Simple and Compound Interest Questions

Multiple choice
  1. 10%

  2. 12%

  3. 8%

  4. 9%

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Using compound interest formula A = P(1 + r/100)^n, the ratio A17.5/A16.5 = (1 + r/100)^(17.5-16.5) = 1 + r/100 = 27/25. So r/100 = 2/25, giving r = 8%. Option C is correct.

Multiple choice
  1. Rs.1000

  2. Rs.5000

  3. Rs.23200

  4. Rs.6000

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

SI on x: (x×5×2)/100=0.1x. CI on y for 2 years at 8%: y(1.08²-1)=y(1.1664-1)=0.1664y. Difference: 0.1664y-0.1x=232. Given x:y=6:5, let x=6k, y=5k: 0.1664(5k)-0.1(6k)=232 → 0.832k-0.6k=232 → 0.232k=232 → k=1000. y=5000, x=6000. Greater principal=6000.

Multiple choice
  1. 2.5%

  2. 10%

  3. 25%

  4. 12.5%

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the required rate be r% and capital be P. Simple interest for 1 year at r% = P × r/100. Simple interest for 2 years at 5% = P × 5 × 2/100 = P × 10/100. Equating: P × r/100 = P × 10/100 → r = 10%. Option B is correct.

Multiple choice
  1. Rs./रु.22000

  2. Rs./रु.20000

  3. Rs./रु.18000

  4. Rs./रु.16000

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let x be the loan at 10%, so (40000-x) is at 12%. Total interest: 0.1x + 0.12(40000-x) = 4440. Simplifying: 0.1x + 4800 - 0.12x = 4440, giving -0.02x = -360, so x = 18000. Options A and B would give insufficient total interest, while D gives excess.

Multiple choice
  1. Rs./रु.1600

  2. Rs./रु.1650

  3. Rs./रु.1700

  4. Rs./रु.1800

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let principal be P. CI for 2 years at 12%: P(1.12)² - P = 1908, so P(1.2544 - 1) = 1908, giving P = 1908/0.2544 = 7500. SI for 2 years at 12%: 7500 × 0.12 × 2 = 1800. Option A (1600) is 10% of P for 2 years, ignoring the actual rate.

Multiple choice
  1. Rs. 5384.45

  2. Rs. 5320.40

  3. Rs. 5402.50

  4. Rs. 5420.40

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Compound interest formula: A = P(1 + r)^n. A = 5000 × (1.025)³ = 5000 × 1.07689 = Rs. 5384.45.

Multiple choice
  1. 10 %

  2. 10.5 %

  3. 9.5 %

  4. 11 %

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let rate = r%. SI from Jairaj = 8200 × r × 16/100 = 1312r. SI from Karna = 4900 × r × 15/100 = 735r. Total SI = 1312r + 735r = 2047r = 19446.5. So r = 19446.5/2047 = 9.5%.

Multiple choice
  1. Rs. 1300

  2. Rs. 650

  3. Rs. 1250

  4. Rs. 625

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

If amount grows from Rs. 650 to Rs. 676 in one year, interest = Rs. 26. Rate = 26 ÷ 650 × 100 = 4%. Let principal be P, then P × 1.04 = 650, so P = 650 ÷ 1.04 = Rs. 625. Option A is incorrectly calculated as 650 × 2, option B is the first year's amount, and option C is a rough approximation.

Multiple choice
  1. Rs. 4320

  2. Rs. 4420

  3. Rs. 4440

  4. Rs. 4220

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

For equal annual installments with compound interest, the present value of all installments equals the loan amount. Let each installment be x. The PV is x/(1.2) + x/(1.2)² + x/(1.2)³ = x(0.8333 + 0.6944 + 0.5787) ≈ 2.1064x. Setting 2.1064x = 9100 gives x ≈ 4320. Verification: 4320/1.2 = 3600, 4320/1.44 = 3000, 4320/1.728 = 2500; sum = 9100.

Multiple choice
  1. Rs. 5000

  2. Rs. 1000

  3. Rs. 925

  4. Rs. 4000

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let x be the amount lent at 4%. Then (5000-x) is lent at 5%. Simple interest: x×4×5/100 + (5000-x)×5×5/100 = 1050. This gives 0.2x + 1250 - 0.25x = 1050, so -0.05x = -200 and x = 4000. The remaining 1000 is lent at 5%.

Multiple choice
  1. 2.43%

  2. 3.62%

  3. 4%

  4. 5%

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The simple interest for 3 years (from year 4 to year 7) is Rs. 1200-1125=Rs. 75. Annual interest is Rs. 25. In the first 4 years, total interest is 1125-P (where P is principal). So 4×25=1125-P, giving P=1025. Rate = (25/1025)×100 = 2.439%, which rounds to 2.43%.

Multiple choice
  1. 6

  2. 7

  3. 9

  4. 12

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

For a recurring deposit, maturity value M = P×n + P×n(n+1)/2×r/12×1/100 where P is monthly installment, n is number of months, r is annual rate. Here: P = 10, n = 24, M = 257.50. Principal deposited = 10×24 = 240. Interest = 257.50 - 240 = 17.50. Using the formula: I = P×n(n+1)/2×r/12×1/100, we get 17.50 = 10×24×25/2×r/12×1/100. Solving: 17.50 = 25r, so r = 0.70 or 7%.

Multiple choice
  1. Rs. 300

  2. Rs. 400

  3. Rs. 500

  4. Rs. 2500

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Simple interest for 2 years at 4% on Rs. 2,50,000 is 250000×4×2/100 = Rs. 20,000. Compound interest: After 1 year, amount = 250000(1 + 4/100) = 250000×1.04 = Rs. 2,60,000. After 2 years, amount = 260000×1.04 = Rs. 2,70,400. CI = 270400 - 250000 = Rs. 20,400. Difference = CI - SI = 20400 - 20000 = Rs. 400.