Mixtures and Alligation Questions

Multiple choice

Each question below contains a statement followed by Quantity I and Quantity II. Find the value of both to find the relationship among them. नीचे दिए गए प्रत्येक प्रश्न में एक कथन के पश्चात मात्रा I और मात्रा II दी गयी है। उनके बीच संबंध ज्ञात करने के लिए दोनों का मान ज्ञात कीजिये। The cost of Type 1 material is Rs. 15 per kg and Type 2 material is Rs.20 per kg. Both Type 1 and Type 2 are mixed in the ratio of 2 : 3. Quantity I: what is the price per kg of the mixed variety of material? Quantity II:What is the price per kg of the mixed variety of material if both Type 1 and Type 2 are mixed in the ratio of 3 : 2? प्रकार 1 सामग्री की लागत 15 रुपये प्रति किलो है और प्रकार 2 सामग्री की लागत 20 रुपये प्रति किलो है। प्रकार 1 और प्रकार 2 को 2: 3 के अनुपात में मिलाया गया। मात्रा I: मिश्रित सामग्री का प्रति किलोग्राम मूल्य क्या है? मात्रा II: मिश्रित विविधता के प्रति किलोग्राम मूल्य क्या है यदि प्रकार 1 और प्रकार 2 दोनों को 3: 2 के अनुपात में मिलाया जाय?

  1. Quantity I > Quantity II मात्रा I > मात्रा II

  2. Quantity I ≥ Quantity II मात्रा I ≥ मात्रा II

  3. Quantity II > Quantity I मात्रा II > मात्रा I

  4. Quantity II ≥ Quantity I मात्रा II ≥ मात्रा I

  5. Quantity I = Quantity II or Relation cannot be established मात्रा I = मात्रा II या संबंध स्थापित नहीं किया जा सकता है

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Quantity I: Ratio 2:3, so weighted average = (2×15 + 3×20)/(2+3) = 90/5 = Rs 18/kg. Quantity II: Ratio 3:2, so weighted average = (3×15 + 2×20)/(3+2) = 85/5 = Rs 17/kg. Since 18 > 17, Quantity I > Quantity II. Option A is correct.

Multiple choice

Each of these questions consists of a question followed by informations in three statements. You have to study the question and the statements and decide that information in which of the statement(s) is/are necessary to answer the question. A milkman sells a homogeneous mixture of water and milk at a rate of Rs.40 per liter. Find the profit percentage of the milkman. Statement I: He bought milk at the rate of Rs.35 per liter. Statement II: He bought water at Rs.10 lower than the rate of milk per liter. Statement III: He sold total 80 litre mixture. नीचे प्रत्येक प्रश्न में, एक प्रश्न और उसके बाद तीन कथनों में जानकारी दी गई है। आप प्रश्नो और कथनों का अध्ययन कीजिए और यह तय कीजिये कि कौनसा/से कथनों में दी गई जानकारी प्रश्न का उत्तर देने के लिए आवश्यक है/हैं। एक दूधवाला पानी और दूध के मिश्रण को 40 रुपये प्रति लीटर की दर से बेचता है। दूधवाले का लाभ प्रतिशत ज्ञात कीजिये। कथन I: उसने दूध 35 रुपये प्रति लीटर की दर से ख़रीदा। कथन II: उसने पानी को दूध से 10 रुपये प्रति लीटर कम दर से खरीदा। कथन III: उसने कुल 80 लीटर मिश्रण बेचा।

  1. I and II I तथा II

  2. II and III II तथा III

  3. Any two कोई भी दो

  4. III and I or II III तथा I या II

  5. None of these इनमे से कोई नहीं

Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

To find profit percentage, we need cost price per liter of mixture and selling price (given as Rs.40/L). Statement I: milk cost = Rs.35/L. Statement II: water cost = Rs.35 - Rs.10 = Rs.25/L. However, none of the statements tell us the ratio of milk to water in the mixture. The milkman's profit depends entirely on this ratio - more water means higher profit. Statement III (total 80L sold) gives quantity but not composition. Even with all three statements, we cannot determine profit percentage without knowing the mixture ratio.

