Mixtures and Alligation Questions

Multiple choice
  1. $\dfrac {3}{2}$
  2. $\dfrac {5}{2}$
  3. $\dfrac {7}{2}$
  4. $\dfrac {9}{2}$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Mixture 1: 1 gallon (5/6 fuel, 1/6 antifreeze). Mixture 2: 0.5 gallon (2/3 fuel, 1/3 antifreeze) = 1/3 gallon fuel, 1/6 gallon antifreeze. Total fuel = 5/6 + 1/3 = 7/6. Total antifreeze = 1/6 + 1/6 = 2/6. Ratio = (7/6) / (2/6) = 7/2.

Multiple choice
  1. $75^{o}C$
  2. $100^{o}C$
  3. $50^{o}C$
  4. $125^{o}C$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Using the principle of calorimetry (heat lost = heat gained): m1*c1*(T1 - T) = m2*c2*(T - T2). Given m1/m2 = 2/3 and c1/c2 = 3/4, the equation becomes (2/3)(3/4)(75 - T) = (T - 150) is incorrect; rather, (m1*c1)/(m2*c2) = (2*3)/(3*4) = 1/2. So 1*(75 - T) = 2*(T - 150) -> 75 - T = 2T - 300 -> 3T = 375 -> T = 125.

Multiple choice
  1. ${ \rho }_{ 1 }=6$ and ${ \rho }_{ 2 }=2$
  2. ${ \rho }_{ 1 }=3$ and ${ \rho }_{ 2 }=5$
  3. ${ \rho }_{ 1 }=12$ and ${ \rho }_{ 2 }=4$
  4. None of these

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Equal volume: (rho1 + rho2)/2 = 4, so rho1 + rho2 = 8. Equal mass: 2/(1/rho1 + 1/rho2) = 3, so 2*rho1*rho2 / (rho1 + rho2) = 3. 2*rho1*rho2 / 8 = 3, so rho1*rho2 = 12. Solving x^2 - 8x + 12 = 0 gives x = 6 and 2.

Multiple choice
  1. $2.5$
  2. $5.0$
  3. $7.5$
  4. $10$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The volume strength of H2O2 is proportional to its concentration. Mixing equal volumes of 10, 15, and 20 volume solutions results in an average concentration of (10+15+20)/3 = 15 volume. Diluting this with an equal volume of water halves the concentration, resulting in 15/2 = 7.5 volume.

Multiple choice
  1. Liquid phase 52.44%, 47.56% vapour phase 78%, 22%

  2. Liquid phase 78%, 22% vapour phase 52.44%, 47.56%

  3. Liquid phase 60.45%, 39.50% vapour phase 82%, 18%

  4. Liquid phase 82%, 18% vapour phase 60.45%, 39.50%

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Using Raoult's Law: P_total = P_A*x_A + P_B*x_B. 80 = 119*x + 37*(1-x). 80 = 119x + 37 - 37x. 43 = 82x, so x = 43/82 = 0.5244 (52.44%). Then x_B = 47.56%. Vapour phase: y_A = P_A*x_A / P_total = 119*0.5244 / 80 = 0.78 (78%).

Multiple choice
  1. $1.9\times 10^{-5}/^{0}C$
  2. $1.9\times 10^{-6}/^{0}C$
  3. $1.6\times 10^{-5}/^{0}C$
  4. $1.6\times 10^{-6}/^{0}C$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

For the volume to remain constant, the expansion of the liquids must equal the expansion of the container. (V1 * alpha1 + V2 * alpha2) * deltaT = V_total * alpha_container * deltaT. (200 * 1.4e-5 + 500 * 2.1e-5) = 700 * alpha_container. (2.8e-3 + 10.5e-3) / 700 = alpha_container. 13.3e-3 / 700 = 0.019e-3 = 1.9e-5.

Multiple choice
  1. $60$%
  2. $70$%
  3. $45$%
  4. $56$%
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

1.68g of CaO corresponds to 1.68 / 56 = 0.03 moles of Ca. This Ca came from CaCl2. Moles of CaCl2 = 0.03. Mass of CaCl2 = 0.03 * 111 = 3.33g. Percentage = (3.33 / 5.55) * 100 = 60%.

Multiple choice
  1. $0.169, 118\%$
  2. $0.169, 108\%$
  3. $0.184, 118\%$
  4. $0.184, 108\%$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

10g H2SO4 (MW 98) is 0.102 mol. 40g SO3 (MW 80) is 0.5 mol. Total moles = 0.602. Mole fraction = 0.102 / 0.602 = 0.169. For oleum labelling, total SO3 is 40g + (10g H2SO4 * 80/98) = 48.16g. Total mass = 50g. % labelling = 100 + (48.16/50 * 18/80 * 100) = 118%.

Multiple choice
  1. $2\mathrm{p}_{1}$
  2. $2\mathrm{p}_{2}$
  3. $3\mathrm{p}_{1}$
  4. $3\mathrm{p}_{2}$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Air follows Boyle's Law (P1V1 = P2V2). If volume becomes 1/4, pressure of air becomes 4 * p2. The saturated vapor pressure p1 remains constant because it is saturated. The total pressure changes from (p1 + p2) to (p1 + 4 * p2). The increase is (p1 + 4 * p2) - (p1 + p2) = 3 * p2.

Multiple choice
  1. $2$ times
  2. $4$ times
  3. $0.5$ times
  4. $0.25$ times
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The rate of esterification is proportional to the product of the concentrations of the carboxylic acid and the alcohol, Rate = k[CH3COOH][CH3OH]. Diluting each solution with an equal volume of water doubles the total volume, thereby halving the concentration of both reactants. Consequently, the new rate is (1/2) * (1/2) = 1/4 = 0.25 times the initial rate.