Simple and Compound Interest Questions

Multiple choice
  1. Rs. 1000

  2. Rs. 1200

  3. Rs. 1500

  4. Rs. 1600

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let sum be P. CI for 2 years at 2.5% = P[(1 + 2.5/100)² - 1] = P[(1.025)² - 1] = P(1.050625 - 1) = 0.050625P = 81. So P = 81/0.050625 = 1600.

Multiple choice
  1. Rs.1200

  2. Rs.1500

  3. Rs.1800

  4. Rs.2100

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

First calculate the reference interest: Rs.2000 at 4% p.a. for 3 years earns SI = 2000 × 4 × 3 / 100 = Rs.240. Let the required sum be P. Then P × 5 × 4 / 100 = 240, which gives 20P/100 = 240, so P = 240 × 5 = Rs.1200. Option B (Rs.1500) would give interest Rs.300. Option C (Rs.1800) would give Rs.360. Option D (Rs.2100) would give Rs.420.

Multiple choice
  1. 1000

  2. 1500

  3. 2400

  4. 3000

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let sum lent = P. Simple interest after 15 years at 5% = P × 5 × 15/100 = 0.75P. Given: 0.75P = P - 250, so 0.25P = 250, giving P = 1000. Verification: Interest on 1000 for 15 years at 5% = 1000 × 0.05 × 15 = 750, which is indeed 250 less than 1000.

Multiple choice
  1. 110

  2. 130

  3. 150

  4. 170

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Simple interest for each year is calculated separately on the principal. Year 1: Rs. 1000 × 4% = Rs. 40. Year 2: Rs. 1000 × 6% = Rs. 60. Year 3: Rs. 1000 × 7% = Rs. 70. Total simple interest = 40 + 60 + 70 = Rs. 170. The key is that simple interest is always calculated on the original principal, not on accumulated interest.

Multiple choice
  1. 3(1/2) years/वर्ष

  2. 1(1/2) years/वर्ष

  3. 2(1/2) years/वर्ष

  4. 2 years/वर्ष

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Half-yearly compounding at 10% means 5% per half-year. A = P(1 + r/100)^n gives 9261 = 8000(1.05)^n, so (1.05)^n = 1.157625. Since (1.05)^3 = 1.157625, n = 3 half-years = 1.5 years. Option B is correct.

Multiple choice
  1. Rs./रु.10000, Rs./रु.15000

  2. Rs./रु.12000, Rs./रु.13000

  3. Rs./रु.12500, Rs./रु.12500

  4. Rs./रु.16000, Rs./रु.9000

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Use allegation method: the ratio of amounts is (10-9.2):(9.2-8) = 0.8:1.2 = 2:3. This means one part is 2/5 of 25000 = Rs.10000 and the other is 3/5 of 25000 = Rs.15000. The allegation method gives the correct mixing ratio when two different rates are combined to produce an average rate.

Multiple choice
  1. 1500

  2. 1800

  3. 2000

  4. 2400

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The compound interest for successive years forms a geometric progression with common ratio (1 + r/100), where r is the annual rate. Since CI for 2nd year is 480 and for 3rd year is 576, we have 576/480 = 1.2, so the rate is 20%. Using CI for 2nd year = P(1 + r/100)(r/100), we get 480 = P(1.2)(0.2), giving P = 2000.

Multiple choice
  1. Rs. 100000

  2. Rs. 900000

  3. Rs. 150000

  4. Rs. 120000

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

For semi-annual compounding at 12% p.a., rate per 6 months = 6%, and amount = P(1 + 0.06)² = P(1.1236). CI = P(0.1236). SI for 1 year at 12% = P(0.12). Difference = P(0.1236 - 0.12) = P(0.0036) = 432. So P = 432/0.0036 = 120000.

Multiple choice
  1. Rs./रु.12000

  2. Rs./रु.12320

  3. Rs./रु.12500

  4. Rs./रु.11320

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

First year amount = 10000 × 1.10 = 11000. Second year amount = 11000 × 1.12 = 12320. Alternatively: 10000 × (1 + 10/100) × (1 + 12/100) = 10000 × 1.1 × 1.12 = 12320.

Multiple choice
  1. xyz = 1

  2. x2 = yz

  3. z = x2y

  4. y2 = xz

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Using SI = PRT/100, we have y = xRT/100 and z = yRT/100. Substituting y from the first into the second: z = (xRT/100)(RT/100) = x(RT/100)². Multiplying y² = x²(RT/100)² and comparing with xz gives y² = xz.

Multiple choice
  1. 200000

  2. 20000

  3. 10000

  4. 100000

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

For 3 years at 10%, the CI-SI difference formula is P(r/100)²(r/100 + 3). With r = 10, this becomes P(0.1)²(3.1) = 0.031P. Setting 0.031P = 620 gives P = 620/0.031 = 20000.

Multiple choice
  1. 20 years/वर्ष

  2. 30 years/वर्ष

  3. 10 years/वर्ष

  4. 22 years/वर्ष

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

If SI for 6 years = 30% of principal, then SI for 1 year = 5% of principal. For SI to equal principal (100%), we need 100% / 5% = 20 years. This is a direct proportion problem in simple interest.

Multiple choice
  1. 10 years / वर्ष

  2. 12 years / वर्ष

  3. 12.5 years / वर्ष

  4. 10.5 years / वर्ष

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

For the principal to become 3 times in 5 years at simple interest, the interest earned is 2P. Using SI = P×R×T/100: 2P = P×R×5/100 gives R = 40% per annum. To become 6 times, interest needed is 5P. Solving: 5P = P×40×T/100 gives 5 = 2T/5, so T = 12.5 years. The rate remains constant, and we find the time needed for 5 times the principal as interest.

Multiple choice
  1. Rs./रु.5000

  2. Rs./रु.4000

  3. Rs./रु.3600

  4. Rs./रु.3800

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

To find present worth with compound interest, use the formula PV = FV/(1+r)^n where PV is present value, FV is future value (Rs.5324), r is rate (10% or 0.10), and n is time (3 years). PV = 5324/(1.10)^3 = 5324/1.331 = Rs.4000. Verification: 4000 x 1.331 = 5324.