Time and Work Questions

Multiple choice
  1. 5, 15

  2. 12, 15

  3. 10, 12

  4. 7, 14

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let Mohit's rate = 1/M work per day, Suresh's rate = 1/S work per day. Case 1: 2/M + 9/S = 1. Case 2: 3/M + 6/S = 1. Solve the simultaneous equations. Subtract: (3/M + 6/S) - (2/M + 9/S) = 0 → 1/M - 3/S = 0 → 1/M = 3/S → S = 3M. Substitute in first equation: 2/M + 9/(3M) = 1 → 2/M + 3/M = 1 → 5/M = 1 → M = 5 days, S = 15 days. This is a classic work-rate problem with changing scenarios.

Multiple choice
  1. Rs 2400, Rs 2400 Rs 2400

  2. Rs 4000, Rs 2400 Rs 800

  3. Rs 3600, Rs 2400 Rs 1200

  4. Rs 3000, Rs 3000 Rs 1200

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Payment is divided in proportion to work done. A did 4/8 = 1/2 of work, B did 4/12 = 1/3, and C did 1/6 (2 days at 1/12 per day). Ratio is 3:2:1. Dividing Rs 7200 gives Rs 3600, Rs 2400, Rs 1200.

Multiple choice
  1. 33 days

  2. 31 days

  3. 30 days

  4. 32 days

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

A's rate: 25%/10 days = 2.5% per day. B's rate: 40%/20 days = 2% per day. C's rate: 50%/30 days = 1.67% per day. Work done in first 10 days (A+B+C): 10 × (2.5 + 2 + 1.67) = 10 × 6.17 = 61.7%. Remaining 38.3% done by C alone: 38.3/1.67 ≈ 22.9 days. Total ≈ 32.9 ≈ 33 days. Option A is correct.

Multiple choice
  1. ₹ 2000

  2. ₹ 1680

  3. ₹ 1800

  4. ₹ 1540

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the daily wages be 3x, 4x, and 4x for Z1, Z2, Z3. Total wages = 8(3x) + 10(4x) + 15(4x) = 124x = ₹2480, so x = 20. Z1's share = 24x = ₹480, Z3's share = 60x = ₹1200. Combined share = ₹480 + ₹1200 = ₹1680.

Multiple choice
  1. 39 days

  2. 40 days

  3. 41 days

  4. 42 days

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Using the work formula: boys × days × hours = constant work. 42 × 20 × 8 = 6720 total work units. For 14 boys working 12 hours daily: 14 × d × 12 = 6720, giving d = 6720/168 = 40 days. Fewer boys working longer hours balances out to the same total time.

Multiple choice
  1. 36.5 days

  2. 42.5 days

  3. 37.5 days

  4. 40 days

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let Y's time = y days, so X's time = 1.5y (50% more). Their combined rate: 1/y + 1/(1.5y) = 1/15. Solving gives 2.5/(1.5y) = 1/15, so y = 25 days for Y. Therefore X takes 1.5 × 25 = 37.5 days alone. Always convert 'more time' to a multiplier.

Multiple choice
  1. 42,21,14

  2. 60,30,20

  3. 54,27,18

  4. 48,24,16

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

If A takes twice as much time as B and thrice as much time as C, then B is twice as fast as A, and C is thrice as fast as A. Let A's efficiency = 1 unit/day, then B = 2 units/day, C = 3 units/day. Combined efficiency = 6 units/day. Together they complete in 8 days, so total work = 48 units. A alone: 48/1 = 48 days, B alone: 48/2 = 24 days, C alone: 48/3 = 16 days. The ratio 48:24:16 matches option D.

Multiple choice
  1. 40

  2. 10

  3. 30

  4. 20

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Work rates: 1 man = 39 days (1/39 work per day), 1 woman = 78 days (1/78), 1 boy = 156 days (1/156), 1 girl = 195 days (1/195). Combined rate = 1/39 + 1/78 + 1/156 + 1/195 = 20/780 + 10/780 + 5/780 + 4/780 = 39/780 = 1/20. Therefore, working together they complete the work in 20 days.

Multiple choice
  1. 4 days

  2. 5 days

  3. 6 days

  4. 8 days

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

With efficiency ratio 3:2:4 and C taking 15 days alone, total work equals 60 units. Together they complete 9 units per day (3+2+4), so 3/4 of work (45 units) takes exactly 5 days. Option A (4 days) would only complete 36 units, while options C and D exceed the required time.

Multiple choice
  1. Neither I nor II

  2. Only I

  3. Only II

  4. Both I and II

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

A completes 3/8 work in 36 days, so 1 work in 36 × 8/3 = 96 days. B completes 1/2 work in 27 days, so 1 work in 27 × 2 = 54 days. A takes 96 days, B takes 54 days, so A is less efficient (slower) - Statement I is correct. Together in 1 day: 1/96 + 1/54 = 3/288 + 5.33/288 ≈ 8.33/288. In 36 days: 36 × 8.33/288 ≈ 1.04 work, not 11/15 (0.73). So II is false. Only I is correct.

Multiple choice
  1. 12

  2. 8

  3. 6

  4. 16

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let m and w be work done by one man and one woman per day. Total work = (5m + 8w) × 12 = (3m + 7w) × 15. Solving: 60m + 96w = 45m + 105w, so 15m = 9w, meaning 5m = 3w. Total work = 11w × 12 = 132w. Therefore 11 women need 132w ÷ 11w = 12 days. Option A is correct.

Multiple choice
  1. 60 days

  2. 50 days

  3. 72 days

  4. 84 days

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

8 men or 10 boys can complete work in 174 days. Let 1 man's work = m units/day and 1 boy's work = b units/day. So 8m = 10b, meaning m/b = 5/4. Let m = 5 units/day, then b = 4 units/day. Total work = 8 × 5 × 174 = 3480 units. 12 men and 14 boys do 12(5) + 14(4) = 60 + 56 = 116 units/day. Days needed = 3480/116 = 30 days. Wait - let me recalculate: 8m × 174 = total work. If 8m = 1 work, then 1 work = 8m. So 8m × 174 = 1392m total work. 12m + 14(0.8m) = 12m + 11.2m = 23.2m. Days = 1392m/23.2m = 60 days.

Multiple choice
  1. 23 days

  2. 24 days

  3. 25 days

  4. 26 days

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let Gagan's efficiency be 1 unit. Naman does half the work in 4/5 the time, so Naman's efficiency = (1/2)/(4/5) = 5/8. Combined efficiency = 1 + 5/8 = 13/8. They complete the work in 16 days, so total work = 16 × 13/8 = 26 units. Gagan alone would take 26/1 = 26 days. The key is understanding relative efficiency from the given relationship.