Mixtures and Alligation Questions

Multiple choice
  1. 3 atm

  2. 4 atm

  3. 5 atm

  4. 6 atm

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Partial pressure is proportional to the number of moles. Moles: O2 = 8/32 = 0.25, N2 = 7/28 = 0.25, H2 = 1/2 = 0.5. Total moles = 1.0. Total pressure = 8 atm. Pressure per mole = 8 atm. Removing O2 (0.25 moles) leaves 0.75 moles. Remaining pressure = 0.75 * 8 = 6 atm.

Multiple choice
  1. $\dfrac{1}{3}$ of total pressure
  2. $\dfrac{2}{3}$ of total pressure
  3. $\dfrac{3}{2}$ of total pressure
  4. $\dfrac{1}{2}$ of total pressure
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Moles of H2 = 3/2 = 1.5. Moles of O2 = 24/32 = 0.75. Total moles = 2.25. Mole fraction of H2 = 1.5 / 2.25 = 2/3. Partial pressure = mole fraction * total pressure.

Multiple choice
  1. $120$ mL
  2. $140$ mL
  3. $144$ mL
  4. $168$ mL
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Red = 1/4 total. Ratio Red:Blue = 3:2, so Blue = (2/3) * Red = (2/3) * (1/4) = 1/6 total. Yellow = 1 - (1/4 + 1/6) = 1 - 5/12 = 7/12 total. 7/12 * Total = 84, so Total = 144 mL.

Multiple choice
  1. $21.6$ atm
  2. $0.126$ atm
  3. $2.16$ atm
  4. $0.216$ atm
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Osmotic pressure is a colligative property. For a mixture, Pi_final = (Pi1*V1 + Pi2*V2) / (V1 + V2). Pi_final = (1.5*1 + 2.5*2) / (1 + 2) = (1.5 + 5) / 3 = 6.5 / 3 = 2.166 atm.

Multiple choice
  1. 125 mm

  2. 500 mm

  3. 1000 mm

  4. 250 mm

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Since the vessels have equal volumes and are joined, the total volume doubles. By Boyle's Law (P1V1 + P2V2 = PfVf), where V1=V2=V and Vf=2V: 100*V + 400*V = Pf*(2V). Thus, 500 = 2*Pf, so Pf = 250 mm.

Multiple choice
  1. 600 mL

  2. 900 mL

  3. 1200 mL

  4. 1500 mL

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Degree of dissociation alpha = sqrt(Ka/C). If alpha doubles, C must become C/4. Initial C = 0.2 M. Final C = 0.05 M. Initial volume = 300 mL. C1V1 = C2V2 => 0.2 * 300 = 0.05 * V2. V2 = 1200 mL. Water to be added = 1200 - 300 = 900 mL.