Tag: petrochemicals and polymers

Questions Related to petrochemicals and polymers

Determine the degree of association (polymerization) for the reaction in aqueous solution
$6HCHO\rightleftharpoons C _6H _{12}O _6$
If observed (mean) molar mass of HCHO and $C _6H _{12}O _6$ is $150$.

  1. $0.50$

  2. $0.833$

  3. $0.90$

  4. $0.96$


Correct Option: D
Explanation:
Let us consider the problem.
$\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, 6HCHO \,\,\,\,\,\leftrightarrow {C _6}{H _{12}}{O _6}$
At equation $c\left( {1 - \alpha } \right)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\dfrac{{C\alpha }}{6}$
$\dfrac{{Observed\,moles\,concentration}}{{Initial\,moles\,concentration}} = \dfrac{{{M _\gamma }}}{{{M _0}}}$
$\dfrac{{C\left( {1 - \alpha } \right) + \dfrac{{C\alpha }}{6}}}{C} = \dfrac{{{M _\gamma }}}{{{M _0}}} = \dfrac{{30}}{{150}}$
Hence the answer is $\alpha  = 0.96$

The monomer that undergo radical polymerisation most easily is ?

  1. $CH _2=CH _2$

  2. $C _6H _5CH=CH _2$

  3. $CH _2=C{(Me)} _2$

  4. $CH _3-CH=CH _2$


Correct Option: A

During the vinyl polymerisation, the chain transfer agent is:

  1. $C{Cl} _{4}$

  2. ${C} _{6}{H} _{5}OH$

  3. t-butyl peroxide

  4. diphenylamine


Correct Option: A
Explanation:
In the presence of $C{Cl} _{4}$ or any other chain transfer agents, the monomer polymerizes to give lower average molecular mass polymers.
Hence, the correct option is A.

Which one of the following polymer is step-growth polymer

  1. Polythylene

  2. Nylon-$66$

  3. Buna-$S$ rubber

  4. Orlon


Correct Option: A

Which of the following free radicals is the most stable ?

  1. primary

  2. methyl

  3. secondary

  4. tertiary


Correct Option: D
Explanation:

Electron poor species are stabilized by neighboring atoms that can donate electron density. The most common way to interpret rich neighbors here is the observation that increasing the number of alkyl groups on the carbon bearing the free radical increases its stability. 


Radical stability increases in the order methyl < primary < secondary < tertiary

Hence, option $D$ is correct.

Which of the following polymer is not an addition polymer?

  1. Teflon

  2. BUNA-N

  3. PAN

  4. Propylene


Correct Option: B
Explanation:

BUNA-N is formed by removal of water molecule so it is condensation polymer.

Which of the following are used as free radical chain initiators ?

  1. Benzoyl peroxide

  2. di-tert-butyl peroxide

  3. Carbon tetrachloride

  4. Benzoquinone


Correct Option: A,B
Explanation:

A radical initiator is a species that acts as the reactant of the initiation step of a radical chain reaction but does not participate in any of the propagation steps.
Radical initiators are substances that can produce radical species under mild conditions and promote radical reaction. These substances generally possess weak bonds that have small bond dissociation energy. Radical initiators are utilized in industrial processes such as polymer synthesis. Typical examples are halogen molecules, azo compounds and organic and inorganic peroxides such as Benzoyl peroxide, di- t-Butyl peroxide.

Which of the following polymers can be made by free radical addition polymerisation mechanism?

  1. PE

  2. HDPE

  3. LDPE

  4. Telfon


Correct Option: A,B,C,D
Explanation:

The polymers polyethene (PE), low density polyethene(LDPE), high density polyethene(HDPE) and teflon (polytetrafluoroethylene) can be made by free radical addition polymerisation (also known as chain growth polymerisation) mechanism.  To obtain free radicals, initiators such as benzoyl peroxide, tert-butyl peroxide or acetyl peroxide are used.

Polymerisation of buta - $1,:3$ - diene by free radical mechanism gives___________.

  1. trans - $1,: 4$ - Polybutadiene

  2. cis - $1, :4$ - Polybutadiene

  3. Polyvinyl polyethene

  4. Polyallyl polythene


Correct Option: A,B,C

$\begin{bmatrix}-CH _2-\underset{\underset{\textstyle\;OH}{\displaystyle\mid}}{\;\;\;CH}-CH _2-\underset{\underset{\textstyle\;OH}{\displaystyle\mid}}{\;\;\;CH}-CH _2-\underset{\underset{\textstyle\;OH}{\displaystyle\mid}}{\;\;\;CH}-\end{bmatrix} _n$

Polyvinyl alcohol (as shown above) is a unique polymer having high affinity for water. Which of the following procedures would be most suitable for its preparation?

  1. radical chain polymerisation of $CH _2=CH-CH _2-OH$

  2. radical chain polymerisation of $CH _2=CH-OH$

  3. radical chain polymerisation of $CH _2=CH-CO _2CH _3$, following by base catalysed hydrolysis

  4. radical chain polymerisation of $CH _2=CH-OCOCH _3$, followed by acid catalysed hydrolysis

  5. radical chain polymerisation of $CH _2=CH-OCOCH _3$, followed by base catalysed hydrolysis


Correct Option: B
Explanation:

$\begin{bmatrix}-CH _2-\underset{\underset{\textstyle\;OH}{\displaystyle\mid}}{\;\;\;CH}-CH _2-\underset{\underset{\textstyle\;OH}{\displaystyle\mid}}{\;\;\;CH}-CH _2-\underset{\underset{\textstyle\;OH}{\displaystyle\mid}}{\;\;\;CH}-\end{bmatrix} _n$ 


Polyvinyl alcohol is prepared by radical chain polymerisation of  $CH _2=CH-OCOCH _3$, followed by base catalysed hydrolysis in which acetate group is replaced by hydroxide group.