Problems on Trains Questions

Multiple choice
  1. If statement I alone is sufficient but statement II alone is not sufficient.

  2. If statement II alone is sufficient but statement I alone is not sufficient.

  3. If each statement alone (either I or II) is sufficient.

  4. If statement I and II together are not sufficient.

  5. If both statement together are sufficient, but neither statement alone is sufficient.

Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Statement I gives length/time but not actual length or speed. Statement II gives bridge length and time but not train length. Neither alone is sufficient. Together: length = speed×30, and length+200 = speed×40. Solving gives speed = 20 m/s. Both needed, so E is correct.

Multiple choice
  1. 750 m/मी.

  2. 550 m/मी.

  3. 850 m/मी.

  4. 1250 m/मी.

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Speed = 72 km/h = 72 × 5/18 = 20 m/s. Time = 1 min 15 sec = 75 seconds. Distance covered = speed × time = 20 × 75 = 1500 m. This distance = train length + bridge length. So bridge length = 1500 - 650 = 850 m.

Multiple choice
  1. Any two

  2. I and II

  3. II and III

  4. All three together are sufficient

  5. None of these

Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Statement II gives length of train if we know speed. Statement III gives (train length + platform length) if we know speed. Statement I relates train and platform lengths. With all three: let train length = 2x, platform = 3x. From II: train crosses pole in 24s, so speed = 2x/24. From III: crosses platform in 60s, so (2x + 3x) = speed × 60, giving 5x = (2x/24) × 60, which solves. None of the partial combinations work.

Multiple choice
  1. 225 m/ मीटर

  2. 125 m/ मीटर

  3. 1225 m/ मीटर

  4. 250 m/ मीटर

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Relative speed of faster train with respect to man in slower train = 60 - 45 = 15 km/h = 15 × 5/18 = 25/6 m/s. Time taken to pass = 30 seconds. Length of faster train = Relative speed × Time = (25/6) × 30 = 125 m. The man in the slower train is stationary relative to that train, so only the relative speed matters. Option B matches this result.

Multiple choice
  1. 4 : 5

  2. 2 : 3

  3. 5 : 6

  4. Can't be determined/तय नहीं कर सकते

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let lengths be 2x and 3x. Speeds are 2x/4 and 3x/5. Ratio = (2x/4):(3x/5) = (1/2):(3/5) = 5:6. Option C is correct assuming the question means the trains cross the man (not platform).

Multiple choice
  1. 36 km/hr / किमी./ घंटा

  2. 54 km/hr / किमी./ घंटा

  3. 72 km/hr / किमी./ घंटा

  4. 48 km/hr / किमी./ घंटा

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The train's speed can be found by noting that in the additional 15 seconds (60-45), it travels the extra 300 meters of bridge length (900-600). This gives speed = 300/15 = 20 m/s. Converting to km/hr: 20 × 18/5 = 72 km/hr. Alternatively, total distance = 1500m in 105 seconds, giving the same result.

Multiple choice
  1. 150 m.

  2. 200 m.

  3. 300 m

  4. Can't be determine.

  5. None of these.

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Relative speed of fast train with respect to slow train = 90-60 = 30 km/hr = 30×5/18 = 25/3 m/s. In 18 seconds, distance covered = (25/3)×18 = 150 m. This is the length of the FAST train. The question asks for the length of the SLOWER train, which is not provided in the problem.

Multiple choice
  1. $Q1 > Q2$
  2. $Q1 \ge Q2$
  3. $Q1 < Q2$
  4. $Q1 \le Q2$
  5. $Q1 = Q2$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

For Q1: Speed = Distance/Time = 115/19 ≈ 6.05 m/s. For Q2: Total distance = Train length + Platform length = 152 + 100 = 252 m. Speed = 252/42 = 6 m/s. Therefore Q1 ≈ 6.05 m/s > Q2 = 6 m/s. The relationship Q1 > Q2 is correct.

Multiple choice
  1. 5 : 8

  2. 8 : 5

  3. 9 : 10

  4. 5 : 6

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Time to cross a pole = Length/Speed. If lengths are 3x, 4x and speeds are 5y, 6y, then times are (3x/5y) and (4x/6y) = (2x/3y). Ratio of times = (3x/5y) : (2x/3y) = 9:10.

Multiple choice
  1. 950 m

  2. 1150 m

  3. 1250 m

  4. 1050 m

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Speed = 72 km/h = 72 × (5/18) = 20 m/s. Time = 1 minute 25 seconds = 85 seconds. Total distance covered = speed × time = 20 × 85 = 1700 m. This distance equals train length + bridge length. So bridge length = 1700 - 550 = 1150 m. Standard train-distance problem.

Multiple choice
  1. 45 sec/सेकेण्ड

  2. 21 sec/सेकेण्ड

  3. 20 sec/सेकेण्ड

  4. 30 sec/सेकेण्ड

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Speeds are 7v and 3v. Lengths are both 12v from pole-crossing. Fast train crosses slow train: distance = sum of lengths = 24v, relative speed = 7v - 3v = 4v. Time = 24v/4v = 30 seconds. This uses the relative speed concept for objects moving in same direction.

Multiple choice
  1. 500 m/मी.

  2. 700 m/मी.

  3. 300 m/मी.

  4. 400 m/मी.

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let usual speed be v m/s and train length be L. At 87.5% speed (7v/8): L = (7v/8)×36 = 31.5v. At usual speed crossing 500m platform: L+500 = v×54 = 54v. Substituting: 31.5v + 500 = 54v, so 500 = 22.5v, v = 500/22.5 = 200/9 m/s. Then L = 31.5×(200/9) = 31.5×22.22 = 700m. The train length is 700 meters.