Deepak has Rs.12615 a part of which he gave to Puneet for 6 years and remaining to Shashank for 8 years, at 5% rate of interest compounded annually. If both Puneet and Shashank gave him same amount at the end of their duration. Find the share of Shashank and Puneet respectively.

Let Puneet's share = P and Shashank's share = S. Given: P + S = 12615. Using CI formula A = P(1 + 5/100)^6 = P(1.05)^6 for Puneet and A = S(1.05)^8 for Shashank. Both receive same amount: P(1.05)^6 = S(1.05)^8. This gives P = S(1.05)^2 = S × 1.1025. Substituting: 1.1025S + S = 12615, so 2.1025S = 12615. Solving: S = 12615 / 2.1025 = 6000. Therefore P = 12615 - 6000 = 6615. Share of Shashank and Puneet = 6000, 6615.