Problems on Trains Questions

Multiple choice
  1. 50 meter/मीटर

  2. 150 meter/मीटर

  3. 100 meter/मीटर

  4. 240 meter/मीटर

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

When trains move in same direction, relative speed = 70 - 40 = 30 km/hr. Converting to m/s: 30 × (5/18) = 25/3 m/s. Distance covered in 12 seconds = (25/3) × 12 = 100 meters. This distance equals the length of the fast train.

Multiple choice
  1. 60

  2. 72

  3. 78

  4. 84

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Total distance = 175 + 125 = 300 m covered in 10 seconds. Relative speed = 300/10 = 30 m/s. First train: 30 km/hr = 30 × 5/18 = 25/3 m/s. Second train speed: 30 - 25/3 = 65/3 m/s = 65/3 × 18/5 = 78 km/hr. Option C is correct.

Multiple choice
  1. 10 sec.

  2. 8 sec.

  3. 12 sec.

  4. 14 sec.

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

When trains move in opposite directions, their relative speed is the sum: 36 + 54 = 90 km/h. Convert to m/s: 90 × (5/18) = 25 m/s. Total distance to cross = sum of lengths = 132 + 118 = 250 m. Time = Distance / Speed = 250/25 = 10 seconds. The 8 second option would be correct if trains were moving in the same direction.

Multiple choice
  1. 5.6 second

  2. 7.2 second

  3. 8 second

  4. 9 second

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

When trains move toward each other, add their speeds to get relative speed: 80 + 55 = 135 km/h = 135 × 5/18 = 37.5 m/s. Total distance to cross = sum of train lengths + initial gap = 120 + 90 + 90 = 300 m. Time = distance/speed = 300/37.5 = 8 seconds. Option A (5.6s) forgets to add train lengths; Option B (7.2s) uses wrong speed conversion; Option D (9s) miscalculates the distance.

Multiple choice
  1. 2

  2. 6

  3. 12

  4. 8

  5. None of these

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Distance to cross platform = Train length + Platform length. At 21 m/s for 19 seconds, total distance = 21 × 19 = 399 m. Platform length = 399 - 216 = 183 m. After adding n boxes of 21 m each, new train length = 216 + 21n. Total distance = (216 + 21n) + 183 = 399 + 21n. At same speed for 27 seconds: 21 × 27 = 567 = 399 + 21n. Therefore 21n = 168 and n = 8 boxes.

Multiple choice
  1. 36 minutes/मिनट

  2. 30 minutes/मिनट

  3. 28 minutes/मिनट

  4. 24 minutes/मिनट

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

When trains move in the same direction, relative speed is the difference of their speeds: 40 - 35 = 5 km/hr = 25/18 m/s. The total distance to cover is the sum of both train lengths: 1100 + 900 = 2000 m. Time = Distance/Relative Speed = 2000/(25/18) = 1440 seconds = 24 minutes. The distractor of 36 minutes would result from incorrectly adding the speeds instead of subtracting.

Multiple choice
  1. 12 seconds/ सेकेण्ड

  2. 15 seconds/ सेकेण्ड

  3. 13 seconds/ सेकेण्ड

  4. 11 seconds/ सेकेण्ड

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Total distance = 300 + 360 = 660 m. Relative speed when opposite = 100 + 116 = 216 km/hr = 216×(5/18) = 60 m/s. Time = 660/60 = 11 seconds. Options A, B, C are arithmetic errors in unit conversion or calculation.

Multiple choice
  1. 9 hr 30 min

  2. 10 hr 30 min

  3. 10 hr 10 min

  4. 10 hr 40 min

  5. None of these

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Speed = distance/time = 595m/17s = 35 m/s. Distance = 1197 km = 1,197,000 m. Travel time = 1,197,000/35 = 34,200 seconds = 570 minutes = 9 hours 30 minutes. Halts = 5 × 8 = 40 minutes. Total = 9h 30min + 40min = 10h 10min. This matches option C.

Multiple choice
  1. 48 seconds/सेकेंड

  2. 36 seconds/सेकेंड

  3. 40 seconds/सेकेंड

  4. 46 seconds/सेकेंड

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Total distance = train length + bridge length = 120 + 360 = 480 m. Speed = 36 km/h = 36×5/18 = 10 m/s. Time = 480/10 = 48 seconds.

Multiple choice
  1. I and either II or III

  2. I and II

  3. III and either I or II

  4. II and III

  5. only I

Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

From Statement I: Train A travels from 6:00 AM to 12:20 PM (6h 20m = 19/3 hours). Train B travels from 7:30 AM to 3:06 PM (7h 36m = 19/3 hours). Both take the same time, so if speeds are v_A and v_B with distance d, then d/v_A = d/v_B, meaning v_A = v_B. When both move toward each other starting at 7:30 AM, relative speed = 2v and they meet when combined distance = d, which happens at time t such that 2vt = d. Since d = v × 19/3, meeting time = 19/6 hours after 7:30 AM. Statement I alone is sufficient.

Multiple choice
  1. I and (II or III) together

  2. I alone

  3. I and II together

  4. II and III together

  5. Even all I, II, and III are not sufficient

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

From Statement I: Crossing pole in 15 sec gives L = 15v, and crossing platform in 35 sec gives L + p = 35v. This alone is insufficient (2 equations, 3 unknowns). With Statement II (speed = 70 kmph): convert to m/s, use L = 15v to find length. With Statement III (p = 400 m): substitute into L + 400 = 35v and L = 15v, solve to get L = 300 m. Thus I + (II or III) is sufficient.

Multiple choice
  1. Any two

  2. I and II

  3. I and II or III

  4. Only I

  5. None of these

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Statement I alone is sufficient: train length 270m, bird speed 9 kmph (2.5 m/s) opposite direction, time 12 sec. Relative speed = 270/12 = 22.5 m/s. Since opposite direction, train speed = 22.5 - 2.5 = 20 m/s = 72 km/h. Statement II requires unknown direction/speed of other train. Statement III only gives second train's speed without context about first train.

Multiple choice
  1. 40 km/hrs.

  2. 30 km/hrs.

  3. 45 km/hrs.

  4. 55 km/hrs.

  5. None of these

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Relative speed = (200 + 150)/18 = 350/18 m/s. Rajdhani speed = 25 km/hr = 25×5/18 = 125/18 m/s. Let passenger train speed = v. Then 125/18 + v = 350/18. Solving: v = 225/18 m/s = 225/18 × 18/5 = 45 km/hr.