Quantitative Aptitude

Time, Work, and Projects

198 Questions

Time and work questions test the ability to calculate the time required to complete tasks involving individual or combined worker efficiency. These problems frequently appear in competitive exams to assess logical calculation skills. Topics include pipes, cisterns, group efficiency, and hourly work rates.

Combined work efficiencyMen and days calculationsWorker efficiency ratiosWorking hours per dayLeaving and joining workers

Time, Work, and Projects Questions

Multiple choice general knowledge math & puzzles
  1. 100

  2. 99

  3. 98

  4. 101

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let escalator speed = e steps/sec. Upward: 50/(1+e) = time, so 50 = (1+e)t. Downward: 125 = (5-e)t. Solving gives t = 100/3 seconds and e = 1/2 steps/sec. Steps visible when still = 1 * 100/3 + (1/2)*(100/3) = 100/2 = 100 steps.

Multiple choice general knowledge math & puzzles
  1. 20

  2. 18

  3. 24

  4. 28

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

If A is 60% more efficient than B, then B takes 60% longer than A to complete the same work. A completes in 15 hours, so B takes 15 × 1.6 = 24 hours. Alternatively, efficiency ratio A:B = 160:100 = 8:5, so time ratio (inversely proportional) is 5:8, giving 15 × 8/5 = 24 hours.

Multiple choice general knowledge math & puzzles
  1. 8 hrs

  2. 7 1/2 hrs

  3. 7 hrs

  4. 9 hrs

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Total work = 30 men × 20 days × 9 hours = 5400 man-hours. With 40 men: 40 × 20 × h = 5400, where h is hours per day. Therefore h = 5400 / (40 × 20) = 5400 / 800 = 6.75 hours = 6 hours and 45 minutes = 6 3/4 hours = 7 1/2 hours. Verification: 40 × 20 × 6.75 = 5400 man-hours ✓

Multiple choice general knowledge math & puzzles
  1. 9

  2. 11

  3. 12

  4. 15

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let total work be 360 units (LCM of 45 and 40). A's rate is 8 units/day, B's is 9 units/day. In the last 23 days, B did 23 * 9 = 207 units. The remaining 153 units (360 - 207) were done by A and B together. Their combined rate is 17 units/day. Thus, they worked together for 153 / 17 = 9 days.

Multiple choice general knowledge math & puzzles
  1. 2

  2. 4

  3. 5

  4. 3

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Total work = 5 painters × 13 days = 65 painter-days. After 3 days, work completed = 5 × 3 = 15 painter-days. Remaining work = 65 - 15 = 50 painter-days. With 10 painters (5 original + 5 new), days needed = 50/10 = 5 more days to finish the job.

Multiple choice softskills communication
  1. "Six months? Don't you really mean twelve?"

  2. "We're not busy. Our department could do it less time than that."

  3. "You always say that."

  4. "What characteristics of the project require six months? Sounds like you're busy! What are some of the other projects you're handling?"

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The comment contains two messages: the timeline (six months) and a hidden concern (busy schedule). Option D picks up on both layers - asking about the timeline AND acknowledging the busy workload. The other options respond superficially or defensively to just one part.

Multiple choice softskills communication
  1. 29.75 days

  2. 28.33 days

  3. 30.33 days

  4. 35.25 days

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Work = Men × Days × Hours. Original work: 17 × 24 × 5 = 2040 man-hours. New work needed: 18 × Days × 4 = 2040. Days = 2040 / (18 × 4) = 2040 / 72 = 28.33 days. More men but fewer hours per day results in slightly fewer total days.

Multiple choice technology mainframe
  1. 248 Days

  2. 365 Days

  3. 357912 minutes

  4. Both 1 & 3

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

TIME=MAXTIME allows a job to run for both 248 days and 357912 minutes. 248 days equals 248 × 24 × 60 = 357,120 minutes, which when added to 357,912 minutes gives the maximum time setting. MAXTIME is a system option that sets the maximum time a SAS job can run.

Multiple choice technology mainframe
  1. 248 Days

  2. 250 Days

  3. 252 Days

  4. 258 Days

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Mainframe jobs have a CPU time limit measured in seconds. The maximum continuous execution time is approximately 248 days before the time counter would overflow or hit system limits. This is a system architecture limitation. Option B (250), C (252), and D (258) days are incorrect. This is very specialized mainframe knowledge.

Multiple choice technology mainframe
  1. 288 days

  2. 225 days

  3. 248 days

  4. 268 days

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

In IBM JCL, coding TIME=MAXIMUM assigns the maximum possible CPU execution limit, which is 357,912 minutes, or approximately 248 days. Distractors (such as 225, 268, or 288 days) do not match this specific mainframe system limit.