Quantitative Aptitude
Profit, Loss and Discount
2,604 Questions
Profit, Loss and Discount Questions
-
36%
-
28%
-
44%
-
48%
-
None of these
C
Correct answer
Explanation
Ranjeet mixes 4 liters of water in 20 liters of milk, creating a 24-liter mixture. He sells the entire mixture at 20% above the cost price of milk. Cost price = 20 × milk cost per liter. Selling price = 24 × 1.2 × milk cost per liter = 28.8 × milk cost per liter. Profit = 28.8 - 20 = 8.8 × milk cost per liter. Profit percentage = (8.8/20) × 100 = 44%. Option C (44%) is correct. Options A (36%), B (28%), and D (48%) are incorrect calculations.
C
Correct answer
Explanation
Let CP = 100. Marked price = 120. After 30% discount: SP = 120 × 0.70 = 84. Since CP = 100, this is a loss of 16%. Loss = 100 - 84 = 16. Always assume CP = 100 for percentage profit/loss problems.
C
Correct answer
Explanation
Given CP:SP = p:q and q = 200% of p = 2p. So CP:SP = p:2p = 1:2, meaning SP = 2 × CP. Profit = SP - CP = 2CP - CP = CP. Profit percent on CP = (Profit/CP) × 100 = (CP/CP) × 100 = 100%. This is straightforward ratio and percentage problem. The key is understanding that 200% means 'twice' not '200% more'. The profit equals the cost price itself, giving 100% profit.
D
Correct answer
Explanation
Let CP = x rupees. Given profit% = x (numerically equal to CP). Profit% = (Profit/CP) × 100 = (SP - x)/x × 100 = x. So (39 - x)/x × 100 = x. Solving: (39 - x) × 100 = x^2, so x^2 + 100x - 3900 = 0. Using quadratic formula: x = [-100 + √(10000 + 15600)]/2 = [-100 + √25600]/2 = [-100 + 160]/2 = 30. (Negative root rejected as CP > 0). Verification: CP=30, SP=39, Profit=9, Profit% = (9/30)×100 = 30%, which equals CP numerically.
-
Rs./रु.800
-
Rs./रु.1400
-
Rs./रु.1600
-
Rs./रु.1800
C
Correct answer
Explanation
Successive discounts: net discount = 30 + 15 - (30×15)/100 = 45 - 4.5 = 40.5%. Customer pays 59.5% of marked price. So 0.595 × MP = 952, giving MP = 952/0.595 = 1600. Option C is correct.
-
Rs./रु.1400
-
Rs./रु.1750
-
Rs./रु.2000
-
Rs./रु.3000
C
Correct answer
Explanation
Let CP = x. SP = 1.3x (30% profit). New CP = 0.78x (22% less). New SP = 1.3x - 884. New profit = 10%, so (1.3x - 884)/0.78x = 1.1 → 1.3x - 884 = 0.858x → 0.442x = 884 → x = 884/0.442 = 2000. Option A (1400) and B (1750) are incorrect.
-
Rs./रु.1000
-
Rs./रु.5000
-
Rs./रु.4000
-
Rs./रु.3000
D
Correct answer
Explanation
Let CP1 = x and CP2 = y. Profit on first item = 10% of x = 0.10x. Profit on second item = 15% of y = 0.15y. Since profits are equal: 0.10x = 0.15y. Also, SP of second item = y + 0.15y = 1.15y = 2300, so y = 2000. Therefore profit = 0.15 × 2000 = 300. Solving: 0.10x = 300, x = 3000. Hence CP of first item is Rs. 3000.
-
60%
-
40%
-
75%
-
80%
-
None of these
D
Correct answer
Explanation
Assuming CP = 100 units. While purchasing, trader gets 120 units for 100 (cheats 20%), so effective CP per unit = 100/120 = 5/6. He marks up by 80%, so MP = 100 × 1.8 = 180. After 25% discount, SP = 180 × 0.75 = 135. While selling, he gives only 90 units but charges for 100 (cheats 10%), so effective SP per unit = 135/0.9 = 150. Profit = 150 - (100/120) × 100 = 150 - 83.33 = 66.67 on CP 83.33, which is 80%.
-
Rs. 55
-
Rs. 60
-
Rs. 45
-
Rs. 50
B
Correct answer
Explanation
Let CP of one article = x. Total CP = 19x, Total SP = 840. Loss = CP - SP = 19x - 840 = 5x. So 19x - 840 = 5x, giving 14x = 840, x = 60. CP of each article is Rs. 60.
C
Correct answer
Explanation
Let CP = 100. A 12% loss means SP = 88. Since a 20% discount is given on MP, we have SP = 0.8 × MP. So 0.8 × MP = 88, which gives MP = 110. Therefore, MP is 10% above CP. Alternatively, if selling at 12% loss after 20% discount, then MP/CP = (100 - 12)/(100 - 20) = 88/80 = 1.10, so MP is 10% above CP.
C
Correct answer
Explanation
If the selling price of certain oranges equals the cost price of 125% of that same number, then SP = 125% of CP for equal quantities. This means SP/CP = 125/100 = 5/4. Profit percent = (SP - CP)/CP × 100 = (5-4)/4 × 100 = 25%.
-
Rs./रु.500
-
Rs./रु.575
-
Rs./रु.600
-
Rs./रु.625
C
Correct answer
Explanation
Difference in profit = 6% - 4% = 2% of CP. This equals Rs. 12. So 0.02 × CP = 12, CP = 12/0.02 = 600. Option C is correct. Verify: 4% of 600 = 24, 6% of 600 = 36, difference = 12 ✓
-
Rs./रु.115
-
Rs./रु.120
-
Rs./रु.138
-
Rs./रु.215
C
Correct answer
Explanation
Let CP = x. SP = 1.12x. New CP = 0.9x, new SP = 1.12x + 5.75. New profit = 30%, so 1.12x + 5.75 = 1.3(0.9x) = 1.17x. Thus 5.75 = 0.05x, x = 115. For 20% profit: SP = 1.2(115) = 138.
D
Correct answer
Explanation
First batch: 12 articles for Rs.20, so CP = 20/12 = Rs.5/3 per article. Second batch: 15 articles for Rs.12, so CP = 12/15 = Rs.4/5 per article. Average CP = (5/3 + 4/5)/2 = (25/15 + 12/15)/2 = (37/15)/2 = Rs.37/30 ≈ Rs.1.233 per article. SP = Rs.1.60 per article. Profit = 1.60 - 1.233 = Rs.0.367 per article. Profit % = (0.367/1.233) × 100 ≈ 29.7%. The options are 39%, 14%, 22%, 30%, 42%. 30% is closest to 29.7%, so option D is correct.
-
Rs. / रू.3600
-
Rs./ रू. 3625
-
Rs./ रू.3650
-
Rs. / रू.4000
B
Correct answer
Explanation
Original scenario: Selling price = Rs. 3000, profit = 25%. Cost price = 3000/(1 + 0.25) = 3000/1.25 = Rs. 2400. New cost price = 2400 + 500 = Rs. 2900. To maintain 25% profit: New selling price = 2900 × 1.25 = Rs. 3625.