Chemistry
Chemical Bonding and Molecular Structure
1,277 Questions
This section tests your knowledge of chemical bonding, molecular structure, and hybridization. It covers ionic and covalent bonds, octet rule exceptions, and molecular geometry. These chemistry questions are common in various competitive entrance examinations.
Ionic and covalent bondsHybridisation of elementsOctet rule exceptionsMolecular geometryIntermolecular forces
Chemical Bonding and Molecular Structure Questions
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Only 1
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Only 2
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Only 2 and 3
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Only 3 and 4
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Only 4
E
Correct answer
Explanation
This option is correct because chemical inertness, magnetically isotropic nature and high volatility of tetramethylsilane (TMS) makes is reference compound of choice for NMR studies. Because of its insolubility in deuterium oxide, it cannot be used with this solvent.
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B-H
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C-H bond
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N-H bond
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O-H bond
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S-H bond
D
Correct answer
Explanation
The strength of the absorption depends on -
(i) polarity of the bond and (ii) the number of bonds. O-H has highest bond polarity, hence it will show strongest absorption in IR.
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Only 1
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Only 3
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1 and 2
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2 and 3
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All are synthetic estrogens.
D
Correct answer
Explanation
This is the correct answer. Both are synthetic estrogens.
Diethylstilbestrol is a synthetic nonsteroidal estrogen that was first synthesized in 1938.
Fosfestrol is a synthetic estrogen used as an antineoplastic agent.
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Fluorine
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Chlorine
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Bromine
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Iodine
A
Correct answer
Explanation
Fluorine is the most reactive halogen due to its small atomic size, high electronegativity (3.98 on the Pauling scale - the highest of all elements), and low F-F bond dissociation energy. Reactivity decreases down the group: F > Cl > Br > I. This extreme reactivity makes fluorine dangerous to handle and capable of reacting with almost any element, including noble gases under certain conditions.
C
Correct answer
Explanation
A carbon atom has 4 valence electrons and forms 4 covalent bonds to achieve a stable octet configuration. This is called tetravalency and is why carbon can form countless organic compounds.
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Only 1
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Only 2
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Only 3
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1 and 2
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2 and 3
D
Correct answer
Explanation
- B-F bond is larger in BF4- than in BF3 molecule. This is due to the fact that in BF4-, the boron atom is sp3 hybridised while in BF3 the boron atom is sp2 hybridised and bond length decreases with increase in s-character as s-orbital is smaller than the p-orbital.
- Sodium tetraborate decahydrate or borax is not used as an indicator. Borax is used as a buffer because its aqueous solution contains equal amounts of weak acid and its salt.
- Borazine is isoelectronic with benzene and the symmetry point group in borazine is D3h.
Hence, statements 1 and 2 both are false.
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CO, N2, O2, NO+
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CO, N2, O2+, CN-
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CO, F2, NO+, CN-
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CO, N2, NO+, CN-
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CO, N2+, NO+, CN-
D
Correct answer
Explanation
Isoelectronic species have same number of electrons. CO, N2, NO+ and CN- each have 14 electrons.
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non-avalibility of d - orbital
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half filled p - orbitals
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the smallest size among all members
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the lowest electronegativity
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of tetrahedral structure
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of half filled p - orbitals
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there are four unpaired electrons in the valence cell
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of non-avalibility of d - orbitals
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tendency to form chains
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tendency to form multiple bonds
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tendency to give protons
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tendency to get ionized
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high lonisation enthalpies
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low lonisation enthalpies
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lack of effective overlapping
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avalibility of d - orbitals
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pyramidal
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tetrahedral
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square pyramidal
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linear
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Both 1 and 2
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Both 1 and 4
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Both 2 and 3
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Both 2 and 4
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Both 3 and 4
E
Correct answer
Explanation
NH4+ and XeO4 have tetrahedral geometry.
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Both 1 and 2
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Both 1 and 4
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Both 2 and 3
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Both 2 and 4
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Both 3 and 4
A
Correct answer
Explanation
CN- : (6+7+1) e-= 14 e-
NO+ : (7+8-1) e-= 14 e-
Both CN- and NO+ have the same number of electrons (isoelectronic species).