Quantitative Aptitude
Time and Work
2,195 Questions
Time and Work Questions
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5, 15
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12, 15
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10, 12
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7, 14
A
Correct answer
Explanation
Let Mohit's rate = 1/M work per day, Suresh's rate = 1/S work per day. Case 1: 2/M + 9/S = 1. Case 2: 3/M + 6/S = 1. Solve the simultaneous equations. Subtract: (3/M + 6/S) - (2/M + 9/S) = 0 → 1/M - 3/S = 0 → 1/M = 3/S → S = 3M. Substitute in first equation: 2/M + 9/(3M) = 1 → 2/M + 3/M = 1 → 5/M = 1 → M = 5 days, S = 15 days. This is a classic work-rate problem with changing scenarios.
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Rs 2400, Rs 2400 Rs 2400
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Rs 4000, Rs 2400 Rs 800
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Rs 3600, Rs 2400 Rs 1200
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Rs 3000, Rs 3000 Rs 1200
C
Correct answer
Explanation
Payment is divided in proportion to work done. A did 4/8 = 1/2 of work, B did 4/12 = 1/3, and C did 1/6 (2 days at 1/12 per day). Ratio is 3:2:1. Dividing Rs 7200 gives Rs 3600, Rs 2400, Rs 1200.
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33 days
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31 days
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30 days
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32 days
A
Correct answer
Explanation
A's rate: 25%/10 days = 2.5% per day. B's rate: 40%/20 days = 2% per day. C's rate: 50%/30 days = 1.67% per day. Work done in first 10 days (A+B+C): 10 × (2.5 + 2 + 1.67) = 10 × 6.17 = 61.7%. Remaining 38.3% done by C alone: 38.3/1.67 ≈ 22.9 days. Total ≈ 32.9 ≈ 33 days. Option A is correct.
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₹ 2000
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₹ 1680
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₹ 1800
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₹ 1540
B
Correct answer
Explanation
Let the daily wages be 3x, 4x, and 4x for Z1, Z2, Z3. Total wages = 8(3x) + 10(4x) + 15(4x) = 124x = ₹2480, so x = 20. Z1's share = 24x = ₹480, Z3's share = 60x = ₹1200. Combined share = ₹480 + ₹1200 = ₹1680.
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39 days
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40 days
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41 days
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42 days
B
Correct answer
Explanation
Using the work formula: boys × days × hours = constant work. 42 × 20 × 8 = 6720 total work units. For 14 boys working 12 hours daily: 14 × d × 12 = 6720, giving d = 6720/168 = 40 days. Fewer boys working longer hours balances out to the same total time.
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36.5 days
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42.5 days
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37.5 days
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40 days
C
Correct answer
Explanation
Let Y's time = y days, so X's time = 1.5y (50% more). Their combined rate: 1/y + 1/(1.5y) = 1/15. Solving gives 2.5/(1.5y) = 1/15, so y = 25 days for Y. Therefore X takes 1.5 × 25 = 37.5 days alone. Always convert 'more time' to a multiplier.
B
Correct answer
Explanation
This is an inverse variation problem where the product of men and days remains constant (total work = 450 × 20 = 9000 man-days). To complete in 30 days, men needed = 9000/30 = 300. More days means fewer men required.
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42,21,14
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60,30,20
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54,27,18
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48,24,16
D
Correct answer
Explanation
If A takes twice as much time as B and thrice as much time as C, then B is twice as fast as A, and C is thrice as fast as A. Let A's efficiency = 1 unit/day, then B = 2 units/day, C = 3 units/day. Combined efficiency = 6 units/day. Together they complete in 8 days, so total work = 48 units. A alone: 48/1 = 48 days, B alone: 48/2 = 24 days, C alone: 48/3 = 16 days. The ratio 48:24:16 matches option D.
D
Correct answer
Explanation
Work rates: 1 man = 39 days (1/39 work per day), 1 woman = 78 days (1/78), 1 boy = 156 days (1/156), 1 girl = 195 days (1/195). Combined rate = 1/39 + 1/78 + 1/156 + 1/195 = 20/780 + 10/780 + 5/780 + 4/780 = 39/780 = 1/20. Therefore, working together they complete the work in 20 days.
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4 days
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5 days
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6 days
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8 days
B
Correct answer
Explanation
With efficiency ratio 3:2:4 and C taking 15 days alone, total work equals 60 units. Together they complete 9 units per day (3+2+4), so 3/4 of work (45 units) takes exactly 5 days. Option A (4 days) would only complete 36 units, while options C and D exceed the required time.
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Neither I nor II
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Only I
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Only II
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Both I and II
B
Correct answer
Explanation
A completes 3/8 work in 36 days, so 1 work in 36 × 8/3 = 96 days. B completes 1/2 work in 27 days, so 1 work in 27 × 2 = 54 days. A takes 96 days, B takes 54 days, so A is less efficient (slower) - Statement I is correct. Together in 1 day: 1/96 + 1/54 = 3/288 + 5.33/288 ≈ 8.33/288. In 36 days: 36 × 8.33/288 ≈ 1.04 work, not 11/15 (0.73). So II is false. Only I is correct.
A
Correct answer
Explanation
Let m and w be work done by one man and one woman per day. Total work = (5m + 8w) × 12 = (3m + 7w) × 15. Solving: 60m + 96w = 45m + 105w, so 15m = 9w, meaning 5m = 3w. Total work = 11w × 12 = 132w. Therefore 11 women need 132w ÷ 11w = 12 days. Option A is correct.
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60 days
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50 days
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72 days
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84 days
A
Correct answer
Explanation
8 men or 10 boys can complete work in 174 days. Let 1 man's work = m units/day and 1 boy's work = b units/day. So 8m = 10b, meaning m/b = 5/4. Let m = 5 units/day, then b = 4 units/day. Total work = 8 × 5 × 174 = 3480 units. 12 men and 14 boys do 12(5) + 14(4) = 60 + 56 = 116 units/day. Days needed = 3480/116 = 30 days. Wait - let me recalculate: 8m × 174 = total work. If 8m = 1 work, then 1 work = 8m. So 8m × 174 = 1392m total work. 12m + 14(0.8m) = 12m + 11.2m = 23.2m. Days = 1392m/23.2m = 60 days.
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25 days
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100 days
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20 days
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50 days
B
Correct answer
Explanation
Combined work rate of P and Q is 1/20 per day. Q's individual rate is 1/25 per day. Therefore P's rate = 1/20 - 1/25 = (5-4)/100 = 1/100 work per day, meaning P alone takes 100 days.
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23 days
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24 days
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25 days
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26 days
D
Correct answer
Explanation
Let Gagan's efficiency be 1 unit. Naman does half the work in 4/5 the time, so Naman's efficiency = (1/2)/(4/5) = 5/8. Combined efficiency = 1 + 5/8 = 13/8. They complete the work in 16 days, so total work = 16 × 13/8 = 26 units. Gagan alone would take 26/1 = 26 days. The key is understanding relative efficiency from the given relationship.