A container contained $80$ litre of milk. From this container $8$ litre of milk was taken out and replaced by water. This process was further repeated three times. How much of milk is now contained by the container?

Using the formula for repeated replacement, the final amount of milk is calculated as Initial Amount times (1 minus Replacement Volume divided by Total Volume) raised to the power of the number of operations. The process was performed one time and then repeated three times, making the total number of operations four. Substituting the given values gives 80 times (1 minus 8 divided by 80) to the fourth power, which equals 80 times 0.9 to the fourth power. Calculating 0.9 to the fourth power gives 0.6561, and multiplying by 80 results in 52.488 litres of milk remaining in the container.

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