Quantitative Aptitude
Time and Work
2,195 Questions
Time and Work Questions
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6 days
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3 days
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5 days
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4 days
B
Correct answer
Explanation
Work rates: A = 1/4, B = 1/12, C = 1/6 per day. Pattern: A works alone days 1-2, A+B+C work day 3. Each 3-day cycle: 2(1/4) + (1/4 + 1/12 + 1/6) = 5/6. After 2 cycles (6 days): 5/6 done. Day 7: A alone completes remaining 1/6. Option A (6 days) misses the final day.
D
Correct answer
Explanation
In 60 days, 20 men complete 60/80 = 3/4 of the work. Remaining 1/4 work must be done in 10 days by adding m men. Work rate equation: (20+m) × 10 = (1/4) × 20 × 80 = 400 man-days. Solving: 200 + 10m = 400, giving m = 20. So 20 additional men are needed to complete the remaining work in the stipulated time.
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18 days
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19 days
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20 days
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21 days
B
Correct answer
Explanation
M's rate = 1/25, N's rate = 1/30. Combined rate = 1/25 + 1/30 = 11/150. In 5 days, they complete 5*(11/150) = 11/30 of work. Remaining = 19/30. N alone needs (19/30)/(1/30) = 19 days. The key is finding individual work rates and tracking remaining work.
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6 days
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5 days
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8 days
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9 days
A
Correct answer
Explanation
Combined rate of A, B, C = (1/12 + 1/18 + 1/36) = (3+2+1)/36 = 6/36 = 1/6. In 2 days, they complete 2×(1/6) = 1/3 of work. Remaining work = 1 - 1/3 = 2/3. After B quits, A + C rate = (1/12 + 1/36) = (3+1)/36 = 4/36 = 1/9. Time needed = (2/3) ÷ (1/9) = (2/3)×9 = 6 days.
A
Correct answer
Explanation
LCM of 20, 24, 30 is 120 units. A's rate=6 units/day, B's rate=5 units/day, C's rate=4 units/day. First 4 days: all work together at 15 units/day → 60 units done. Remaining 60 units done by A+C at 10 units/day → 6 more days. The question asks total time, which is 4+6=10 days. Option A is correct.
D
Correct answer
Explanation
Let efficiencies be 4k, 5k, 3k for A,B,C. Combined efficiency = 12k units/day. In 25 days, total work = 25×12k = 300k units. A and C together have efficiency 7k units/day. To complete 35% of work = 0.35×300k = 105k units, they need 105k/(7k) = 15 days.
C
Correct answer
Explanation
C is 5 times as efficient as B, so C's work rate is 5 times B's rate. If B alone takes x days, B's rate is 1/x and C's rate is 5/x. A takes 60 days (rate 1/60). Together: 1/60 + 1/x + 5/x = 1/12. Solving: 1/60 + 6/x = 1/12, so 6/x = 1/12 - 1/60 = 4/60 = 1/15, giving x = 90.
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$174.5 days$
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$194.5 days$
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$116 days$
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$174 days$
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None of these
B
Correct answer
Explanation
4 men complete work in 58 days, so total work = 4 × 58 = 232 man-days. Women have 25% efficiency, so 1 woman = 0.25 man. Every 5 days, 1 man is replaced by 1 woman. Days 1-5: 4M → 20 work. Days 6-10: 3M+1W → 5×3.25 = 16.25. Days 11-15: 2M+2W → 5×2.5 = 12.5. Days 16-20: 1M+3W → 5×1.75 = 8.75. Days 21+: 4W → 5×1 = 5 per cycle. After 20 days: 57.5 work done. Remaining: 174.5. At 5 per 5-day cycle: 34.95 × 5 = 174.75. Total: 20 + 174.75 = 194.75 ≈ 194.5.
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35 days
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40 days
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45 days
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50 days
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54 days
E
Correct answer
Explanation
माना विकाश की दक्षता 1, तो अमन की दक्षता 3। विकाश को 1 काम पूरा करने में 54 दिन लगेंगे। अमन 6 दिन काम करता है = 18 इकाई काम। विकाश 9 दिन काम करता है = 9 इकाई काम। कुल 27 इकाई = 50% काम, तो पूरा काम = 54 इकाई। विकाश अकेला 54 दिन में पूरा करेगा। विकल्प E सही है।
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12
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14
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15
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16
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None of these
D
Correct answer
Explanation
Set up equations: Let m and b be work done by one man and one boy per day. From (12m + 16b) × 20 = (52m + 96b) × 4, we get m = 2b. Total work = 800b. For 15 men + 20 boys = 50b, days = 800b ÷ 50b = 16 days. The key is finding the relationship between men's and boys' work capacity.
A
Correct answer
Explanation
Let total work be 60 units. A's rate = 5 units/day, B's rate = 4 units/day. B leaves 3 days before completion, so A works alone for 3 days, completing 15 units. Remaining 45 units done together at 9 units/day = 5 days. Total = 5 + 3 = 8 days.
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5 days
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6 days
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2 days
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8 days
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None of these
E
Correct answer
Explanation
Calculate A's rate = 1/15 per day and B's rate = 1/25 per day. Together they do 8/75 per day. In first 5 days (A+B): 5 × 8/75 = 8/15 work done. Next 5 days (B alone): 5 × 1/25 = 1/5 = 3/15 work done. Total done = 11/15, remaining = 4/15. A alone needs: (4/15) ÷ (1/15) = 4 days. Since 4 is not among options A-D, option E (None of these) is correct.
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34 days
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32 days
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54 days
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52 days
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None of these
C
Correct answer
Explanation
A completes 1/3 of work in 30 days, so A's full work time = 30 × 3 = 90 days, rate = 1/90 per day. B completes remaining 2/3 work in 90 days, so B's full work time = 90 × 3/2 = 135 days, rate = 1/135 per day. Combined rate = 1/90 + 1/135 = 3/270 + 2/270 = 5/270 = 1/54. Together they complete the work in 54 days.
C
Correct answer
Explanation
Let B's efficiency be 100 units/day. Then A's efficiency is 150 (50% more) and C's efficiency is 60 (40% less). Combined efficiency = 150+100+60=310 units/day. Total work = 310×10=3100 units. A alone does 150% of 3100 = 4650 units. At 150 units/day, A needs 4650/150=31 days. If A took 35 days, efficiency would need to be about 133 units/day, not 150.
C
Correct answer
Explanation
A's work rate is 1/48 per day. Combined rate is 1/36 per day, so B's rate is 1/36 - 1/48 = 1/144 per day. Let A leave x days before completion. Then (A+B) work together for (54-x) days at rate 1/36, and B works alone for x days at rate 1/144. Setting (54-x)/36 + x/144 = 1 gives 216 - 3x = 144, so x = 24 days.