Quantitative Aptitude
Simple and Compound Interest
3,394 Questions
Simple and Compound Interest Questions
D
Correct answer
Explanation
The difference between compound interest and simple interest for 2 years is the interest on the first year's simple interest. Simple interest for 2 years = 10000, so for 1 year = 5000. Difference = CI - SI = 10625 - 10000 = 625, which is interest on 5000 for 1 year. Rate = (625/5000) × 100 = 12.5%.
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Rs. 6000
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Rs. 8000
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Rs. 5000
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Rs. 6500
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None of these
C
Correct answer
Explanation
Use compound interest formula: CI = P[(1+r/100)^n - 1]. Here CI = 618, r = 6%, n = 2. So 618 = P[(1.06)^2 - 1] = P[1.1236 - 1] = P(0.1236). Therefore P = 618÷0.1236 = 5000. Check: 5000×0.1236 = 618 ✓
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Rs. 1200
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Rs. 1250
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Rs. 1280
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Rs. 1296
B
Correct answer
Explanation
Amount = Principal * (1 + r/100)^t. 1352 = P * (1.04)^2. 1.04^2 = 1.0816. P = 1352 / 1.0816 ≈ 1250. The principal sum is Rs. 1250.
D
Correct answer
Explanation
Original amount: Rs. 600 becomes Rs. 740 in 5 years, so interest = Rs. 140. Rate = (140 × 100) / (600 × 5) = 14000 / 3000 = 4.67% per annum. New rate = 4.67% + 3% = 7.67%. New interest = 600 × 7.67% × 5 = Rs. 230. New amount = 600 + 230 = Rs. 830. The calculation checks out.
A
Correct answer
Explanation
For annual compounding: Amount = 1000(1.2)¹(1.1) = 1320, so CI = 320. For half-yearly: Amount = 1000(1.1)³ = 1331, so CI = 331. The difference is 331 - 320 = 11.
C
Correct answer
Explanation
Total interest = (450 × 2 × r)/100 + (500 × 3 × r)/100 = (900r + 1500r)/100 = 2400r/100 = 24r. Given 24r = 120, solving gives r = 5%. Therefore the rate of interest is 5%.
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72000 Rs.
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75500 Rs.
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80000 Rs.
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79000 Rs.
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None of these
D
Correct answer
Explanation
Let P be principal. Interest for first 4 years at 5% = P × 5 × 4/100 = 0.2P. Interest for next 6 years at 7.5% = P × 7.5 × 6/100 = 0.45P. Interest for remaining 5 years (years 11-15) at 9% = P × 9 × 5/100 = 0.45P. Total interest = 0.2P + 0.45P + 0.45P = 1.1P. Given 1.1P = 86900, so P = 86900/1.1 = Rs.79000.
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I and either II or III
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Any two
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II and either I or III
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II and III
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None of these
C
Correct answer
Explanation
Statement I: Principal becomes 3P in 3 years at SI, so rate r = 2P/3P = 2/3 per year. Statement II: CI for 2 years is 1700, so P(1+r)² - P = 1700. Statement III: P becomes 126.5625% of P after 2 years, so (1+r)² = 1.265625, giving r = 12.5%. II or III with I gives both r and P. From I, r = 2/3. Using r in II or III gives P. Then calculate amount at 3.5 years.
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968 Rs.
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1024 Rs.
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1052 Rs.
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1148 Rs.
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None of these
B
Correct answer
Explanation
Let the principal be P. Compound interest for 3 years at 8%: CI = P(1 + 0.08)³ - P = P(1.259712 - 1) = 0.124864P = 831.0784. So P = 831.0784/0.124864 ≈ 6656.78. Simple interest for 4 years at 8%: SI = P × 8% × 4 = 6656.78 × 0.08 × 4 ≈ 2130.17. Wait, this doesn't match. Let me recalculate: CI = P((1.08)³ - 1) = P × 0.259712 = 831.0784, so P = 831.0784/0.259712 ≈ 3200. Then SI = 3200 × 0.08 × 4 = 1024, making option B correct.
A
Correct answer
Explanation
The difference between amounts after 7 years and 4 years is Rs. 75 (1200-1125), which is interest for 3 years. Annual interest = Rs. 25. Interest for 4 years = Rs. 100, so principal = 1125-100 = Rs. 1025. Rate = (100×100)/(1025×4) = 10000/4100 ≈ 2.439%, closest to 2.43%.
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4090.8
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4040.8
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4060.8
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4045.8
B
Correct answer
Explanation
After year 1: 20000 × 1.05 = 21000. After year 2: 21000 × 1.06 = 22260. After year 3: 22260 × 1.08 = 24040.8. CI = 24040.8 - 20000 = 4040.8. The amounts for each year are 1000, 1260, and 1780.8.
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Rs. 8000
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Rs. 27000
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Rs. 24000
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Rs. 35000
C
Correct answer
Explanation
First investment: Interest = P × R × T = 30000 × 0.12 × 2 = Rs. 7200. For second investment at 15% for 2 years to give same interest: P × 0.15 × 2 = 7200. Therefore P = 7200/0.30 = Rs. 24000. Option A (Rs. 8000) would give much less interest, Option B (Rs. 27000) gives more, and Option D (Rs. 35000) gives even more.
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Rs. 8854
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Rs. 6566
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Rs. 6656
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Rs. 7556
C
Correct answer
Explanation
The difference between CI for 3rd year and 2nd year is the interest on 2nd year's CI for one year: 1053 - 936 = 117. So 936 × r/100 = 117, giving r = 12.5%. CI for 1st year = 936/1.125 = 832. Total CI for 2 years = 832 + 936 = 1768. Principal P satisfies: P(1.125)² - P = 1768, so P = 1768/0.265625 = Rs. 6656.
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Rs. 22000
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Rs. 20000
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Rs. 18000
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Rs. 16000
C
Correct answer
Explanation
Let Rs x be from first bank at 10% and Rs(40000-x) from second bank at 12%. Total interest: 0.10x + 0.12(40000-x) = 4440. Solving: 0.10x + 4800 - 0.12x = 4440, so -0.02x = -360, giving x = 18000. This is a mixture problem using weighted interest rates.
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Rs.2256.18
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Rs.2019.38
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Rs.2421.09
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Rs.2615.08
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None of these
C
Correct answer
Explanation
Use CI formula: A = P(1 + r/100)^n - P. Here P=8400, r=13.5, n=2. A = 8400[(1.135)² - 1] = 8400[1.288225 - 1] = 8400 × 0.288225 = 2421.09. The compound interest after 2 years is Rs. 2421.09.