Multiple choice

A female mason works for 8 hr a day for 6 days to finish a certain job. A male mason finishes the same job in 4 days, working 6 hr a day. How many female masons are required to do the job in the same time as taken by the male mason?

  1. 3

  2. 2

  3. 4

  4. 5
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Work = 8 * 6 = 48 female-hours. Male work = 4 * 6 = 24 male-hours. Assuming 1 male = 1 female, 48 units / 24 units = 2. The male finishes in 24 hours, so 48/24 = 2 females are needed.

AI explanation

The total work is 48 hours (8 hours per day for 6 days), which the male mason completes in 24 hours (6 hours per day for 4 days). To finish the 48-hour job in that same 24-hour timeframe, you need 2 female masons working in parallel (48 divided by 24). Thus, 2 female masons are required.

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