Problems on Trains Questions

Multiple choice
  1. 3 : 2

  2. 3 : 4

  3. 4 : 3

  4. 2 : 3

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let length of train A = L, length of train B = 2L. Speed of A = L/25, Speed of B = 2L/75 = L/37.5. Ratio A:B = (L/25)/(L/37.5) = 37.5/25 = 3/2 = 3:2. Verify: If A=150m, B=300m, Speed A=6m/s, Speed B=4m/s, ratio=3:2.

Multiple choice
  1. 160

  2. 400

  3. 248

  4. 180

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Relative speed = 90 - 72 = 18 km/hr = 5 m/s. In 80 seconds, distance covered = 5 × 80 = 400m. This equals sum of both train lengths, so second train length = 400 - 240 = 160m.

Multiple choice
  1. 11 : 20

  2. 9 : 20

  3. 11 : 9

  4. 11 : 10

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Total distance = 200 km. They cross at 110 km from one station, so one train traveled 110 km and the other traveled 200 - 110 = 90 km in the same time. Speed ratio = Distance ratio = 110:90 = 11:9. This works because when two objects start simultaneously and travel for equal durations, their speeds are directly proportional to distances covered.

Multiple choice
  1. 12.8 km./hr.

  2. 14 km./hr.

  3. 16 km./hr.

  4. 16.8 km./hr.

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Total distance covered = sum of train lengths = 330 + 110 = 440 m = 0.44 km. Time = 55 seconds = 55/3600 hours. Relative speed = Distance/Time = 0.44/(55/3600) = 28.8 km/hr. Since trains move in opposite directions, relative speed = sum of individual speeds: 12 + v = 28.8, giving v = 16.8 km/hr.

Multiple choice
  1. 750 m./मी.

  2. 700 m./मी.

  3. 800 m./मी.

  4. 680 m./मी.

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Train speed = 72 km/h = 20 m/s. In 1 minute (60 seconds), distance covered = 20 × 60 = 1200 m. This distance equals tunnel length + train length. So train length = 1200 - 500 = 700 m. The train must completely exit the tunnel.

Multiple choice
  1. 42 km/h / किमी/घंटा

  2. 56 km/h / किमी/घंटा

  3. 46 km/h / किमी/घंटा

  4. 66 km/h / किमी/घंटा

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

When two trains cross in opposite directions, their relative speed is the sum of their individual speeds. Total distance to cover = sum of train lengths = 215 + 175 = 390 metres. Time taken = 18 seconds. Relative speed = 390/18 = 21.67 m/s. Converting to km/h: 21.67 × (18/5) = 78 km/h. Since the passenger train moves at 32 km/h in opposite direction, express train speed = 78 - 32 = 46 km/h.

Multiple choice
  1. 40 Km/h

  2. 36 Km/h

  3. 50 Km/h

  4. 45 Km/h

  5. 54 Km/h

Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

When the train crosses a pole in 15 seconds, it covers its own length L. When it crosses a 150m platform in 25 seconds, it covers L+150. The extra 10 seconds are for the 150m platform, so speed = 150÷10 = 15 m/s. Converting to km/h: 15 × 3.6 = 54 km/h. Options A (40), B (36), C (50), and D (45) are all incorrect conversions.

Multiple choice
  1. 100 km.hr./किमी./घण्टा

  2. 120 km.hr./किमी./घण्टा

  3. 140 km.hr./किमी./घण्टा

  4. 150 km.hr./किमी./घण्टा

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

When trains move in opposite directions, their relative speed is the sum of individual speeds. Distance covered = length of second train = 1000 m = 1 km. Time = 18 seconds = 18/3600 hours = 1/200 hours. Relative speed = Distance/Time = 1 ÷ (1/200) = 200 km/hr. Therefore, speed of second train = 200 - 80 = 120 km/hr.

Multiple choice
  1. 160 m/मी.

  2. 260 m/मी.

  3. 200 m/मी.

  4. 310 m/मी.

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let usual speed = v. At 50% speed (v/2), crossing pole takes 20s, so train length x = (v/2)*20 = 10v, giving v = x/10. At usual speed, crossing 300m platform takes 25s, so x+300 = v*25. Substituting v: x+300 = (x/10)*25, giving x+300 = 2.5x, so 300 = 1.5x, and x = 200m. The key insight is relating the two scenarios through the train's speed.

Multiple choice
  1. 45 km./hr.(किमी./घंटा)

  2. 48 km./hr.(किमी./घंटा)

  3. 52 km./hr.(किमी./घंटा)

  4. 54 km./hr.(किमी./घंटा)

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Train speed: (150+150)/30 = 10 m/s = 36 km/h. Relative speed when crossing opposite train: (150+150)/12 = 25 m/s. If second train's speed is x, then 36+x = 25×3.6 = 90 km/h. So x = 54 km/h. The key is understanding relative speed concept and unit conversion from m/s to km/h.

Multiple choice
  1. 45

  2. 24

  3. 36

  4. 40

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Train crosses a man in 10 seconds, so train length = speed × 10. Train crosses 50m platform in 14 seconds, so train length + 50 = speed × 14. Solving: speed × 14 - speed × 10 = 50, so speed × 4 = 50, giving speed = 12.5 m/s. Converting to km/h: 12.5 × 18/5 = 45 km/h.

Multiple choice
  1. 200 m./मी.

  2. 300 m./मी.

  3. 350 m./मी.

  4. 400 m./मी.

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let first train length = L. Second train length = 2L. Relative speed = 96+84 = 180 kmph = 50 m/s. In 24 seconds, they cover L+2L = 3L, so 3L = 50×24 = 1200, giving L = 400m. Let platform length = P. Train covers L+P in 45 seconds at 96 kmph = 80/3 m/s. So 400+P = (80/3)×45 = 1200, giving P = 350m.

Multiple choice
  1. 8 m/s.

  2. 10 m/s.

  3. 12 m/s.

  4. 15 m/s

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Train speed = 72 km/h = 72×(5/18) = 20 m/s. Total distance in 23s = 20×23 = 460m. Platform length = 460 - 280 = 180m. Man's speed = 180/15 = 12 m/s. The problem has calculation inconsistency in the options - actual answer should be 12 m/s, which matches option C.

Multiple choice
  1. 132 metre/मीटर

  2. 143 metre/मीटर

  3. 165 metre/मीटर

  4. 150 metre/मीटर

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let train length = L meters and speed = v m/s. Crossing a pole: L = v × 12, so v = L/12. Crossing a 198m tunnel: L + 198 = v × 30. Substituting v: L + 198 = (L/12) × 30 = 2.5L. So 198 = 1.5L, giving L = 198/1.5 = 132 meters. Verification: Speed = 132/12 = 11 m/s. Time for tunnel = (132 + 198)/11 = 330/11 = 30 seconds, which matches.