Problems on Trains Questions

Multiple choice
  1. 16 sec.

  2. 12 sec.

  3. 10 sec.

  4. 15 sec.

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The train length is 220 m and its speed is 62 km/hr. The man runs opposite to the train at 4 km/hr. Relative speed = 62 + 4 = 66 km/hr = (66 × 5/18) m/s = 55/3 m/s. Time = Distance/Speed = 220 ÷ (55/3) = 220 × 3/55 = 12 seconds. Since the man starts from the engine and runs opposite to the train, he needs to cover the entire train length.

Multiple choice
  1. 125 km/hr.

  2. 132 km/hr.

  3. 168 km/hr.

  4. 172 km/hr.

  5. None of these

Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Total distance = 150 + 150 = 300 m. Relative speed = 300/12 = 25 m/s = 90 km/hr. Let slower train speed = v, then faster = 2.5v. So v + 2.5v = 3.5v = 90 km/hr. Therefore v = 90/3.5 ≈ 25.7 km/hr and faster train = 2.5 × 25.7 ≈ 64.3 km/hr. None of the given options (125, 132, 168, 172) match this result.

Multiple choice
  1. 16.8

  2. 15.5

  3. 14.2

  4. 17.1

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

First find the train's speed: when crossing the man, relative speed = (train speed + 8 km/h) = 135/9 = 15 m/s = 54 km/h. So train speed = 54 - 8 = 46 km/h. When crossing the other train, relative speed = 46 + 14 = 60 km/h = 60 × 5/18 = 50/3 m/s. Time = (135 + 150)/(50/3) = 285 × 3/50 = 17.1 seconds.

Multiple choice
  1. All three together are sufficient

  2. II and III together

  3. I and III together

  4. All three together are not sufficient

  5. None of these

Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

From Statement I and III: Length = 300m, crosses pole in 18s. Speed = 300/18 = 50/3 m/s. From II and III: Platform length = 2*train length. Crosses in 54s, so 3*length = speed*54. Also crosses pole in 18s, so length = speed*18. Solving: 3*18*speed = 54*speed, consistent. Speed = 50/3 m/s. Both (I,III) and (II,III) work, so E is correct.

Multiple choice
  1. 38.88

  2. 35.56

  3. 48.56

  4. 32.35

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

ट्रेन की चाल = 80 किमी/घंटा = 80×5/18 = 22.22 मीटर/सेकंड। साइकिल सवार की चाल = 12 किमी/घंटा = 12×5/18 = 3.33 मीटर/सेकंड। सापेक्ष चाल (समान दिशा) = 22.22 - 3.33 = 18.89 मीटर/सेकंड। ट्रेन की लंबाई = 18.89 × 5 = 94.45 मीटर (गलत दृष्टिकोण)। सही विधि: प्लेटफार्म पार करने में: ट्रेन की लंबाई + प्लेटफार्म की लंबाई = 22.22 × 6 = 133.32 मीटर। साइकिल सवार को पार करने में: ट्रेन की लंबाई = (22.22 - 3.33) × 5 = 94.45 मीटर। प्लेटफार्म की लंबाई = 133.32 - 94.45 = 38.87 ≈ 38.88 मीटर। विकल्प A सही है।

Multiple choice
  1. Quantity I > Quantity II

  2. Quantity I ≥ Quantity II

  3. Quantity II > Quantity I

  4. Quantity II ≥ Quantity I

  5. Quantity I = Quantity II or Relation cannot be established

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Quantity I: Train crosses pole in 18 sec, so length L = 18 × speed. Crosses 210 m platform in 39 sec, so L+210 = 39 × speed. Subtracting: 210 = 21 × speed, so speed = 10 m/s. Therefore L = 18 × 10 = 180 m. Quantity II: 200 m train crosses pole in 20 sec, so speed = 10 m/s. Platform length P satisfies 200+P = 46 × 10 = 460, so P = 260 m. Comparing: 180 < 260, so Quantity II > Quantity I.

Multiple choice
  1. 18

  2. 27

  3. 24

  4. 20

  5. None of these

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let lengths be LA and LB. LA + LB = 696. Time = length/speed, so LA/SA : LB/SB = 5:4. Given SA:SB = 6:7, then LA:LB = 15:14. So LA = 360m, LB = 336m. Difference = 24m. Option C matches.

