Mixtures and Alligation Questions

Multiple choice
  1. 13 : 55

  2. 20 : 74

  3. 16 : 65

  4. 10 : 48

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The formula for the final concentration of the original liquid after n replacements is: Final = Initial * (1 - x/y)^n. Here, 1/3 is replaced, so 2/3 remains. After 4 operations, the ratio of dettol to total volume is (2/3)^4 = 16/81. Thus, dettol is 16 parts and water is 81 - 16 = 65 parts. The ratio is 16:65.

Multiple choice
  1. $\displaystyle \frac{719}{371}$
  2. $\displaystyle \frac{709}{291}$
  3. $\displaystyle \frac{727}{273}$
  4. $\displaystyle \frac{729}{271}$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Initial paint = 20. After 3 replacements of 2L: Final paint = 20 * (1 - 2/20)^3 = 20 * (0.9)^3 = 20 * 0.729 = 14.58. Oil = 20 - 14.58 = 5.42. Ratio Paint/Oil = 14.58 / 5.42 = 1458 / 542 = 729 / 271.

Multiple choice
  1. 25

  2. 30

  3. 45

  4. Cannot be determined

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let initial petrol be 3x and kerosene be 2x. Total = 5x. Removing 10L removes 6L petrol and 4L kerosene. Remaining: (3x-6) petrol and (2x-4+10) kerosene. Ratio (3x-6)/(2x+6) = 2/3. 9x - 18 = 4x + 12, so 5x = 30.

Multiple choice
  1. $43:96$
  2. $438:962$
  3. $348:962$
  4. $481:219$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Vessel volumes are 2x, 3x, 5x. Milk/Water ratios: V1 (1:3) -> 0.5 milk, 1.5 water; V2 (2:3) -> 1.2 milk, 1.8 water; V3 (2:5) -> 1.428 milk, 3.571 water. Summing these and simplifying gives the ratio 481:219.