Quantitative Aptitude
Simple and Compound Interest
3,394 Questions
Simple and Compound Interest Questions
D
Correct answer
Explanation
Compound interest formula: A = P(1 + r/100)^n. Here A = 78125 × (1.04)^3 = 78125 × 1.124864 = Rs.87880 (approx). CI = A - P = 87880 - 78125 = Rs.9755. The answer is option D.
-
Rs. 32768
-
Rs. 37682
-
Rs. 37862
-
Rs. 37268
D
Correct answer
Explanation
Let installments be x, 2x, (3/4)(2x) = 1.5x. Using present value at 10% compound interest: x/1.1 + 2x/1.1² + 1.5x/1.1³ = 68740. Solving gives x ≈ 18634. Second installment = 2x ≈ 37268. Option D is correct.
D
Correct answer
Explanation
Simple Interest = P × R × T / 100. Difference in interests = P × T × (R1 - R2) / 100 = 7500 × 3 × ΔR / 100 = 225 × ΔR = 13.50. Therefore ΔR = 13.50 / 225 = 0.06%. Option D is correct.
-
292000
-
29200
-
229000
-
252000
A
Correct answer
Explanation
Daily interest = Rs. 40. Annual interest at 5% = 40 × 365 = Rs. 14,600. If principal is P, then 5% of P = 14,600. Therefore P = 14,600 × 100/5 = Rs. 2,92,000.
-
Rs. 12000
-
Rs. 12100
-
Rs. 12200
-
Rs. 12300
B
Correct answer
Explanation
Let annual payment = x. After 1st year: 21000×1.1 - x = 23100 - x. After 2nd year: (23100-x)×1.1 - x = 25410 - 2.1x = 0. Solving: 25410 = 2.1x, x = 12100. Verification: Year 1: 23100-12100=11000; Year 2: 11000×1.1-12100=12100-12100=0.
-
4252
-
4500
-
3852.5
-
4755
-
None of these
D
Correct answer
Explanation
Rajesh borrows Rs. 38400 at 10% simple interest for 3 years. Using SI = PRT/100, interest = 38400 * 10 * 3 / 100 = Rs. 11520. Total repayment to Seema = 38400 + 11520 = Rs. 49920. He lends the same amount at 12.5% compound interest annually for 3 years. Using A = P(1+r/100)^n, amount = 38400 * (1.125)^3 = 38400 * 1.4238 = Rs. 54975. Profit = 54975 - 49920 = Rs. 4755.
-
Rs. 6000
-
Rs. 7000
-
Rs. 8000
-
Rs. 15750
B
Correct answer
Explanation
For 2 years, CI - SI = P × (r/100)^2. Given CI - SI = 157.5 and r = 15%. So 157.5 = P × (15/100)^2 = P × 0.0225. Therefore P = 157.5/0.0225 = 157.5 × 10000/225 = 1575000/225 = 7000. Verification: SI for 2 years = 7000 × 0.15 × 2 = 2100. CI for 2 years = 7000 × (1.15)^2 - 7000 = 9257.50 - 7000 = 2257.50. CI - SI = 2257.50 - 2100 = 157.50. ✓
-
Rs. 3280
-
Rs. 3580
-
Rs. 3680
-
Rs. 3780
D
Correct answer
Explanation
Amount after 2nd year = 21780, after 3rd year = 23958. Interest for 3rd year = 23958 - 21780 = 2178. This is the interest on 21780 at rate r%. So r = (2178/21780) × 100 = 10%. Interest for 2nd year = 21780 - Amount after 1st year. Let A1 = amount after 1st year. Then A1 × 1.10 = 21780, so A1 = 19800. Principal = 19800/1.10 = 18000. CI for 2 years = 21780 - 18000 = 3780. ✓
A
Correct answer
Explanation
Simple Interest formula: SI = P × R × T / 100. Amount after 3 years = P + SI = P + (P × R × 3)/100 = P(1 + 3R/100). Given amount = (7/6)P, so (7/6)P = P(1 + 3R/100). Dividing by P: 7/6 = 1 + 3R/100, giving 3R/100 = 1/6, so R = 100/18 = 50/9 = 5(5/9)% per annum. Option B gives 6.67%, Option C gives 18%, and Option D gives 25% - all too high for the given growth.
-
Rs./रु.600
-
Rs./रु.675
-
Rs./रु.650
-
Rs./रु.625
B
Correct answer
Explanation
For compound interest: A = P(1 + r/100)ⁿ. Given A = Rs. 2916, r = 8%, n = 2 years. So 2916 = P(1.08)² = P × 1.1664, giving P = 2916/1.1664 = Rs. 2500. For simple interest at 9% for 3 years on Rs. 2500: SI = 2500 × 9 × 3 / 100 = Rs. 675. Option A requires principal Rs. 2500 at 8%, Option C would need Rs. 2500 at 8.67%, and Option D is a calculation error.
A
Correct answer
Explanation
Difference between CI and SI for 2 years at 12% = P(12/100)² = 360. This gives P × 0.0144 = 360, so P = 25000. Amount after 2 years = P(1 + 12/100)² = 25000 × 1.2544 = 31360. Options B, C, D are incorrect.
B
Correct answer
Explanation
Compound interest formula: A = P(1 + r/100)^n. Here P = 16000, r = 5%, n = 3. A = 16000(1.05)³ = 16000 × 1.157625 = 18522. CI = A - P = 18522 - 16000 = 2522.
-
Rs.12000
-
Rs.11025
-
Rs.11500
-
Cannot be determined
-
None of these
E
Correct answer
Explanation
Let the principal be P and rate be R%. Amount after 2 years = P + (P × R × 2)/100 = 12575. Amount after 4 years = P + (P × R × 4)/100 = 13125. Subtracting: (P × R × 2)/100 = 13125 - 12575 = 550. This means interest for 2 years is Rs 550. From first equation: P + 550 = 12575, so P = 12025. But 12025 is not in options A, B, C, or D. Option E (None of these) is correct.
-
Rs. 1800
-
Rs. 1500
-
Rs. 2400
-
Rs. 3000
-
None of these
B
Correct answer
Explanation
SI at 15% for 3 years: Interest = P × 0.15 × 3 = 0.45P. CI at 20% for 3 years: Amount = P × 1.20³ = 1.728P, Interest = 0.728P. Difference = 0.728P - 0.45P = 0.278P = 417. Solving: P = 417/0.278 = 1500.
-
Rs. 800
-
Rs. 1200
-
Rs. 1600
-
Rs. 1000
B
Correct answer
Explanation
Let sum be P. Difference: P×4×6/100 - P×5×4/100 = 48. This gives P(0.24 - 0.20) = 48, so 0.04P = 48, and P = 48/0.04 = 1200.