Quantitative Aptitude
Time and Work
2,195 Questions
Time and Work Questions
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$67\dfrac{49}{53}\ days$
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$67\dfrac{17}{24}\ days$
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$66\dfrac{17}{24}\ days$
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$68\dfrac{17}{24}\ days$
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$20$ days
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$30$ days
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$40$ days
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$50$ days
C
Correct answer
Explanation
Given 1/A + 1/B = 1/10 and 1/B + 1/C = 1/20. Also 4/A + 6/B + 22/C = 1. Substituting 1/A = 1/10 - 1/B, we get 4(1/10 - 1/B) + 6/B + 22/C = 1, which simplifies to 2/B + 22/C = 0.6. Using 1/B = 1/20 - 1/C, we get 2(1/20 - 1/C) + 22/C = 0.6, so 20/C = 0.5, C = 40.
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$4\ days$
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$2\ days$
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$1\ days$
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$6\ days$
C
Correct answer
Explanation
The total work is 5 people x 2 days = 10 person-days. With 10 people working at the same rate, the time required is 10/10 = 1 day.
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$\dfrac{1}{6}$
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$\dfrac{1}{9}$
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$\dfrac{2}{5}$
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$\dfrac{2}{7}$
A
Correct answer
Explanation
A takes 18 days. B takes 9 days. A's daily work = 1/18. B's daily work = 1/9. Together = 1/18 + 2/18 = 3/18 = 1/6.
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$23$ days
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$37$ days
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$37 \dfrac { 1 } { 2 }$ days
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$40$ days
C
Correct answer
Explanation
A does 4/5 in 20 days, so A's rate is (4/5)/20 = 1/25 per day. Remaining work = 1/5. A and B finish 1/5 in 3 days, so their combined rate is (1/5)/3 = 1/15. B's rate = Combined - A = 1/15 - 1/25 = (5-3)/75 = 2/75. B takes 75/2 = 37.5 days.
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$120$ men
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$170$ men
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$180$ men
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$150$ men
D
Correct answer
Explanation
The work formula is (M1*D1)/W1 = (M2*D2)/W2. Initially, 90 men did 2 km in 20 days. Remaining work is 4 km in 15 days. (90*20)/2 = (M2*15)/4. Solving gives M2 = 240. Since 90 men are already there, 150 more are needed.
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Rs. $2475$
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Rs. $2425$
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Rs. $2524$
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Rs. $2452$
B
Correct answer
Explanation
Kamlesh does 75% in 27 days, so his rate is 75/27 = 25/9 percent per day. Together they do 25% in 5 days, so their combined rate is 25/5 = 5 percent per day. Lucifer's rate = 5 - 25/9 = 20/9 percent per day. Time for 100% = 100 / (20/9) = 45 days.
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$22$ days
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$25$ days
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$15$ days
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$29$ days
B
Correct answer
Explanation
Work is constant. 15 * 30 = 18 * x. x = 450 / 18 = 25 days.
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$20$ days
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$30$ days
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$50$ days
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$40$ days
B
Correct answer
Explanation
Let M and W be daily work of a man and woman. (6M + 6W) * 24 = 1; (8M + 12W) * 15 = 1. Solving these: 144M + 144W = 120M + 180W => 24M = 36W => M = 1.5W. Substituting, (6*1.5W + 6W) * 24 = 1 => 15W * 24 = 1 => 360W = 1. So 1 woman does 1/360 work/day. 4M + 6W = 4(1.5W) + 6W = 12W. Time = 1 / (12 * (1/360)) = 360/12 = 30 days.
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$8$ days
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$3$ days
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$4$ days
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$9$ days
B
Correct answer
Explanation
This is an inverse proportion problem. 3 persons * 4 days = 12 man-days of work required. If 4 persons are used, the time taken is 12 man-days / 4 persons = 3 days.
A
Correct answer
Explanation
This is an inverse proportion problem: M1 * D1 = M2 * D2. So, 60 * 28 = M2 * 40. Solving for M2 gives (60 * 28) / 40 = 42.
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$9$ days
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$12$ days
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$6$ days
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$7$ days
A
Correct answer
Explanation
12 men = 18 women, so 1 man = 1.5 women. 4 men + 8 women = 4(1.5) + 8 = 6 + 8 = 14 women. 18 women take 7 days, so 14 women take (18*7)/14 = 9 days.
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$10.0$
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$12.0$
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$15.0$
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$18.0$
A
Correct answer
Explanation
Let the daily work rates of A and B be a and b, respectively. We have the system of equations a + b = 1/5 and 2a + b/2 = 1/4. Solving this system gives a = 1/10, meaning A alone can complete the work in 10 days.
D
Correct answer
Explanation
Work done = 448m in 27 days by 56 men. Rate = 448 / (56 * 27) = 8/27 m per man-day. Remaining work = 1000 - 448 = 552m. Remaining time = 50 - 27 = 23 days. Required men = 552 / (23 * 8/27) = 552 / (184/27) = 552 * 27 / 184 = 3 * 27 = 81 men. Extra men = 81 - 56 = 25.