Quantitative Aptitude
Time and Work
2,195 Questions
Time and Work Questions
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Both statements A and C
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Only statement B
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Either statement A or C
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Both statements A and B
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Any one of them
A
Correct answer
Explanation
A: John = 1/12. B: John + Mary = 1/4. C: Mary + Ben = 1/5. From A and B, Mary = 1/4 - 1/12 = 2/12 = 1/6. From C, Ben = 1/5 - 1/6 = 1/30. Total rate = 1/12 + 1/6 + 1/30 = (5+10+2)/60 = 17/60. Time = 60/17 days. A and C are sufficient.
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15 days
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10 days
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12 days
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14 days
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None of these
B
Correct answer
Explanation
A+B+C in 2 days = 1/2, so in 1 day = 1/4. B+C in 2 days = 3/10, so in 1 day = 3/20. A's rate = 1/4 - 3/20 = 5/20 - 3/20 = 2/20 = 1/10. A takes 10 days to finish the work.
A
Correct answer
Explanation
Let M, W, B be the work done by a man, woman, and boy in one day. Given W=3M and B=0.5M, the group (3M+4W+6B) = (3M + 12M + 3M) = 18M. Total work = 18M * 6 days = 108M. To complete 108M in 4 days, the daily work needed is 27M. Since one woman does 3M, the number of women needed is 27M / 3M = 9.
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50 8 17 days
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60 8 17 days
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55 3 17 days
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57 8 17 days
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72 12 17 days
A
Correct answer
Explanation
Let S be the work of a supervisor and W be the work of a worker per day. From the problem, 8(4S + 6W) = 10(3S + 7W), which simplifies to 32S + 48W = 30S + 70W, or 2S = 22W, meaning S = 11W. Substituting back, the total work is 8(4(11W) + 6W) = 8(50W) = 400W. If 10 workers do the job, they take 400W / 10W = 40 days.
C
Correct answer
Explanation
Ron and Sam do 1/8 of the work per day. In 3 days, they do 3/8 of the work. Remaining work = 5/8. Sam does 5/8 of the work in 15 days, so Sam's rate is (5/8)/15 = 1/24 per day. Ron's rate = (1/8) - (1/24) = 3/24 - 1/24 = 2/24 = 1/12. Ron takes 12 days to finish the work alone.
B
Correct answer
Explanation
Work = 8 * 6 = 48 female-hours. Male work = 4 * 6 = 24 male-hours. Assuming 1 male = 1 female, 48 units / 24 units = 2. The male finishes in 24 hours, so 48/24 = 2 females are needed.
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2 2 5 days
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3 1 5 days
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3 2 5 days
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4 5 days
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None of these
B
Correct answer
Explanation
C takes 28 days, so C's efficiency is 1/28 of the work per day. B's efficiency is twice C's, so 2/28 = 1/14. A's efficiency equals B's, so 1/14. Total work is 1. After 4 days, C and B have done 4 * (1/28 + 1/14) = 4 * (3/28) = 3/7. Remaining work is 4/7. A, B, and C together do 1/14 + 1/14 + 1/28 = 5/28 per day. Time taken = (4/7) / (5/28) = (4/7) * (28/5) = 16/5 = 3.2 days.
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36 days
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12 days
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9 days
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27 days
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None of these
A
Correct answer
Explanation
Let Ravi take x days, Rahul takes 3x days. (1/x + 1/3x) = 1/9. (4/3x) = 1/9. 3x = 36. Rahul takes 36 days.
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12 days
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20 days
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10 days
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4 days
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8 days
B
Correct answer
Explanation
Let Sachin take S days. Piyush takes 5S days. Kadil is 6 times as efficient as Piyush, so Kadil takes (5S)/6 days. Together: 1/S + 1/(5S) + 6/(5S) = 1/2. (5+1+6)/(5S) = 1/2. 12/(5S) = 1/2. 5S = 24, S = 4.8. Piyush = 5 * 4.8 = 24 days. Kadil = 24/6 = 4 days. Difference = 24 - 4 = 20 days.
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52 days
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48 days
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46 days
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40 days
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None of these
B
Correct answer
Explanation
Let total work be 48 units. Piyush + Ankit = 48/16 = 3 units/day. Piyush = 48/24 = 2 units/day. Ankit = 3 - 2 = 1 unit/day. Ankit time = 48/1 = 48 days.
B
Correct answer
Explanation
Total work = 16 * 12 = 192 man-days. Work done in 4 days = 16 * 4 = 64 man-days. Remaining work = 192 - 64 = 128 man-days. Remaining time = 4 days. Men needed = 128 / 4 = 32. Original men = 16. New men joined = 32 - 16 = 16.
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15
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19
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12
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21
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None of these
D
Correct answer
Explanation
Let x be the original number of men. The total work is 15x. With (x-6) men, the work takes 21 days, so 21(x-6) = 15x. Solving this: 21x - 126 = 15x, which gives 6x = 126, so x = 21.