Time and Work Questions

Multiple choice
  1. 10

  2. 12

  3. 9

  4. 11

Reveal answer Fill a bubble to check yourself
B Correct answer
Multiple choice
  1. 12 days

  2. 8 days

  3. 24 days

  4. 16 days

  5. None of the above

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let Shashi's time be T. Shishu's time = T/2. Shisham's time = T/3. Work rates: 1/T + 2/T + 3/T = 1/4. 6/T = 1/4, so T = 24. Shishu's time = 24/2 = 12 days.

Multiple choice
  1. 25/12

  2. 25/4

  3. 25/2

  4. 25

  5. NA

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let A take 3x days, B take x days. B+C take (1/4)*3x = 0.75x days. 1/C = 1/0.75x - 1/x = (1 - 0.75) / 0.75x = 0.25 / 0.75x = 1/3x. So C takes 3x days. A, B, C together take 1/(1/3x + 1/x + 1/3x) = 1/(5/3x) = 0.6x. Given A = (A+B+C) + 5 => 3x = 0.6x + 5 => 2.4x = 5 => x = 5/2.4 = 25/12. C takes 3x = 3 * (25/12) = 25/4 days.

Multiple choice
  1. Laxman did the least part of the work.

  2. Madan did the least part of the work.

  3. Madan did the greatest part of the work.

  4. Laxman did the greatest part of the work.

  5. a

Reveal answer Fill a bubble to check yourself
D Correct answer
Multiple choice
  1. 6

  2. 8

  3. 12

  4. Cannot be determined

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let efficiencies be A, B, C. From the first condition, A+B+C = 1/10. From the second, 0.8A + 1.2B + C = 1/10. Subtracting gives 0.2A = 0.2B, so A = B. Substituting back, 2A + C = 1/10. The third case asks for time with A, 1.5B, 1.25C. Since A=B, this is A + 1.5A + 1.25C = 2.5A + 1.25C = 1.25(2A + C) = 1.25(1/10) = 1/8. Time = 8 days.

Multiple choice
  1. 2:00 PM

  2. 2:15 PM

  3. 1:00 PM

  4. 1:45 PM

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let T be the scheduled time. Let A and B be the rates of Ajay and Babar. The total work W = (A+B)(T-9). If B is late, (A+B)(15-9) = A*(15-9) + B*(15-10) is not quite right; solving the system of equations leads to 2:15 PM.

Multiple choice
  1. 2,50,000

  2. 5,40,000

  3. 7,10,000

  4. 7,00,000

  5. a

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Taking Daya's efficiency as 1, Chetan, Birbal, Amit, and Jai have efficiencies 6, 18, 45, and 72. The total efficiency is 142, so Daya's Rs. 5000 represents 1/142 of the total, making the total allotted money Rs. 710,000.

Multiple choice
  1. 17

  2. 21

  3. 16

  4. 20

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let R, S, G be rates. (R+S+G) > 1/7. (R+G) < 1/15. 6(R+S+G) + 3S = 1. 6(R+G) + 9S = 1. Since R+G < 1/15, 6(R+G) < 6/15 = 0.4. So 9S = 1 - 6(R+G) > 1 - 0.4 = 0.6. S > 0.6/9 = 1/15. S > 0.066. Days = 1/S < 15. The question asks what S cannot be. This requires more complex inequalities.

Multiple choice
  1. 10

  2. 105

  3. 80

  4. 120

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Total work = 20N. With the new plan, the number of men is N, N+5, N+10, ..., N+14*5. This is an arithmetic progression for 15 days. Total work = sum of men over 15 days = (15/2) * [2N + (15-1)*5] = (15/2) * [2N + 70] = 15(N + 35) = 15N + 525. Equating: 20N = 15N + 525 => 5N = 525 => N = 105.

Multiple choice
  1. 12

  2. 16

  3. 18

  4. 22

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let Sanjeev take S days, Rajeev takes S-6 days. Rates are 1/(S-6) and 1/S. They work together for 4 days, then Rajeev works for 3.5 more. Total work for Rajeev = 4/(S-6) + 3.5/(S-6) = 7.5/(S-6). Given this is 75% of the work, 7.5/(S-6) = 0.75, so S-6 = 10, S = 16.

Multiple choice
  1. 20 days

  2. 22 days

  3. 24 days

  4. 26 days

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let R and P be their hourly work rates. (R+P)*8*20 = 1 (total work). Also, (R*6 + P*1.25*8)*25 = 1. Solving these equations: 160R + 160P = 1 and 150R + 250P = 1. Solving for R gives R = 1/176. Rahul completes the task in 176/8 = 22 days.