Quantitative Aptitude
Time and Work
2,195 Questions
Time and Work Questions
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$8$ days
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$5$ days
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$7$ days
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$9$ days
D
Correct answer
Explanation
A's rate = 1/12, B's rate = 1/16. Combined rate = 1/12 + 1/16 = 7/48. In 3 days, they do 3 * (7/48) = 21/48 = 7/16 of the work. Remaining work = 1 - 7/16 = 9/16. B takes (9/16) / (1/16) = 9 days to finish.
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$60$ days
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$15$ days
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$6$ days
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$51$ days
B
Correct answer
Explanation
Let M be the work of a man and C be the work of a child per day. From the problem, 2M + 7C = 1/4 and 4M + 4C = 1/3. Solving this system gives M = 1/15, meaning one man completes the work in 15 days.
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$8$ days
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$12$ days
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$6$ days
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$11$ days
B
Correct answer
Explanation
If 1 man, 2 women, or 3 boys take 22 days, their daily work rates are 1/22, 1/44, and 1/66 of the total work respectively. The combined rate of 1 man, 1 woman, and 1 boy is (1/22 + 1/44 + 1/66) = (6+3+2)/132 = 11/132 = 1/12. Thus, they complete the work in 12 days.
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$70$ days
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$30$ days
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$40$ days
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$50$ days
C
Correct answer
Explanation
A does half the work of B in 1/6 the time. If B takes T time for 1 unit, A takes (1/6)T time for 0.5 units. Thus, A's rate is 0.5 / (T/6) = 3/T. B's rate is 1/T. Combined rate: 3/T + 1/T = 4/T = 1/10. So T = 40.
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$10$ days
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$11$ days
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$15$ days
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$20$ days
C
Correct answer
Explanation
A+B = 1/12, A = 1/20. So B = 1/12 - 1/20 = (5-3)/60 = 2/60 = 1/30. If B works half-time, his rate is 1/60. Combined rate = 1/20 + 1/60 = 4/60 = 1/15. Time taken = 15 days.
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$18$ days
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$30$ days
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$24$ days
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$21$ days
D
Correct answer
Explanation
Let M be the work of a man and B be the work of a boy per day. From the equations 14(2M + 7B) = W and 11(3M + 8B) = W, we find 28M + 98B = 33M + 88B, which simplifies to 5M = 10B or M = 2B. Substituting M = 2B into the first equation, 14(4B + 7B) = 154B = W. For 8M + 6B, we have 8(2B) + 6B = 22B. The time required for 3W is (3 * 154B) / 22B = 21 days.
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$7 \frac{3}{4}$
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$6 \frac{5}{6}$
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$4 \frac{3}{4}$
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$3 \frac{3}{4}$.
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$10$ days
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$12$ days
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$15$ days
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$8$ days
A
Correct answer
Explanation
Let A and B's rates be a and b. 1/a + 1/b = 1/5. If A is 2a and B is b/2, 1/(2a) + 1/(b/2) = 1/4, which is 1/(2a) + 2/b = 1/4. Solving the system: 1/a + 1/b = 1/5 and 1/(2a) + 2/b = 1/4. Multiply first by 2: 2/a + 2/b = 2/5. Subtract second: 1.5/a = 2/5 - 1/4 = 3/20. So 1/a = (3/20) * (2/3) = 1/10. A takes 10 days.
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13$\dfrac{1}{2}$ days
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$13$ days
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12 $\dfrac{1}{2}$days
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$14$ days
C
Correct answer
Explanation
Let M be men's daily work and B be boys' daily work. 10(2M + 3B) = 1, so 2M + 3B = 0.1. 8(3M + 2B) = 1, so 3M + 2B = 0.125. Solving the system: M = 0.0375, B = 0.00833. For 2M + 1B, work per day = 2(0.0375) + 0.00833 = 0.0833. Days = 1 / 0.0833 = 12.5 days.
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$74$ days
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$88$ days
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$54$ days
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$84$ days
D
Correct answer
Explanation
Let total work be 1 unit. Rate of A+B = 1/35. Rate of A = 1/60. Rate of B = 1/35 - 1/60 = (12-7)/420 = 5/420 = 1/84. So B takes 84 days.
C
Correct answer
Explanation
Let M be the work of a man and B be the work of a boy per day. 10(2M + 3B) = 1, so 20M + 30B = 1. 8(3M + 2B) = 1, so 24M + 16B = 1. Solving the system: 80M + 120B = 4 and 180M + 120B = 7.5. Subtracting gives 100M = 3.5, M = 0.035. Then 30B = 1 - 20(0.035) = 0.3, B = 0.01. 2M + 1B = 2(0.035) + 0.01 = 0.08. Time = 1 / 0.08 = 12.5 days.
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$\cfrac{1}{24}$ day
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$\cfrac{7}{24}$ day
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$3\cfrac{3}{7}$ days
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$4$ days
C
Correct answer
Explanation
Combined rate = 1/24 + 1/6 + 1/12 = (1 + 4 + 2) / 24 = 7/24. Time = 24/7 = 3 and 3/7 days.
B
Correct answer
Explanation
Let x be the number of days worked. Then (60-x) is the number of idle days. 20x - 3(60-x) = 280. 20x - 180 + 3x = 280. 23x = 460. x = 20. Idle days = 60 - 20 = 40.
A
Correct answer
Explanation
Let x be the number of men. Total work = 16 * 14 = 224 man-days. Work done in first 5 days = 5x. Remaining work = 224 - 5x. After 7 men leave, x-7 men work for 3 days. Then (x-7)/2 men work for 5 days. Setting up the equation: 5x + 3(x-7) + 5((x-7)/2) = 224. Solving this yields x = 25.
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$22.5$ days
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$22$ days
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$24.5$ days
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$24$ days
A
Correct answer
Explanation
Efficiency ratio A:B = 3:1. Time ratio A:B = 1:3. Let A take x days, B takes 3x days. 3x - x = 60 -> 2x = 60 -> x = 30. A takes 30 days, B takes 90 days. Combined rate = 1/30 + 1/90 = 4/90 = 2/45. Time = 45/2 = 22.5 days.