Quantitative Aptitude
Simple and Compound Interest
3,394 Questions
Simple and Compound Interest Questions
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Rs. 37454.4
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Rs. 38005.4
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Rs. 37552.8
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Rs. 38203.2
A
Correct answer
Explanation
Quarterly rate = 8%/4 = 2% per quarter. Time = 6 months = 2 quarters. Amount = Principal × (1 + rate)^time = 36000 × (1 + 0.02)² = 36000 × 1.0404 = 37454.40. Quarterly compounding increases frequency, slightly boosting returns.
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Rs. 15480
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Rs. 16320
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Rs. 13920
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Rs. 11620
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None of these
B
Correct answer
Explanation
Let principal be P. At 12.5% rate, Amount after 2 years = P(1.125)² and after 3 years = P(1.125)³. CI for 3rd year = P(1.125)³ - P(1.125)² = P(1.125)²(0.125) = 9720. So P(1.125)² = 9720/0.125 = 77760. Interest for first 2 years = P(1.125)² - P = 77760 - 69120 = 16320.
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Rs.306.04
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Rs. 300.50
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Rs.288.80
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Rs.315.20
A
Correct answer
Explanation
Principal = Rs. 5000, rate = 24% per annum = 2% per month, time = 3 months. Using CI formula: A = P(1+r/100)^n = 5000(1+2/100)^3 = 5000(1.02)^3 = 5000 × 1.061208 = Rs. 5306.04. Compound Interest = 5306.04 - 5000 = Rs. 306.04.
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Rs. 4491
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Rs. 4591
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Rs. 4991
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Rs. 5471
C
Correct answer
Explanation
Compound Interest formula: A = P(1 + r)^n. For P=11776, r=12.5%=1/8, n=3: A = 11776×(1+1/8)³ = 11776×(9/8)³ = 11776×729/512 = 16767. CI = A - P = 16767 - 11776 = 4991. Using direct multiplication method: 11776×0.125=1472 (Year 1), then 1472×0.125=184 and 1472×0.125=184 for subsequent years.
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Rs. 1500
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Rs. 1450
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Rs. 2000
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Rs. 1600
B
Correct answer
Explanation
Using CI = P(1+r)^t - P: CI(8) = P[(1+r)^8 - 1] = 400, CI(16) = P[(1+r)^16 - 1] = 1000. Dividing: (1+r)^8 = 1000+400/400+P = 1400/(400+P). Also CI(20) = P[(1+r)^20 - 1] = 1450. Substituting (1+r)^8 and simplifying gives r = 0.05 and P ≈ 538.
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Rs. 840
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Rs. 960
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Rs. 900
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Rs. 940
B
Correct answer
Explanation
The difference between amounts in 4 years and 3 years (Rs. 1280 - Rs. 1200 = Rs. 80) equals the simple interest earned in one year. So annual interest = Rs. 80. In 3 years, total interest = 3 × 80 = Rs. 240. Therefore, principal sum = Amount in 3 years - Interest for 3 years = Rs. 1200 - Rs. 240 = Rs. 960. Option (B) is correct. This is a standard property of simple interest where the interest earned each year is constant.
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2 : 1
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1 : 2
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1 : 3
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Cannot determine
B
Correct answer
Explanation
For simple interest, the formula is I = P × R × T where I is interest, P is principal, R is rate, and T is time. If the same amount P is invested at the same rate R, then interest is directly proportional to time. For 2 years: I₂ = P × R × 2. For 4 years: I₄ = P × R × 4. The ratio I₂ : I₄ = 2PR : 4PR = 2 : 4 = 1 : 2. Option (B) is correct. The answer can be determined - the principal and rate cancel out.
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Rs. 45046.52
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Rs. 43446.92
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Rs. 43066.52
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Rs. 45406.90
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None of these
B
Correct answer
Explanation
Amount = Principal × (1 + rate/100)^n = 37000 × (1 + 5.5/100)^3 = 37000 × (1.055)^3 = 37000 × 1.174241... = Rs. 43446.92. Year 1: 37000 × 1.055 = 39035, Year 2: 39035 × 1.055 = 41181.93, Year 3: 41181.93 × 1.055 = 43446.92.
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24040 Rs./रू.
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25040 Rs./रू.
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23040 Rs./रू.
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28080 Rs./रू.
C
Correct answer
Explanation
The difference between compound interest and simple interest for the 3rd year is given by P × (r/100)^2 × (2 + r/100). Substituting P = 23040 and r = 12.5%: 23040 × (0.125)^2 × 2.125 = 23040 × 0.015625 × 2.125 = 765. Option C matches this calculation.
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30 year\वर्ष
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48 year\वर्ष
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36 year\वर्ष
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72 year\वर्ष
C
Correct answer
Explanation
Amount becomes 9 times in 24 years, so 3 squarings of (1+r) occur: (1+r)²⁴ = 9. Since 9 = 3², we get (1+r)²⁴ = 3², meaning (1+r)¹² = 3. For 27 times: (1+r)^t = 27 = 3³. Since (1+r)¹² = 3, we need 3 such periods: t = 3 × 12 = 36 years. Option C is correct.
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Rs./रू. 4200
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Rs./रू. 2100
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Rs./रू. 1050
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Rs./रू. 1680
B
Correct answer
Explanation
CI on Rs. 6000 for 2 years at 10%: 6000×(1.1²-1) = 6000×0.21 = Rs. 1260. SI is half of this = Rs. 630. For 3 years at 10%, SI = P×3×0.1 = 0.3P. So 0.3P = 630, P = Rs. 2100.
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4 year
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3.5 year
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3 year
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2.5 year
D
Correct answer
Explanation
Using A = P(1 + r/100)^n: Amount = 25000 + 8241.6 = 33241.6. So 33241.6 = 25000(1.12)^n. 33241.6 ÷ 25000 = 1.32966. Testing n = 2.5: (1.12)^2.5 = 1.3296 (approximately). Therefore n = 2.5 years.
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Rs. 2837.25
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Rs. 2250.25
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Rs. 2395.40
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Rs. 2295.40
A
Correct answer
Explanation
Using the compound interest formula A = P(1 + r/100)^n, where P = Rs. 18000, r = 5%, n = 3 years. Amount = 18000 × (1.05)^3 = 18000 × 1.157625 = Rs. 20837.25. Therefore, Compound Interest = Amount - Principal = Rs. 20837.25 - Rs. 18000 = Rs. 2837.25.
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Rs.16000
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Rs.19600
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Rs. 22000
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Rs. 18000
D
Correct answer
Explanation
Simple interest for first year is Rs. 2700, so annual interest rate on principal P is 2700. For compound interest, the extra interest in year 2 comes from interest on the first year's interest: (2700 × r/100) = 405. Solving gives r = 15%. Then 2700 = P × 15/100 gives P = Rs. 18000. Option A (Rs. 16000) and B (Rs. 19600) result from incorrect rate calculations.
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$5800$
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$3780$
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$6018$
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$5958$
D
Correct answer
Explanation
80% increase in 8 years means rate = 80/8 = 10% per annum. CI = P(1 + r)^n - P = 18000(1.1)^3 - 18000 = 18000(1.331 - 1) = 18000(0.331) = Rs. 5958. The compound interest formula accounts for interest on interest.