Problems on Trains Questions

Multiple choice
  1. 40 m./मी.

  2. 45 m./मी.

  3. 75 m./मी.

  4. 100 m./मी.

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

When a train passes a bridge, the distance covered equals the train's length plus the bridge's length. Using the two equations: (L + 400)/v = 50 and (L + 200)/v = 30, we divide them to eliminate speed and solve for L. This gives L = 100 meters. The speed works out to 10 m/s in both cases, confirming the answer.

Multiple choice
  1. 73.125 sec

  2. 83 sec

  3. 76.25 sec

  4. 40 sec

  5. None of these

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Train length = 180 m. Platform length = 3 × 180 = 540 m. Total distance to cross platform = 180 + 540 = 720 m. Time = 90 seconds. Speed = 720/90 = 8 m/s. Bridge length = (3/4) × 540 = 405 m. Distance to cross bridge = 180 + 405 = 585 m. Time = 585/8 = 73.125 seconds.

Multiple choice
  1. 238.5 m./ मी.

  2. 375 m./ मी.

  3. 328.5 m./ मी.

  4. 382.5 m./ मी.

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let train length be L meters and speed be S m/s. Crossing a pole: L = 18S. Crossing platform: L + 157.5 = 39S. Substituting L = 18S: 18S + 157.5 = 39S, so 21S = 157.5, giving S = 7.5 m/s and L = 135 m. Second train length = (135/2) + (2 × 157.5) = 67.5 + 315 = 382.5 m.

Multiple choice
  1. 45

  2. 54

  3. 50

  4. 65

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

When trains move in the same direction, their relative speed is the difference of their speeds: 46 - 36 = 10 km/h = 25/9 m/s. To completely pass the slower train, the faster train must cover the sum of both lengths (2L). Using distance = speed × time: 2L = (25/9) × 36 = 100 m. Therefore, each train is 50 m long. Option A (45 m) and B (54 m) are incorrect calculations. Option D (65 m) would require different speeds or time.

Multiple choice
  1. 270 metres/मीटर

  2. 340 metres/मीटर

  3. 180 metres/मीटर

  4. 160 metres/मीटर

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let train length be L. Time to cross pole = L/20 seconds. Time to cross platform = (L + 3L)/20 = 4L/20 = L/5 seconds. The difference: L/5 - L/20 = 24. Solving: (4L - L)/20 = 24, so 3L = 480, giving L = 160 metres. This is a standard train problem where crossing a pole requires covering the train's length, while crossing a platform requires covering train length plus platform length.

Multiple choice
  1. 800

  2. 600

  3. 400

  4. 100

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Speed = 60 km/h = 60 × 1000/3600 = 50/3 m/s. Time taken to cross platform = 30 seconds. Total distance covered = length of train + length of platform = Speed × Time = (50/3) × 30 = 500 meters. Given train length = 400m, so platform length = 500 - 400 = 100 meters. The key is understanding that 'crossing the platform' means covering the train's own length plus the platform's length, and converting units consistently (km/h to m/s).

Multiple choice
  1. 12.5 sec./से.

  2. 10 sec./से.

  3. 8 sec./से.

  4. 20 sec./से.

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Distance = length of train = 250 m. Speed = 90 km/hr = 90 × (5/18) = 25 m/s. Time = Distance/Speed = 250/25 = 10 seconds. To pass a standing man, the train must cover its own length. Therefore, option B is correct.

Multiple choice
  1. 15 sec./से.

  2. 6 sec./से.

  3. 9 sec./से.

  4. 18 sec./से.

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let train length be L. Platform length = 2L. Total distance to cross platform = L + 2L = 3L in 18 sec. Speed = 3L/18 = L/6 per sec. To cross pole (distance = L): time = L / (L/6) = 6 sec. Options A, C, D are incorrect.

Multiple choice
  1. 8 sec. / से.

  2. 9 sec. / से.

  3. 5 sec. / से.

  4. 6 sec. / से.

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Train speed = 82 km/hr, boy speed = 8 km/hr opposite direction. Relative speed = 82 + 8 = 90 km/hr = 90×(5/18) = 25 m/s. Time to cross = length/relative speed = 125/25 = 5 seconds.

Multiple choice
  1. 400

  2. 300

  3. 200

  4. 500

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let time taken to cross platform = t seconds. Speed = 2t km/hr = (2t × 5/18) m/s. Distance to cross platform = train length + platform length = 200 + L. Time = distance/speed, so 30 = (200 + L) / (2t × 5/18). But t = 30 seconds (given), so speed = 60 km/hr = 60 × 5/18 = 50/3 m/s. Distance = speed × time = (50/3) × 30 = 500m. So L = 500 - 200 = 300m. The key insight is that the numeric value of speed in km/hr equals the time in seconds.

Multiple choice
  1. 13 : 7

  2. 9 : 7

  3. 13 : 11

  4. 11 : 5

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let train lengths be L1 and L2, speeds be S1 and S2. A man standing still is crossed when the train passes its own length. So L1/S1 = 32 and L2/S2 = 20. Thus L1 = 32S1 and L2 = 20S2. When trains cross each other (opposite direction), relative speed is S1 + S2. Time = (L1 + L2)/(S1 + S2) = 42. Substituting: (32S1 + 20S2)/(S1 + S2) = 42. Solving: 32S1 + 20S2 = 42S1 + 42S2, giving 20S2 - 42S2 = 42S1 - 32S1, or -22S2 = 10S1, so S1/S2 = -22/10 = -11/5. Since speed is positive, S1:S2 = 11:5. The ratio is 11:5.

Multiple choice
  1. 100 m/मी.

  2. 120 m/मी.

  3. 140 m/मी.

  4. 160 m/मी.

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let train length = L and speed = v. Crossing a post: L = 8v. Crossing bridge: L + 200 = 24v. Substituting v = L/8 gives L + 200 = 3L, so 2L = 200 and L = 100m. The train travels its own length in 8 seconds.

Multiple choice
  1. 12 km./hr./किमी./घं.

  2. 24 km./hr./किमी./घं.

  3. 36 km./hr./किमी./घं.

  4. Data inadequate/डाटा अपर्याप्त

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The question states 'the speed of a train is 24 km/hr' but doesn't specify which train. Without knowing which train has this speed and whether they're moving in same or opposite directions, the second train's speed cannot be uniquely determined from given information.

Multiple choice
  1. 45 km./किमी.

  2. 40 km./किमी.

  3. 35 km./किमी.

  4. 42 km./किमी.

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Trains meet first at M after covering 180 km together. Speeds 5x and 4x, so distances are 100 km and 80 km respectively. Total distance for second meeting is 3×180 = 540 km (each reaches destination and turns back). Distance MN = (540/9) × 2 = 40 km. Option A incorrectly uses the first meeting distance.

Multiple choice
  1. 42.3

  2. 43.2

  3. 46.5

  4. 45.6

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let train length = L and speed = v. Crossing platform: (L+72)/v = 18. Crossing person: L/v = 12, so L = 12v. Substituting: (12v+72)/v = 18 → 12v+72 = 18v → 6v = 72 → v = 12 m/s. In km/hr: 12 × (18/5) = 43.2 km/hr.