Multiple choice
  1. 28 seconds

  2. 20 seconds

  3. 24 seconds

  4. 32 seconds

  5. None of these

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let longer train length = L, shorter = S, speeds = Vl, Vs. Opposite direction: (L+S)/(Vl+Vs) = 10. Same direction: (L+S)/(Vl-Vs) = 30. Reduced length: (0.25L+S)/(Vl-Vs) = 18. Also L - S = 50. From first two equations: 10(Vl+Vs) = 30(Vl-Vs), so Vl = 2Vs. Using this and the equations, we find Vs = 25, Vl = 50, L = 400. Tunnel length = 2L = 800, crossing time = (L+2L)/Vl = 3L/Vl = 1200/50 = 24 seconds.

Multiple choice
  1. Only A and B together

  2. Only B and C together

  3. Only A and C together

  4. Questions can’t be answered even after using all the information

  5. None of these

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

We have ratios (length and speed) and individual train speeds, but never the total distance covered while crossing. We need either: (relative speed × time) = sum of lengths, or a specific length value. Neither is provided. Even with all statements, we cannot find the lengths.

Multiple choice
  1. Quantity I > Quantity II

  2. Quantity I ≥ Quantity II

  3. Quantity II > Quantity I

  4. Quantity II ≥ Quantity I

  5. Quantity I = Quantity II or Relation cannot be established

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Quantity I: Train speed = 210÷(39-18) = 10 m/s. Length = 10×18 = 170 m. Quantity II: Train speed = 200÷20 = 10 m/s. Platform length = 10×46 - 200 = 260 m. 260 > 170, so Quantity II is greater.

Multiple choice
  1. Quantity I > Quantity II

  2. Quantity I ≥ Quantity II

  3. Quantity II > Quantity I

  4. Quantity II ≥ Quantity I

  5. Quantity I = Quantity II or Relation cannot be established

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Quantity I: B takes 6 days for 3/5 work, so B's rate = (3/5)/6 = 1/10 per day. B takes 10 days alone. A + B together take 5 days for 3/4 work, so combined rate = (3/4)/5 = 3/20 per day. A's rate = 3/20 - 1/10 = 1/20 per day. A takes 20 days alone. For 1/5 work: time = (1/5)/(1/20) = 20/5 = 4 days. Quantity II: Train crosses a pole (its own length) in 2.5 hours at 60 km/hr. So train length = 60 × 2.5 = 150 km. Wait - that's very long for a train. Let me reconsider: crossing time = length/speed, so length = speed × time = 60 × 2.5 = 150 km. To cross a 60 km platform: distance = 150 + 60 = 210 km. Time = 210/60 = 3.5 hours. Comparing: Quantity I = 4 days, Quantity II = 3.5 hours. 4 days > 3.5 hours, so Quantity I is greater.

Multiple choice
  1. 9 seconds/सेकेण्ड

  2. 3 seconds/सेकेण्ड

  3. 18 seconds/सेकेण्ड

  4. 12 seconds/सेकेण्ड

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let speeds be 3x and 4x. From crossing telegraph posts in 9 seconds, lengths are 27x and 36x respectively. When crossing each other in opposite directions, relative speed = 3x + 4x = 7x. Total distance = 27x + 36x = 63x. Time = distance/speed = 63x/7x = 9 seconds.

Multiple choice
  1. 30 seconds/सेकेण्ड

  2. 36 seconds/सेकेण्ड

  3. 48 seconds/सेकेण्ड

  4. 42 seconds/सेकेण्ड

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Relative speed = 65 - 5 = 60 km/hr = 60 × (5/18) = 50/3 m/s. Time = distance/speed = 800 ÷ (50/3) = 800 × 3/50 = 48 seconds.

Multiple choice
  1. 70 km

  2. 56 km

  3. 23 km

  4. 78 km

  5. 85 km

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let distance = d km. At 40 kmph, time = d/40 hours. At 35 kmph, time = d/35 hours. The difference is 15 minutes = 15/60 = 1/4 hours. So d/35 - d/40 = 1/4. d(1/35 - 1/40) = 1/4. d(40 - 35)/(35 × 40) = 1/4. d(5)/(1400) = 1/4. d/280 = 1/4. Therefore d = 280/4 = 70 km.

Multiple choice
  1. 9 seconds

  2. 18 seconds

  3. 13 seconds

  4. 27 seconds

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

When a train overtakes a person moving in the same direction, use relative speed. The train's speed minus the person's speed gives relative speed: 20 - 10 = 10 m/s. The train must cover its own length (180m) at this relative speed. Time = Distance / Speed = 180 / 10 = 18 seconds. Option A (9s) would be the result if you used 20 m/s without subtracting the man's speed. Option D (27s) might come from adding the speeds incorrectly.