If 9 people together can complete a piece of work in 5 days, working 8 hours a day, then how many people can complete the same work in 3 days, working 6 hours a day?

Using the formula M1 times D1 times H1 equals M2 times D2 times H2, the total work is 9 people times 5 days times 8 hours, which equals 360 man-hours. For the second scenario, the total required hours are M2 times 3 days times 6 hours. Setting them equal gives 18 times M2 equals 360. Solving this gives M2 equals 20, so 20 people are required.

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