Multiple choice
  1. Quantity I > Quantity II

  2. Quantity I ≤ Quantity II

  3. Quantity I ≥ Quantity II

  4. Quantity I < Quantity II

  5. Quantity I = Quantity II or no relation

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Quantity I: Using dilution formula, final milk = initial milk * (1 - x/24)^3 where x is amount removed each time. 15.36 * (1 - x/24)^3 = 6.48, solving gives (1 - x/24) = 0.75, so x = 6 liters. Quantity II: 36L in 4:5 ratio means 16L milk and 20L water. To get 5:4 ratio, let m be milk added: (16+m)/20 = 5/4, solving gives m = 9 liters. Since 6 < 9, Quantity I < Quantity II is correct.

Multiple choice
  1. Quantity I > Quantity II

  2. Quantity I < Quantity II

  3. Quantity I ≥ Quantity II

  4. Quantity I ≤ Quantity II

  5. Quantity I = Quantity II or no relation

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Quantity I: Cost price of mixture = 30/(1 + 2/3) = Rs 18/kg. Using alligation on Rs 12 and Rs 28 with mean Rs 18 gives ratio 2:1 (a:b = 2:1). When ratio reversed to 1:2, new cost = (1*12 + 2*28)/3 = Rs 68/3 ≈ Rs 22.67. Gain% = (30 - 68/3)/(68/3) * 100 = 33.33%. Quantity II: With ratio 2:3, cost = (2*12 + 3*28)/5 = Rs 108/5 = Rs 21.60. Profit% = (27 - 21.60)/21.60 * 100 = 25%. Since 33.33% > 25%, Quantity I > Quantity II is correct.

Multiple choice
  1. Quantity I > Quantity II

  2. Quantity I < Quantity II

  3. Quantity I ≥ Quantity II

  4. Quantity I ≤ Quantity II

  5. Quantity I = Quantity II or No relation

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let mixture A have a liters with milk:water = 2:3, so milk = 2a/5, water = 3a/5. Let mixture B have b liters with milk:water = 1:3, so milk = b/4, water = 3b/4. When a liters of A is mixed with B: total milk = 2a/5 + b/4, total water = 3a/5 + 3b/4. Ratio (2a/5 + b/4)/(3a/5 + 3b/4) = 41/99. When a liters of B is mixed with A: total milk = 2a/5 + a/4, total water = 3a/5 + 3a/4. Ratio = 7/13. From second equation: (8a+5a)/20 / (12a+15a)/20 = 13a/27a = 13/27 ≠ 7/13. Solving first equation gives relationship. Given b = a + 20. Solving yields a = 40, b = 60. Initial milk in A = 16L, in B = 15L. Quantity I > Quantity II.

Multiple choice
  1. 1.25 kg 1.25 किग्रा

  2. 1 kg 1 किलो

  3. 1.5 kg 1.5 किग्रा

  4. 2 kg 2 किग्रा

  5. none of these इनमें से कोई नहीं

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Each operation removes 20% of honey and replaces with sugar solution, so 80% of honey remains. After 4 operations: Honey remaining = Initial × (0.8)^4 = Initial × 0.4096. Given 512g remains: Initial = 512/0.4096 = 1250g = 1.25 kg.

Multiple choice
  1. 7:2

  2. 31:12

  3. 35:9

  4. 5:2

  5. None of these इनमें से कोई नहीं

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Container 1 (40L, 87.5% full, 3:2 mix): Milk = 35 × 3/5 = 21L, Water = 35 × 2/5 = 14L. Container 2 (30L, 80% full, 5:1 mix): Milk = 24 × 5/6 = 20L, Water = 24 × 1/6 = 4L. Container 3 (20L, 90% full, 7:2 mix): Milk = 18 × 7/9 = 14L, Water = 18 × 2/9 = 4L. Total milk = 21 + 20 + 14 = 55L. Total water = 14 + 4 + 4 = 22L. Ratio = 55:22 = 5:2, matching option D.

