Chemistry
Organic Chemistry Fundamentals
237 Questions
Organic chemistry fundamentals cover the structure, properties, and reactions of carbon containing compounds. The questions explore functional groups, isomerism, homologous series, and basic reaction mechanisms. This forms the basis of general chemistry across multiple examination formats.
Functional groupsIsomerism typesHomologous seriesCycloalkanesOrganic monomers
Organic Chemistry Fundamentals Questions
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XeF2 : Linear
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XeF4 : Square planar
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XeOF4 : Trigonal bipyramidal
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XeO3 : Pyramidal
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XeF6 : Octahedral
C
Correct answer
Explanation
XeOF4 has square pyramidal structure.
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Presence of asymmetric carbon atom.
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Spatial orientation of groups of single carbon atom.
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Orientation of H-OH group in C1 and C4.
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Rotation of plane of polarized light.
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Spatial arrangement of groups in asymmetric carbon atoms.
B
Correct answer
Explanation
Difference in spatial orientation of groups on a single asymmetric carbon of a molecule having more than one asymmetric carbon. For example, glucose and galactose are 4 epimers of each other differing with respect to groups on C4.
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Only A
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Only B
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Only C
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A and C
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B and C
A
Correct answer
Explanation
This statement is correct because the molecule as whole is chiral since this molecule and its mirror image are non-superimposable.
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A and B
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A and C
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B and C
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A, B and C
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Only A
D
Correct answer
Explanation
Statements A, B and C are incorrect. 1-Methoxypropane and 2-methoxypropane are positional isomers , an optically active substance must be chiral and Isomers are molecules that have the same molecular formula, but have a different arrangement of the atoms in space.
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Only A
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Only B
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A and C
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A, B and C
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Only C
D
Correct answer
Explanation
This option is correct because dihedral angle between the H-atoms in staggered conformation of ethane is 60˚.
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2-chloro-1, 3-butadiene
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1, 3-butadiene
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2-methyl-1, 3-butadiene
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3-methyl-1, 3-pentadiene
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None of the above
C
Correct answer
Explanation
It is the monomer unit of natural rubber which is also called polyisoprene.
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-OH, -NR2, -CH3
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-NO, -SO3H, -CHO
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-NO2, -CN, -NR2
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-NO, -SO3H, -NR2
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-OH, -NR2, -SO3H
B
Correct answer
Explanation
A monosubstituted benzene, when treated with an electrophile, undergoes electrophilic aromatic substitution reactions. Each reaction yields a disubstituted benzene as the organic product, which can be identified using the descriptors ortho, para and meta products.
Common ortho and para directing groups are:
-OH, -NR2, -CH3, -NR2 etc.
Common meta directing groups are:
-NO, -SO3H, -CHO, -NO2, -CN etc.
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Only 2
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Only 3
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Only 4
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1 and 3
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3 and 4
C
Correct answer
Explanation
Monosubstituted benzene when treated with an electrophile, undergoes electrophilic aromatic substitution reactions. Each reaction yields disubstituted benzene as the product, which can be identified using the descriptors ortho, para and meta as products.
Common ortho and para directing groups are:
-OH, -OCH3, -NR2, -CH3, -NR2 etc.
Common meta directing groups are:
-NO, -SO3H, -COCH3, -CHO, -NO2, -CN, -NR3+ etc.
Hence, only –OCH3 group is ortho and para directing.
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pyramidal
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tetrahedral
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square pyramidal
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linear
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Both 1 and 2
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Both 1 and 4
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Both 2 and 3
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Both 2 and 4
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Both 3 and 4
A
Correct answer
Explanation
CN- : (6+7+1) e-= 14 e-
NO+ : (7+8-1) e-= 14 e-
Both CN- and NO+ have the same number of electrons (isoelectronic species).
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trigonal bipyramidal
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trigonal pyramidal
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pentagonal
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none of the above
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benzene
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methane
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ethane
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None of these
A
Correct answer
Explanation
C6H6 is the molecular formula of benzene.
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SnCl2, SeH2
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SO2, CO2
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H2O, ClO-
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ICl, ClO-
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SCl2, XeF2
A
Correct answer
Explanation
SnCl2 has one lone pair of electrons with V-shaped geometry. SeH2 has two lone pairs of electrons with V-shaped geometry.
SO2 has one lone pair of electrons with V-shaped geometry while CO2 has zero lone pair of electrons with linear shape.
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single
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double
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triple
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carbon-carbon
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carbon-functional group
C
Correct answer
Explanation
Yes, it is correct. Hydrocarbons having at least one triple bond between two carbon atoms are known as alkyne.
B
Correct answer
Explanation
Yes, C2H2 is the odd one out as it does not belong to the homologous series of alkanes. It should have been C2H6.