Quantitative Aptitude
Time and Work
2,195 Questions
Time and Work Questions
C
Correct answer
Explanation
Let e be one employee's daily work and t be one trainee's daily work. From first condition: 2e + 3t = 1/7. From second condition: 6e + 13t = 1/2. Subtracting 3×(first equation) from second: 4t = 1/2 - 3/7 = 1/14, so t = 1/56. Then 2e = 1/7 - 3/56 = 5/56, so e = 5/112. For 4 employees and 4 trainees: daily work = 4×(5/112) + 4×(1/56) = 20/112 + 4/56 = 20/112 + 8/112 = 28/112 = 1/4. Therefore 4 days needed.
D
Correct answer
Explanation
Work rates: A = 1/6 per day, B = 1/8 per day. Combined A+B+C = 1/3 per day. So C's rate = 1/3 - 1/6 - 1/8 = 1/24 per day. Wages are distributed in ratio of work rates. C's share = (1/24)/(1/3) × 1848 = (1/8) × 1848 = ₹231. Option D is correct.
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24 days
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36 days
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18 days
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9 days
C
Correct answer
Explanation
A and B together take 6 days, so their combined rate is 1/6 work per day. A works 2 days and completes 25% (1/4) of the job, so A's rate is (1/4)÷2 = 1/8 work per day. B's rate = 1/6 - 1/8 = 1/24 work per day. Remaining work = 3/4. Time for B = (3/4)÷(1/24) = 18 days.
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12 days
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6 days
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18 days
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24 days
A
Correct answer
Explanation
N's speed is half of T's speed. Let T's rate = 2x letters/day, N's rate = x letters/day. Combined rate = 3x letters/day. Together for 12 days: 36x letters completed. Remaining: 2000 - 36x letters. N works alone at rate x: time = (2000 - 36x)/x = 2000/x - 36 days. Total time = 12 + 2000/x - 36 = 2000/x - 24 days. Normal time at combined rate: 2000/(3x) days. Delay = (2000/x - 24) - (2000/(3x)) = (4000/(3x) - 24). From 18 days together at rate 3x: 54x = 2000, x = 1000/27. Delay = 4000/(3×1000/27) - 24 = 36 - 24 = 12 days.
B
Correct answer
Explanation
Since P is 4 times as efficient as Q, P takes 1/4 the time Q takes. Let Q take x days, then P takes x/4 days. Given P takes 45 days less: x - x/4 = 45, so 3x/4 = 45, x = 60. Q takes 60 days, P takes 15 days. Combined rate: 1/60 + 1/15 = 1/60 + 4/60 = 5/60 = 1/12. Together they complete the work in 12 days.
D
Correct answer
Explanation
A's rate is 1/20, B's rate is 1/25, and they work together for x days before C joins. C works for (10-x) days. The equation is x(1/20+1/25)+(10-x)(1/20+1/25+1/C)=1. Also x(1/20+1/25)=0.45 (work done before C joined). Solving gives x=5 and C's share proportion to 0.5/10 = 0.05. C's share = 0.05/0.1 * 700 = Rs. 70.
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$15 : 4$
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$6 : 5$
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$4 : 5$
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$5 : 4$
C
Correct answer
Explanation
A's daily wage = 40 × 12 = 480. B's daily wage = 60 × 10 = 600. The ratio A:B = 480:600 = 48:60 = 4:5 after dividing both by 12. So the ratio of their per day wages is 4:5.
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15 days
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16.5 days
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15.5 days
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17 days
B
Correct answer
Explanation
Work pattern repeats every 3 days: Day1(Arun)=1/10, Day2(Rahul)=1/20, Day3(Deepak)=1/40. Combined 3-day work = 1/10+1/20+1/40 = 4/40+2/40+1/40=7/40. After 15 days (5 cycles): 35/40 done. Day16 (Arun): 35/40+1/10=39/40. Day16.5 (Rahul half day): 39/40+1/40=40/40=1 complete.
A
Correct answer
Explanation
Let S, V, M be the rates of work per day. S+V = 1/12, M+S = 1/16, M+V = 1/24. Adding all three equations: 2(S+V+M) = 1/12 + 1/16 + 1/24 = (4+3+2)/48 = 9/48 = 3/16. Therefore S+V+M = 3/32. Time taken together = 32/3 days.
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25
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22
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28
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30
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None of these
D
Correct answer
Explanation
Ram's work rate: 1/15 per day. In 5 days, he completes 5 × (1/15) = 1/3 of the work. Remaining work = 2/3. Mohan completes 2/3 work in 20 days, so his rate is (2/3)/20 = 1/30 per day. Therefore, Mohan alone would take 30 days.
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21
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20
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24
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25
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None of these
C
Correct answer
Explanation
Let total work = LCM(36, 72, 54) = 216 units. A's rate = 6/day, B's rate = 3/day, C's rate = 4/day. A worked for (d-8) days, C worked for (d-12) days, B worked for all d days. So 6(d-8) + 3d + 4(d-12) = 216. Solving: 6d - 48 + 3d + 4d - 48 = 216, so 13d = 312, giving d = 24 days.
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12 days
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10 days
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16 days
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24 days
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None of these
C
Correct answer
Explanation
Let total work = 120 units (LCM of 20, 30, 40). A+B rate = 6/day, A+C rate = 4/day, C rate = 3/day. So A's rate = 3/day, B's rate = 3/day. All three together: 3+3+3 = 9/day. In 8 days, they complete 72 units. Remaining = 48 units. C alone at 3/day needs 16 days. The key is finding individual rates from combined rates.
C
Correct answer
Explanation
A's 1-day work = 1/40, B's 1-day work = 1/45. Total work: y/40 + (y+0.625)/45 = 1/4. Solving gives y = 5. This is a standard work equation where rates add and time multiplies.
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42
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45
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48
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50
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None of these
C
Correct answer
Explanation
A's work rate is 1/30 per day. In 4 days, A completes 4/30 work, leaving 26/30. A and B together complete the remaining 26/30 in 16 days, so (1/30 + 1/B) × 16 = 26/30. This gives 1/B = (26/30 - 16/30) / 16 = 10/480 = 1/48. Therefore B alone takes 48 days.
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27 days
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36 days
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32 days
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40 days
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None of These
B
Correct answer
Explanation
P's efficiency = 1/21 work per day. Q is 25% less efficient, so Q's efficiency = 0.75 × 1/21 = 3/84 = 1/28. Q worked for 7 days: 7/28 = 1/4 work done. Remaining work = 3/4, completed by R in 27 days. R's rate = (3/4)/27 = 1/36. So R alone takes 36 days.