Time and Work Questions

Multiple choice
  1. 27

  2. 9

  3. 17

  4. 25

  5. 26

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Adolf's rate is 1/15, Beggie's is 1/25. In 6 days, they do 6(1/15 + 1/25) = 6(5/75 + 3/75) = 6(8/75) = 48/75 = 16/25 of the work. Remaining work is 9/25. Beggie finishes this in (9/25) / (1/25) = 9 days.

Multiple choice
  1. 8 days

  2. 10 days

  3. 13 days

  4. 12 days

  5. None of these

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let Rajavi take R days. Selena takes R-6 days. Together: 1/R + 1/(R-6) = 1/4. Solving: (R-6+R)/(R(R-6)) = 1/4, so 4(2R-6) = R^2-6R, 8R-24 = R^2-6R, R^2-14R+24 = 0. (R-12)(R-2) = 0. Since R must be greater than 6, R = 12.

Multiple choice
  1. 300%

  2. 400%

  3. 500%

  4. 250%

  5. 600%

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Initial rate = 2000/10 = 200 questions/day. After 6 days, 1200 questions are done, leaving 800. To finish 800 in 1 day, the new rate must be 800 questions/day. The increase is (800 - 200) / 200 = 600 / 200 = 300%.

Multiple choice
  1. Rs. 200

  2. Rs. 300

  3. Rs. 100

  4. Rs. 400

  5. None of these

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Work rates: Ram = 1/16, Sandhu = 1/24. Together = 1/16 + 1/24 = 5/48. With Sunita, rate = 1/8. Sunita's rate = 1/8 - 5/48 = 1/48. Total work is shared in ratio of rates: 1/16 : 1/24 : 1/48 = 6 : 4 : 2 = 3 : 2 : 1. Ram's share = (3/6) * 600 = 300.

Multiple choice
  1. 25/2 days

  2. 128/9 days

  3. 15 days

  4. 50/3 days

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

A's rate = 1/25, B's rate = 1/20. In 10 days, A completes 10/25 = 2/5 of the work. Remaining work = 3/5. Combined rate = 1/25 + 1/20 = 9/100. Time for remaining work = (3/5) / (9/100) = (3/5) * (100/9) = 20/3 days. Total time = 10 + 20/3 = 50/3 days.

Multiple choice
  1. 10 days

  2. 12 days

  3. 15 days

  4. 18 days

  5. None of these

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let M and W be the work done by one man and one woman per day. 20(6M + 8W) = 10(8M + 22W). 120M + 160W = 80M + 220W. 40M = 60W, so 2M = 3W. Total work = 20(6M + 8(2/3)M) = 20(6M + 16/3 M) = 20(34/3 M) = 680/3 M. Time for 34 women = (680/3 M) / (34 * 2/3 M) = 680 / 68 = 10 days.

Multiple choice
  1. Rs. 65

  2. Rs. 85

  3. Rs. 80

  4. Rs. 60

  5. None of these

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the number of workers be 3x, 2x, x for women, men, children. Given 3x = 90, so x = 30. Total workers: 90 women, 60 men, 30 children. Let wages be 5y, 3y, 2y. Total wage = 90(5y) + 60(3y) + 30(2y) = 450y + 180y + 60y = 690y. 690y = 11730, so y = 17. A woman's daily wage is 5y = 5 * 17 = 85.

Multiple choice
  1. X

  2. Y

  3. Z

  4. Cannot be determined

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let X, Y, Z be their rates. X+Y = 1/9, Y+Z = 1/12, X+Z = 1/18. Adding these: 2(X+Y+Z) = 1/9 + 1/12 + 1/18 = (4+3+2)/36 = 9/36 = 1/4. So X+Y+Z = 1/8. Then Z = 1/8 - 1/9 = 1/72; X = 1/8 - 1/12 = 1/24; Y = 1/8 - 1/18 = 5/72. Comparing 1/24, 5/72, 1/72, Y is the largest.