Quantitative Aptitude
Profit, Loss and Discount
2,604 Questions
Profit, Loss and Discount Questions
-
Rs. 1950
-
Rs. 2430
-
Rs. 2000
-
Rs. 2250
C
Correct answer
Explanation
Let CP = x. Marked price = 1.4x. Selling price after 10% discount = 1.4x × 0.9 = 1.26x. Gross profit = 1.26x - x = 0.26x. Tax = 10% of gross profit = 0.026x. Net profit = Gross profit - Tax = 0.26x - 0.026x = 0.234x. Given 0.234x = Rs. 468, so x = Rs. 2000.
-
$125%$
-
$60%$
-
$240%$
-
$250%$
D
Correct answer
Explanation
Given CP = 40% of SP, or CP = 0.4 × SP. We need SP as a percentage of CP: SP/CP = SP/(0.4×SP) = 1/0.4 = 2.5 = 250%. So SP is 250% of CP, which matches option D.
-
Rs. 250
-
Rs. 260
-
Rs. 270
-
Rs. 280
-
None of these
A
Correct answer
Explanation
Working backwards: Retailer paid Rs. 273 at 5% profit over wholesaler's price. Wholesaler's selling price = 273/1.05 = Rs. 260. Wholesaler sold at 5% profit over cost, so wholesaler's cost = 260/1.05 ≈ Rs. 247.62. But manufacturer sold at 4% profit, so manufacturer's cost = 247.62/1.04 ≈ Rs. 238.10. This doesn't match Rs. 250. Let me recalculate: If manufacturer's CP = 250, manufacturer sells at 4% = 250 × 1.04 = 260. Wholesaler sells at 5% = 260 × 1.05 = 273. ✓ So Rs. 250 is correct.
-
Only II & III
-
Only I & II
-
All are necessary
-
Any two out of 3
-
All are insufficient
C
Correct answer
Explanation
Profit per article = Selling Price - Cost Price = 765 - 632 = Rs. 133. Total profit = Rs. 1596. Number of articles = Total Profit / Profit per article = 1596/133 = 12. Statement I gives total profit, Statement II gives cost price, Statement III gives selling price. All three are needed because profit per article requires both SP and CP (from II & III), and then number of articles requires total profit (from I). So all three statements are necessary.
-
14%
-
86%
-
17%
-
46%
-
Can't be determined
B
Correct answer
Explanation
Let SP = 100. Loss 7% means CP = 100/0.93 ≈ 107.53. New SP = 200. Profit = 200 - 107.53 = 92.47. Profit% = (92.47/107.53) × 100 ≈ 86%. Alternatively: original loss 7% on CP, doubling SP gives roughly 86% gain. Options A and C are arithmetic errors.
-
Rs 3000
-
Rs 3312
-
Rs 3240
-
Rs 2960
A
Correct answer
Explanation
Selling price after 10% discount = 3600 × 0.9 = Rs 3240. If profit is 8%, then CP × 1.08 = 3240, so CP = 3240/1.08 = Rs 3000. Option A is correct. Rs 3312 is the selling price (10% discount on marked price Rs 3680), Rs 3240 is the discounted selling price, and Rs 2960 is irrelevant.
-
40% to 45.8%
-
33% to 42.5%
-
30% to 33.1%
-
25% to 30%
A
Correct answer
Explanation
CP = Rs. 500, MP = Rs. 1000. Final SP after successive discounts a%, b%, c%: SP = 1000 × (1 - a/100)(1 - b/100)(1 - c/100). Given a + b + c = 30. To maximize profit, minimize discounts - make one discount 30%, others 0%. SP_min = 1000 × 0.7 = 700, profit = 40%. To minimize profit, distribute discounts equally (10% each): SP = 1000 × 0.9³ = Rs. 729, profit = 45.8%. Range is 40% to 45.8%.
-
60 kg.
-
70 kg.
-
72 kg.
-
75 kg
B
Correct answer
Explanation
Use allegation: 7% profit quantity and 17% profit quantity mix to 10% profit. Ratio is (17-10):(10-7) = 7:3. 7% portion = 7/(7+3) × 100 = 70 kg. Option A would give 11%, C gives 10.4%, D gives 9.25%.
C
Correct answer
Explanation
Let CP = 100. Initial SP = 100 + P (where P is initial profit %). After 60% reduction: New SP = 0.4 × (100 + P). This is at 10% loss, so 0.4(100 + P) = 90. Solving: 40 + 0.4P = 90, so 0.4P = 50, P = 125. Initial profit was 125%.
A
Correct answer
Explanation
CP of 15 articles = SP of 12 articles. Let CP of 1 article = 1, so CP of 15 = 15. SP of 12 = 15, so SP of 1 = 15/12 = 1.25. Profit = SP - CP = 1.25 - 1 = 0.25. Profit% = (0.25/1) × 100 = 25%. Formula: Profit% = ((15/12) - 1) × 100 = 25%. Option B (20%) would be if 15 CP = 12 SP. Option C (18%) and D (15%) are incorrect.
-
35%
-
40%
-
45%
-
30%
-
None of these
B
Correct answer
Explanation
Marked price = 140% of CP (40% above). Selling price after discount = 85% of MP = 0.85×1.4×CP = 1.19×CP. But he gives only 850 gm for 1000 gm price, so effective SP = 1.19×CP×(1000/850) = 1.19×CP×1.176 = 1.4×CP. Profit = 40%.
-
Rs.54
-
Rs. 102
-
Rs.108
-
Rs. 100
C
Correct answer
Explanation
Marked Price = Rs.150. After 10% discount, Selling Price = 150 × 0.90 = Rs.135. This SP includes a 25% profit on Cost Price, so CP = SP/1.25 = 135/1.25 = Rs.108. Alternatively: Profit = 25% of CP = 0.25 × CP, so CP + 0.25 CP = 135, giving 1.25 CP = 135, CP = 108. Key distractor: Rs.100 incorrectly ignores the discount.
-
$Rs 3450$
-
$Rs 4500$
-
$Rs 3018$
-
$Rs 2016$
-
$None of these$
B
Correct answer
Explanation
First TV: SP = Rs 3450, profit = 15%. So CP = 3450 ÷ 1.15 = Rs 3000. Let second TV's CP = y. It sells at 10% loss, so SP = 0.9y. Overall: neither gain nor loss, so total SP = total CP. 3450 + 0.9y = 3000 + y. So 3450 - 3000 = y - 0.9y, giving 450 = 0.1y. Therefore y = Rs 4500.
-
1% profit
-
0.9% profit
-
1.2% loss
-
1% loss
-
None of these
C
Correct answer
Explanation
Let CP = 100. After 10% increase, marked price = 110. After 10% discount on this, SP = 110 × 0.9 = 99. So there's a loss of 1% on CP. The net effect is always a loss when same percentage increase and decrease are applied successively. Loss% = (10×10 ÷ 100)% = 1%.
-
$2.5%$
-
$3.5%$
-
$2%$
-
$4%$
-
$None of these$
A
Correct answer
Explanation
Total CP = 1200 + 1200 = 2400. Loss on first fan = 5% of 1200 = 60. SP of first fan = 1140. Profit on second fan = 10% of 1200 = 120. SP of second fan = 1320. Total SP = 1140 + 1320 = 2460. Total profit = 2460 - 2400 = 60. Profit percentage = (60/2400) × 100 = 2.5%. The net transaction yields a 2.5% profit overall.