Multiple choice

The liquids $X$ and $Y$ are mixed in the ratio of $3:2$ and the mixture is sold at $Rs\;11$ per liter at a profit of $10\%$. If the liquid $X$ costs $Rs\;2$ more per liter than $Y$, the cost of $X$ per liter is (in Rs.):

  1. $9.50$
  2. $10.80$
  3. $11.75$
  4. $11$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Selling price = 11, profit 10%, so Cost Price = 11 / 1.1 = 10. Ratio 3:2. Let X = y+2. 3(y+2) + 2y = 5 * 10. 3y + 6 + 2y = 50 => 5y = 44 => y = 8.8. X = 8.8 + 2 = 10.8.

AI explanation

The selling price of the mixture is Rs 11 at a 10% profit, so the cost price of the mixture is 11 divided by 1.1, equalling Rs 10 per liter. Let the cost of liquid Y be y, making the cost of liquid X equal to y plus 2; because they are mixed in a 3:2 ratio, the equation becomes (3 times (y + 2) plus 2 times y) divided by 5 equals 10. Solving 5y plus 6 equals 50 gives y as 8.8, meaning the cost of liquid X is 8.8 plus 2, which is Rs 10.80.

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