4 Men can complete a piece of work in 58 days. They started the work together but at the end of every 5th day one man leaves the work and in the place of the man, one woman joins the work and the women continue doing the work and finish it despite all the men left in the mid of the work. Find the total number of days they take to complete the work in this manner if the efficiency of one women is 25% of the efficiency of one man.

4 men complete work in 58 days, so total work = 4 × 58 = 232 man-days. Women have 25% efficiency, so 1 woman = 0.25 man. Every 5 days, 1 man is replaced by 1 woman. Days 1-5: 4M → 20 work. Days 6-10: 3M+1W → 5×3.25 = 16.25. Days 11-15: 2M+2W → 5×2.5 = 12.5. Days 16-20: 1M+3W → 5×1.75 = 8.75. Days 21+: 4W → 5×1 = 5 per cycle. After 20 days: 57.5 work done. Remaining: 174.5. At 5 per 5-day cycle: 34.95 × 5 = 174.75. Total: 20 + 174.75 = 194.75 ≈ 194.5.