Mixtures and Alligation Questions

Multiple choice
  1. $1$:$10$
  2. $1:12$
  3. $1$:$15$
  4. $1:20$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

At a 37.5% profit, the cost of one litre of mixture is 8/1.375 = 64/11 rupees. This requires 10/11 litre of milk costing 6.40 per litre, leaving 1/11 litre of water, so the water-to-milk ratio is 1:10.

Multiple choice
  1. $9.50$
  2. $10.80$
  3. $11.75$
  4. $11$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Selling price = 11, profit 10%, so Cost Price = 11 / 1.1 = 10. Ratio 3:2. Let X = y+2. 3(y+2) + 2y = 5 * 10. 3y + 6 + 2y = 50 => 5y = 44 => y = 8.8. X = 8.8 + 2 = 10.8.

Multiple choice
  1. $22\dfrac{1}{8}$%
  2. $25.75$ %
  3. $25.25$ %
  4. $25\dfrac{1}{8}$%
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The mixture consists of 5 parts of 22.5% and 7 parts of 27%. The weighted average is ((5 * 22.5) + (7 * 27)) / 12 = (112.5 + 189) / 12 = 301.5 / 12 = 25.125%. 25.125% is 25 1/8%.

Multiple choice
  1. Rs. $16.00$ gain
  2. Rs. $16.00$ Loss
  3. Rs. $20.00$ gain
  4. Rs. $10$ gain
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Total cost = (25 * 6) + (35 * 7) = 150 + 245 = 395. Total weight = 25 + 35 = 60 kg. Selling price = 60 * 6.75 = 405. Gain = 405 - 395 = 10.

Multiple choice
  1. $14 : 9$
  2. $9 : 14$
  3. $16 : 9$
  4. $3 : 4$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let the ratio of chemical to water be x:y. The cost price of the mixture is 25x / (x+y). Selling at 20 with 25% profit means the cost price is 20 / 1.25 = 16. Setting 25x / (x+y) = 16 gives 25x = 16x + 16y, so 9x = 16y, or x/y = 16/9.

Multiple choice
  1. Rs.360

  2. Rs.270

  3. Rs.180

  4. None of these

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Total cost = (60 * 5) + (150 * 6) = 300 + 900 = 1200. Total weight = 60 + 150 = 210 kg. Selling price = 210 * 7 = 1470. Gain = 1470 - 1200 = 270.

Multiple choice
  1. $20$ mLof solution $A$ and $80$ mL of solution $B$ were used.
  2. $80$ mLof solution $A$ and $70$ mL of solution $B$ were used.
  3. $30$ mL of solution $A$ and $60$ mL of solution $B$ were used.
  4. $40$ mLof solution $A$ and $70$ mL of solution $B$ were used.
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let the amounts of 20% and 50% acid solutions be a and b millilitres. Since a + b = 90 and 0.20a + 0.50b = 0.40 x 90, solving gives a = 30 and b = 60.

Multiple choice
  1. $20$ kg
  2. $18$ kg
  3. $33$ kg
  4. $45$ kg
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let x be the quantity of the second rice. Total cost = 10*10 + 15*x = 100 + 15x. Total weight = 10 + x. Selling price = 14(10 + x). Gain is 5%, so 1.05 * (100 + 15x) = 14(10 + x). Solving for x gives 105 + 15.75x = 140 + 14x, so 1.75x = 35, x = 20.

Multiple choice
  1. $\displaystyle \frac{ne}{100+e}$
  2. $\displaystyle \frac{100-e}{ne}$
  3. $\displaystyle \frac{ne}{100-e}$
  4. $\displaystyle \frac{100+e}{ne}$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

If the tank is e% empty, it is (100-e)% full. The current volume n represents (100-e)/100 of the total capacity T, so T = 100n / (100-e). The amount needed to fill the remaining e% is (e/100) * T, which simplifies to (e/100) * (100n / (100-e)) = ne / (100-e).