Multiple choice
  1. 36.45 liter 36.45 लीटर

  2. 45 liter 45 लीटर

  3. 29 liter 29 लीटर

  4. 32 liter 32 लीटर

  5. None of these इनमें से कोई नहीं

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Initial milk = 50L. After first replacement (remove 5L milk, add 5L water): milk = 50 - 5 = 45L. After second replacement (remove 5L of mixture which is 45/50 = 0.9 or 90% milk): milk removed = 5 * 0.9 = 4.5L, milk remaining = 45 - 4.5 = 40.5L. After third replacement: concentration = 40.5/50 = 0.81 or 81% milk. Milk removed = 5 * 0.81 = 4.05L, milk remaining = 40.5 - 4.05 = 36.45L. Option A is correct.

Multiple choice
  1. 42

  2. 48

  3. 40

  4. 45

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let initial quantities be 4x, 5x, 8x. After adding: (4x+5):(5x+10):(8x+z) = 5:7:9. From first ratio: (4x+5)/(5x+10) = 5/7, giving 28x+35 = 25x+50, so 3x = 15, x = 5. From second ratio: (5x+10)/(8x+z) = 7/9, giving 9(5x+10) = 7(8x+z). Substituting x=5: 225+90 = 280+7z, so 7z = 35, z = 5. Third variety total = 8×5+5 = 45 kg.

Multiple choice
  1. 15 : 13

  2. 46 : 29

  3. 48 : 29

  4. 29 : 44

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Starting with 120L pure milk. After removing some milk and adding 23L water, milk:water = 4:1, so milk = 96L, water = 24L. Then 23L of this mixture (with milk:water = 4:1) is removed, so 18.4L milk and 4.6L water removed. Remaining: 77.6L milk, 19.4L water. Adding 28L water: 77.6L milk, 47.4L water. This ratio is approximately 46:29. Option B is correct.

Multiple choice
  1. $4.0$
  2. $3.5$
  3. $2.5$
  4. $1.85$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Raoult's Law: P_A = x_A * P_A_pure, P_B = x_B * P_B_pure. In vapor phase, y_A = P_A / P_total. y_A = 0.6, x_A = 0.3, x_B = 0.7. P_A = 0.3 * P_A_pure, P_B = 0.7 * P_B_pure. P_total = 0.3*P_A_pure + 0.7*P_B_pure. y_A = (0.3*P_A_pure) / (0.3*P_A_pure + 0.7*P_B_pure) = 0.6. 0.3*P_A_pure = 0.18*P_A_pure + 0.42*P_B_pure. 0.12*P_A_pure = 0.42*P_B_pure. Ratio = P_A_pure / P_B_pure = 0.42 / 0.12 = 3.5.

Multiple choice
  1. $\cfrac{16}{17}$
  2. $\cfrac{7}{11}$
  3. $\cfrac{8}{9}$
  4. $\cfrac{5}{16}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Equal weights means equal moles of CO (MW=28) and CH4 (MW=16). Let mass be w. Moles of CO = w/28, Moles of CH4 = w/16. Total moles = w(1/28 + 1/16) = w(4+7)/112 = 11w/112. Mole fraction of CH4 = (w/16) / (11w/112) = (1/16) * (112/11) = 7/11.

Multiple choice
  1. $0.24$ atm
  2. $0.36$ atm
  3. $0.48$ atm
  4. $0.52$ atm
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Osmotic pressure is a colligative property. When mixing two solutions, the final pressure is (P1V1 + P2V2) / (V1 + V2). (0.3 * 400 + 0.4 * 600) / 1000 = (120 + 240) / 1000 = 360 / 1000 = 0.36 atm.

Multiple choice
  1. $0.2$
  2. $0.8$
  3. $0.1$
  4. $0.9$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

According to Raoult's Law, the vapour pressure of a solution is equal to the mole fraction of the solvent multiplied by the vapour pressure of the pure solvent. Substituting the given values, 24 = X_solvent * 30, which gives a solvent mole fraction of 0.8.