Multiple choice

$20 g$ water at$\ 20^o C$ is contained in a calorimeter. 10 g of water at $50^o C$ is mixed into it. Temperature of mixture would be :

  1. $15.2 ^o C$
  2. $30 ^o C$
  3. $35.2 ^o C$
  4. $43.7^o C$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Heat lost = Heat gained. 10g * (50-T) = 20g * (T-20). 500 - 10T = 20T - 400. 30T = 900. T = 30 degrees C.

AI explanation

Using the method of mixtures and weighted averages, the final temperature is calculated as the sum of the products of mass and temperature divided by the total mass. You calculate 20 multiplied by 20 plus 10 multiplied by 50 to get 900. Dividing 900 by the total mass of 30 grams yields a final temperature of 30 degrees Celsius.