. 1901.50
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Rs. 1791.50
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Rs. 1918.50
A
Correct answer
Explanation
For quarterly compounding, rate per quarter = 20%/4 = 5% and time = 9 months = 3 quarters. Amount = 12000 × (1 + 5/100)³ = 12000 × 1.157625 = Rs. 13891.50. Compound Interest = Amount - Principal = 13891.50 - 12000 = Rs. 1891.50. Option B (Rs. 1901.50) is incorrect as it doesn't follow the formula.
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Rs./रू.1200
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Rs./रू.2400
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Rs./रू.1500
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Rs./रू.1800
A
Correct answer
Explanation
For 2 years, a 1% higher rate yields Rs.24 more interest annually, so Rs.12 extra per year. This means Rs.12 equals 1% of the principal, giving principal as 12 times 100 equals Rs.1200. Formula: extra interest per year equals principal multiplied by rate difference.
A
Correct answer
Explanation
The difference between compound and simple interest for 2 years at rate r percent is given by the formula P times (r over 100) squared. Substituting 129.60 equals P times (9 over 100) squared gives P equals 129.60 times 10000 over 81 equals 16000. This works because compound interest earns interest on interest while simple interest does not.
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Rs. 81,000
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Rs.16,200
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Rs. 18,000
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Rs. 20,000
D
Correct answer
Explanation
Rate = 18% p.a., half-yearly compounding. For 1 year, effective rate for CI = (1 + 0.18/2)² - 1 = (1.09)² - 1 = 0.1881 or 18.81%. SI for 1 year = 18%. Difference = (18.81 - 18)% of P = 0.81% of P = 162. So P = 162 / 0.0081 = 20000.
C
Correct answer
Explanation
Amount becomes 1.331 times in 3 years at compound interest. Since 1.331^(1/3)=1.1, the rate is 10% per annum. Verify: 1×1.1³=1.331, which matches.
D
Correct answer
Explanation
Total interest=500×4×r/100 + 600×3×r/100 = 190. Simplifying: 2000r/100 + 1800r/100 = 190 gives 38r = 190, so r=5%.
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Rs/रू.5000
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Rs/रू.550
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Rs./रू.500
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Rs./रू.1500
C
Correct answer
Explanation
Difference between CI and SI for 3 years at rate r% is P × (r/100)² × (3 + r/100). Given r=10%, difference=15.50. Substituting: 15.50 = P × (1/10)² × (3.10) = P × 0.031. Solving: P = 15.50/0.031 = 500.
C
Correct answer
Explanation
Simple Interest formula: SI = P × R × T / 100. 2700 = P × 12 × 3 / 100, so P = 2700 × 100 / 36 = Rs. 7500. Compound Interest for 2 years at 12%: Amount = 7500 × (1 + 12/100)² = 7500 × 1.2544 = 9408. CI = 9408 - 7500 = Rs. 1908. Option A (2296) and B (2189) are calculation errors.
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16.408
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19.306
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14.218
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17.405
B
Correct answer
Explanation
Simple Interest = Prt/100 = 985 × 14 × 2/100 = Rs 275.80. Compound Interest = P[(1+r/100)² - 1] = 985[(1.14)² - 1] = 985[1.2996 - 1] = 985 × 0.2996 = Rs 295.106. The difference is 295.106 - 275.80 = 19.306. The difference between CI and SI for 2 years can also be calculated directly as P(r/100)² = 985(0.14)² = 985 × 0.0196 = 19.306.