The osmotic pressure of 400 ml urea and 600 ml glucose solutions are respectively 0.3 atm and 0.4 atm. The osmotic pressure of the solution obtained by mixing them will be?

The total moles of solute in the mixed solution are found by adding the products of the osmotic pressure and the volume for each solution, and then dividing by the constant R times T. This gives (0.3 times 0.4 plus 0.4 times 0.6) divided by (R times T), which equals 0.36 divided by (R times T) total moles. The total volume of the new mixture is 400 ml plus 600 ml, which equals 1000 ml or 1 litre. Applying the osmotic pressure formula, pi equals n divided by V times R times T, the new osmotic pressure is (0.36 divided by (R times T) divided by 1) times R times T, yielding 0.36 atm. The result is 0.36 atm.

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